testbookLayout.git

			@@ -1,5 +1,5 @@
			<template>
			<div class="chapter" num="2">
			<div class="chapter" num="3">
			<!-- 第二单元首页 -->
			<div class="page-box" page="38">
			<div v-if="showPageList.indexOf(38) > -1">
			@@ -274,27 +274,70 @@
			<p>
			<span class="zt-ls"><b>例1</b></span>　已知<i>a</i>＞<i>b</i>＞0.
			</p>
			<p>（1）比较2<i>a</i>与2<i>b</i>的大小；</p>
			<p>（2）比较-2<i>a</i>与-2<i>b</i>的大小；</p>
			<p>（3）比较<i>ac</i>与<i>bc</i>的大小.</p>
			<p>
			<p class="p-btn">
			（1）比较2a与2b的大小；
			<span class="btn-box" @click="isShowAnswer0 = !isShowAnswer0">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p v-if="isShowAnswer0">
			<span class="zt-ls"><b>解</b></span>（1）因为<i>a</i>＞<i>b</i>，2＞0，根据性质2，有2<i>a</i>＞2<i>b</i>.
			</p>
			<p>
			<p class="p-btn">
			（2）比较-2a与-2b的大小；
			<span class="btn-box" @click="isShowAnswer1 = !isShowAnswer1">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p v-if="isShowAnswer1">
			<span class="zt-ls"><b>解</b></span>
			（2）
			因为<i>a</i>＞<i>b</i>，-2＜0，根据性质3，有-2<i>a</i>＜-2<i>b</i>.
			</p>
			<p>（3）若<i>c</i>＞0，根据性质2，有<i>ac</i>＞<i>bc</i>.</p>
			<p>若<i>c</i>＜0，根据性质3，有<i>ac</i>＜<i>bc</i>.</p>
			<p>若<i>c</i>=0，则有<i>ac</i>=<i>bc</i>=0，所以<i>ac</i>=<i>bc</i>.</p>
			<p>
			<span class="zt-ls"><b>例2</b></span>　已知<i>a</i>＞<i>b</i>，比较<i>a</i>-1与<i>b</i>-2的大小.
			<p class="p-btn">
			（3）比较ac与bc的大小.
			<span class="btn-box" @click="isShowAnswer2 = !isShowAnswer2">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span> 因为<i>a</i>＞<i>b</i>，-1＞-2，
			<div v-if="isShowAnswer2">
			<p>
			<span class="zt-ls"><b>解</b></span>
			（3）若<i>c</i>＞0，根据性质2，有<i>ac</i>＞<i>bc</i>.
			</p>
			<p>若<i>c</i>＜0，根据性质3，有<i>ac</i>＜<i>bc</i>.</p>
			<p>若<i>c</i>=0，则有<i>ac</i>=<i>bc</i>=0，所以<i>ac</i>=<i>bc</i>.</p>
			</div>
			<p class="p-btn">
			<span class="zt-ls"><b>例2</b></span>
			<span class="t1">已知a＞b，比较a-1与b-2的大小.</span>
			<span class="btn-box" @click="isShowAnswer3 = !isShowAnswer3">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>根据推论1，有<i>a</i>+（-1）＞<i>b</i>+（-2），</p>
			<p>即<i>a</i>-1＞<i>b</i>-2.</p>
			<div v-if="isShowAnswer3">
			<p>
			<span class="zt-ls"><b>解</b></span> 因为<i>a</i>＞<i>b</i>，-1＞-2，
			</p>
			<p>根据推论1，有<i>a</i>+（-1）＞<i>b</i>+（-2），</p>
			<p>即<i>a</i>-1＞<i>b</i>-2.</p>
			</div>
			</div>
			</div>
			</div>
			@@ -332,100 +375,110 @@
			<p>
			因为（<i>a</i><sup>2</sup>+1）-2<i>a</i>=<i>a</i><sup>2</sup>-2<i>a</i>+1=（<i>a</i>-1）<sup>2</sup>，且当<i>a</i>≠1时，（<i>a</i>-1）<sup>2</sup>＞0，所以<i>a</i><sup>2</sup>+1＞2<i>a</i>.
			</p>
			<p>
			<span class="zt-ls"><b>例1</b></span>　分析本节“问题提出”中的问题.
			<p class="p-btn">
			<span class="zt-ls"><b>例1</b></span>
			<span class="t1">分析本节“问题提出”中的问题.</span>
			<span class="btn-box" @click="isShowAnswer4 = !isShowAnswer4">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span> 作差可得<math display="0">
			<mfrac>
			<mn>98</mn>
			<mn>166</mn>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mrow>
			<div v-if="isShowAnswer4">
			<p>
			<span class="zt-ls"><b>解</b></span> 作差可得<math display="0">
			<mfrac>
			<mn>98</mn>
			<mo>+</mo>
			<mn>8</mn>
			</mrow>
			<mrow>
			<mn>166</mn>
			<mo>+</mo>
			<mn>8</mn>
			</mrow>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mn>98</mn>
			<mn>166</mn>
			</mfrac>
			<mo>−</mo>
			<mfrac>
			<mn>106</mn>
			<mn>174</mn>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mrow>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mrow>
			<mn>98</mn>
			<mo>+</mo>
			<mn>8</mn>
			</mrow>
			<mrow>
			<mn>166</mn>
			<mo>+</mo>
			<mn>8</mn>
			</mrow>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mn>98</mn>
			<mo>×</mo>
			<mn>174</mn>
			<mo>−</mo>
			<mn>166</mn>
			</mfrac>
			<mo>−</mo>
			<mfrac>
			<mn>106</mn>
			<mo>×</mo>
			<mn>166</mn>
			</mrow>
			<mrow>
			<mn>166</mn>
			<mo>×</mo>
			<mn>174</mn>
			</mrow>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mrow>
			<mo>−</mo>
			<mn>544</mn>
			</mrow>
			<mrow>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mrow>
			<mn>98</mn>
			<mo>×</mo>
			<mn>174</mn>
			<mo>−</mo>
			<mn>106</mn>
			<mo>×</mo>
			<mn>166</mn>
			</mrow>
			<mrow>
			<mn>166</mn>
			<mo>×</mo>
			<mn>174</mn>
			</mrow>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mrow>
			<mo>−</mo>
			<mn>544</mn>
			</mrow>
			<mrow>
			<mn>166</mn>
			<mo>×</mo>
			<mn>174</mn>
			</mrow>
			</mfrac>
			<mo>＜</mo>
			<mn>0</mn>
			</math>，所以<math display="0">
			<mfrac>
			<mn>98</mn>
			<mn>166</mn>
			<mo>×</mo>
			</mfrac>
			<mo>＜</mo>
			<mfrac>
			<mn>106</mn>
			<mn>174</mn>
			</mrow>
			</mfrac>
			<mo>＜</mo>
			<mn>0</mn>
			</math>，所以<math display="0">
			<mfrac>
			<mn>98</mn>
			<mn>166</mn>
			</mfrac>
			<mo>＜</mo>
			<mfrac>
			<mn>106</mn>
			<mn>174</mn>
			</mfrac>
			</math>.
			</p>
			<p>
			又因为<math display="0">
			<mfrac>
			<mn>98</mn>
			<mn>166</mn>
			</mfrac>
			<mo>≈</mo>
			<mn>0.590</mn>
			<mn>4</mn>
			</math>，<math display="0">
			<mfrac>
			<mn>106</mn>
			<mn>174</mn>
			</mfrac>
			<mo>≈</mo>
			<mn>0.690</mn>
			<mn>2</mn>
			</math>，所以立起脚尖后，该芭蕾舞演员的下半身长与全身长的比值更接近0.618.
			</p>
			</mfrac>
			</math>.
			</p>
			<p>
			又因为<math display="0">
			<mfrac>
			<mn>98</mn>
			<mn>166</mn>
			</mfrac>
			<mo>≈</mo>
			<mn>0.590</mn>
			<mn>4</mn>
			</math>，<math display="0">
			<mfrac>
			<mn>106</mn>
			<mn>174</mn>
			</mfrac>
			<mo>≈</mo>
			<mn>0.690</mn>
			<mn>2</mn>
			</math>，所以立起脚尖后，该芭蕾舞演员的下半身长与全身长的比值更接近0.618.
			</p>
			</div>
			<div class="bk">
			<div class="bj1">
			<p class="left">
			@@ -521,9 +574,10 @@
			</math>.
			</p>
			</div>

			<p>
			<span class="zt-ls"><b>例2</b></span>　已知<i>b</i>＞<i>a</i>＞0，<i>c</i>＞0，比较<math display="0">
			<p class="p-btn">
			<span class="zt-ls"><b>例2</b></span>
			<span calss="t1">已知b＞a＞0，c＞0，比较</span>
			<math display="0">
			<mfrac>
			<mrow>
			<mi>a</mi>
			@@ -542,166 +596,175 @@
			<mi>b</mi>
			</mfrac>
			</math>的大小.
			<span class="btn-box" @click="isShowAnswer5 = !isShowAnswer5">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span> 作差可得<math display="0">
			<mfrac>
			<mrow>
			<mi>a</mi>
			<mo>+</mo>
			<mi>c</mi>
			</mrow>
			<mrow>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			</mrow>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mi>a</mi>
			<mi>b</mi>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<div v-if="isShowAnswer5">
			<p>
			<span class="zt-ls"><b>解</b></span> 作差可得<math display="0">
			<mfrac>
			<mrow>
			<mi>a</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mi>b</mi>
			</mrow>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mrow>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mi>b</mi>
			</mrow>
			</mfrac>
			<mo>−</mo>
			<mfrac>
			<mrow>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mi>a</mi>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</mrow>
			<mrow>
			<mi>b</mi>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mi>a</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</mrow>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mi>b</mi>
			<mo>−</mo>
			</mrow>
			</mfrac>
			<mo>−</mo>
			<mfrac>
			<mrow>
			<mi>a</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</mrow>
			<mi>c</mi>
			</mrow>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mrow>
			<mi>b</mi>
			<mo>+</mo>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</mrow>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mi>b</mi>
			<mo>−</mo>
			<mi>a</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mi>b</mi>
			</mrow>
			</mfrac>
			</math>.
			</p>
			<p>
			因为<i>b</i>＞<i>a</i>＞0，所以<i>b</i>-<i>a</i>＞0.又因为<i>c</i>＞0，所以<math display="0">
			<mfrac>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mi>b</mi>
			<mo>−</mo>
			</mrow>
			</mfrac>
			</math>.
			</p>
			<p>
			因为<i>b</i>＞<i>a</i>＞0，所以<i>b</i>-<i>a</i>＞0.又因为<i>c</i>＞0，所以<math display="0">
			<mfrac>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mi>b</mi>
			<mo>−</mo>
			<mi>a</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mi>c</mi>
			</mrow>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mi>b</mi>
			</mrow>
			</mfrac>
			<mo>＞</mo>
			<mn>0</mn>
			</math>，
			</p>
			<p>
			即<math display="0">
			<mfrac>
			<mrow>
			<mi>a</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			<mo>+</mo>
			<mi>c</mi>
			</mrow>
			<mi>c</mi>
			</mrow>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mrow>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mi>b</mi>
			</mrow>
			</mfrac>
			<mo>＞</mo>
			<mn>0</mn>
			</math>，
			</p>
			<p>
			即<math display="0">
			<mfrac>
			<mrow>
			</mfrac>
			<mo>−</mo>
			<mfrac>
			<mi>a</mi>
			<mo>+</mo>
			<mi>c</mi>
			</mrow>
			<mrow>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			</mrow>
			</mfrac>
			<mo>−</mo>
			<mfrac>
			<mi>a</mi>
			<mi>b</mi>
			</mfrac>
			<mo>＞</mo>
			<mn>0</mn>
			</math>，所以<math display="0">
			<mfrac>
			<mrow>
			</mfrac>
			<mo>＞</mo>
			<mn>0</mn>
			</math>，所以<math display="0">
			<mfrac>
			<mrow>
			<mi>a</mi>
			<mo>+</mo>
			<mi>c</mi>
			</mrow>
			<mrow>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			</mrow>
			</mfrac>
			<mo>＞</mo>
			<mfrac>
			<mi>a</mi>
			<mo>+</mo>
			<mi>c</mi>
			</mrow>
			<mrow>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			</mrow>
			</mfrac>
			<mo>＞</mo>
			<mfrac>
			<mi>a</mi>
			<mi>b</mi>
			</mfrac>
			</math>.
			</p>
			</mfrac>
			</math>.
			</p>
			</div>
			<div class="bk-hzjl">
			<div class="bj1-hzjl">
			<p class="left">
			@@ -817,8 +880,16 @@
			区间也是一个集合，它是实数集的一个子集.但并非所有的数集都能用区间表示.例如，集合{1，3，4，5，7，8，11，12}、自然数集<b>N</b>、整数集<b>Z</b>就不能用区间表示.
			</p>
			</div>
			<p>
			<span class="zt-ls"><b>例1</b></span>　把下列集合用区间表示出来，并指出区间的类型.
			<p class="p-btn">
			<span class="zt-ls"><b>例1</b></span>
			<span class="t1">把下列集合用区间表示出来，并指出区间的类型.</span>
			<span class="btn-box" @click="isShowAnswer6 = !isShowAnswer6">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>（1） {<i>x</i>\|-3≤<i>x</i>≤1}；（2） {<i>x</i>\|-1＜<i>x</i>＜2}；</p>
			<p>
			@@ -863,93 +934,114 @@
			</math>；
			</p>
			<p>（5） {<i>x</i>\|<i>x</i>≥2}；（6） {<i>x</i>\|<i>x</i>＜1}.</p>
			<p>
			<span class="zt-ls"><b>解</b></span>（1）［-3，1］，是闭区间；
			<div v-if="isShowAnswer6">
			<p>
			<span class="zt-ls"><b>解</b></span>（1）［-3，1］，是闭区间；
			</p>
			<p>（2）（-1，2），是开区间；</p>
			<p>
			（3）
			<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">[</mo>
			<mfrac>
			<mn>3</mn>
			<mn>2</mn>
			</mfrac>
			<mo>，</mo>
			<mn>4</mn>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>，是左闭右开区间；
			</p>
			<p>
			（4）
			<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mo>−</mo>
			<mn>6</mn>
			<mo>，</mo>
			<mo>−</mo>
			<mfrac>
			<mn>1</mn>
			<mn>2</mn>
			</mfrac>
			<mo data-mjx-texclass="CLOSE">]</mo>
			</mrow>
			</math>，是左开右闭区间；
			</p>
			<p>（5）［2，+∞），是左闭右开区间；</p>
			<p>（6）（-∞，1），是开区间.</p>
			</div>
			<p class="p-btn">
			<span class="zt-ls"><b>例2</b></span>
			<span class="t1">用区间表示不等式3<i>x</i>＜9<i>x</i>+4的解集，并在数轴上表示出来.</span>
			<span class="btn-box" @click="isShowAnswer7 = !isShowAnswer7">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>（2）（-1，2），是开区间；</p>
			<p>
			（3）
			<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">[</mo>
			<mfrac>
			<mn>3</mn>
			<mn>2</mn>
			</mfrac>
			<mo>，</mo>
			<mn>4</mn>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>，是左闭右开区间；
			<div v-if="isShowAnswer7">
			<p>
			<span class="zt-ls"><b>解</b></span> 解不等式3<i>x</i>＜9<i>x</i>+4，得
			</p>
			<math display="block">
			<mi>x</mi>
			<mo>＞</mo>
			<mo>−</mo>
			<mfrac>
			<mn>2</mn>
			<mn>3</mn>
			</mfrac>
			<mo>.</mo>
			</math>
			<p>
			所以不等式的解集用区间表示为<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mo>−</mo>
			<mfrac>
			<mn>2</mn>
			<mn>3</mn>
			</mfrac>
			<mo>，</mo>
			<mo>+</mo>
			<mi mathvariant="normal">∞</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>，表示在数轴上如图2-1所示.
			</p>
			<p class="center"><img class="img-f" alt="" src="../../assets/images/0050-7.jpg" /></p>
			<p class="img">图2-1</p>
			</div>
			<p class="p-btn">
			<span class="zt-ls"><b>例3</b></span>
			<span class="t1">设<b>R</b>为全集，集合A={x\|-5＜x＜6}，B={x\|x≥3或x≤-3}，用区间表示A∩B.</span>
			<span class="btn-box" @click="isShowAnswer8 = !isShowAnswer8">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			（4）
			<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mo>−</mo>
			<mn>6</mn>
			<mo>，</mo>
			<mo>−</mo>
			<mfrac>
			<mn>1</mn>
			<mn>2</mn>
			</mfrac>
			<mo data-mjx-texclass="CLOSE">]</mo>
			</mrow>
			</math>，是左开右闭区间；
			</p>
			<p>（5）［2，+∞），是左闭右开区间；</p>
			<p>（6）（-∞，1），是开区间.</p>
			<p>
			<span class="zt-ls"><b>例2</b></span>　用区间表示不等式3<i>x</i>＜9<i>x</i>+4的解集，并在数轴上表示出来.
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span> 解不等式3<i>x</i>＜9<i>x</i>+4，得
			</p>
			<math display="block">
			<mi>x</mi>
			<mo>＞</mo>
			<mo>−</mo>
			<mfrac>
			<mn>2</mn>
			<mn>3</mn>
			</mfrac>
			<mo>.</mo>
			</math>
			<p>
			所以不等式的解集用区间表示为<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mo>−</mo>
			<mfrac>
			<mn>2</mn>
			<mn>3</mn>
			</mfrac>
			<mo>，</mo>
			<mo>+</mo>
			<mi mathvariant="normal">∞</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>，表示在数轴上如图2-1所示.
			</p>
			<p class="center"><img class="img-f" alt="" src="../../assets/images/0050-7.jpg" /></p>
			<p class="img">图2-1</p>
			<p>
			<span
			class="zt-ls"><b>例3</b></span>　设<b>R</b>为全集，集合<i>A</i>={<i>x</i>\|-5＜<i>x</i>＜6}，<i>B</i>={<i>x</i>\|<i>x</i>≥3或<i>x</i>≤-3}，用区间表示<i>A</i>∩<i>B</i>.
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span>
			在数轴上将集合<i>A</i>，<i>B</i>表示出来，如图2-2所示.
			</p>
			<p class="center"><img class="img-d" alt="" src="../../assets/images/0050-8.jpg" /></p>
			<p class="img">图2-2</p>
			<p>
			<i>A</i>∩<i>B</i>={<i>x</i>\|-5＜<i>x</i>＜6}∩{<i>x</i>\|<i>x</i>≥3或<i>x</i>≤-3}
			</p>
			<p>={<i>x</i>\|-5＜<i>x</i>≤-3}∪{<i>x</i>\|3≤<i>x</i>＜6}</p>
			<p>=（-5，-3］∪［3，6）.</p>
			<div v-if="isShowAnswer8">
			<p>
			<span class="zt-ls"><b>解</b></span>
			在数轴上将集合<i>A</i>，<i>B</i>表示出来，如图2-2所示.
			</p>
			<p class="center"><img class="img-d" alt="" src="../../assets/images/0050-8.jpg" /></p>
			<p class="img">图2-2</p>
			<p>
			<i>A</i>∩<i>B</i>={<i>x</i>\|-5＜<i>x</i>＜6}∩{<i>x</i>\|<i>x</i>≥3或<i>x</i>≤-3}
			</p>
			<p>={<i>x</i>\|-5＜<i>x</i>≤-3}∪{<i>x</i>\|3≤<i>x</i>＜6}</p>
			<p>=（-5，-3］∪［3，6）.</p>
			</div>
			</div>
			</div>
			</div>
			@@ -971,8 +1063,8 @@
			</div>
			<h3 id="c015">习题2.2<span class="fontsz2">＞＞＞</span></h3>
			<div class="bj">
			<examinations :cardList="questionData[47] ? questionData[47][2] : []" :hideCollect="true" sourceType="json" inputBc="#d3edfa"
			v-if="questionData"></examinations>
			<examinations :cardList="questionData[47] ? questionData[47][2] : []" :hideCollect="true" sourceType="json"
			inputBc="#d3edfa" v-if="questionData"></examinations>
			</div>
			<h2 id="b009">
			2.3 一元二次不等式<span class="fontsz1">＞＞＞＞＞＞＞＞</span>
			@@ -1135,24 +1227,50 @@
			</math>，与<i>y</i>轴的交点坐标为（0，<i>c</i>）.
			</p>
			</div>
			<p><b>例</b> 已知二次函数<i>y</i>=<i>x</i><sup>2</sup>-2<i>x</i>-3，</p>
			<p>（1）画出该函数图像；</p>
			<p>
			<p class="p-btn">
			<b>例</b>
			<span>已知二次函数<i>y</i>=<i>x</i><sup>2</sup>-2<i>x</i>-3，</span>
			<span class="btn-box" @click="openDialog(thinkOne)">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.545" height="18.112" viewBox="0 0 20.545 22.112">
			<path class="a"
			d="M3771.2-14311.889a2.356,2.356,0,0,1-1.727-.626c-.027-.054-.053-.1-.079-.148l0-.007c-.123-.224-.2-.371-.076-.629a.869.869,0,0,1,.784-.471.205.205,0,0,1,.158.079.205.205,0,0,0,.158.079.187.187,0,0,0,.038.1.143.143,0,0,0,.117.05h.158a.573.573,0,0,0,.471.158,2.2,2.2,0,0,0,.916-.3l.023-.011a.572.572,0,0,1,.471-.158.575.575,0,0,1,.626.626.526.526,0,0,1,.036.409.664.664,0,0,1-.349.375A3.582,3.582,0,0,1,3771.2-14311.889Zm-1.885-1.723h-.155a.718.718,0,0,1-.784-.63.38.38,0,0,1-.021-.3.976.976,0,0,1,.492-.485l4.86-1.252a1.047,1.047,0,0,1,.784.626c.151.3-.128.61-.471.784l-4.705,1.256Zm-.155-1.885H3769a.716.716,0,0,1-.784-.626c-.149-.3.129-.611.471-.784l4.234-1.1v-.158l-.021.007a7.808,7.808,0,0,1-1.861.31,5.3,5.3,0,0,1-3.137-.942,5.789,5.789,0,0,1-2.666-4.076,6.421,6.421,0,0,1,1.256-5.018,7.038,7.038,0,0,1,2.194-1.568,7.848,7.848,0,0,1,2.666-.472,6.43,6.43,0,0,1,2.979.784,4.958,4.958,0,0,1,2.2,2.194,5.522,5.522,0,0,1,.313,5.177,13.113,13.113,0,0,1-1.256,1.882l-.313.313a2.156,2.156,0,0,0-.78,1.244l0,.012a1.731,1.731,0,0,1-1.727,1.723l-.313.158-3.292.939Zm1.256-6.271v1.256h1.41v-1.256Zm.784-4.234c.718,0,1.1.271,1.1.784a.925.925,0,0,1-.316.783l-.468.156a2.235,2.235,0,0,0-.63.471l-.012.024a2.2,2.2,0,0,0-.3.918v.155h1.1v-.155a1.2,1.2,0,0,1,.313-.629.543.543,0,0,0,.315-.153c.007,0,.315,0,.315-.16a1.226,1.226,0,0,0,.626-.626,2.277,2.277,0,0,0,.313-1.1,1.409,1.409,0,0,0-.626-1.252,2.337,2.337,0,0,0-1.569-.471,2.258,2.258,0,0,0-2.507,2.353l1.252.154A1.121,1.121,0,0,1,3771.2-14326Zm-6.51,9.645a.769.769,0,0,1-.549-.237.772.772,0,0,1-.235-.549.772.772,0,0,1,.235-.548l.939-.939a.781.781,0,0,1,.55-.234.772.772,0,0,1,.547.234.772.772,0,0,1,.238.549.772.772,0,0,1-.238.549l-.939.938A.769.769,0,0,1,3764.686-14316.356Zm13.174-.157a.774.774,0,0,1-.549-.234l-.943-.942a.678.678,0,0,1-.233-.47.678.678,0,0,1,.233-.47.774.774,0,0,1,.549-.234.774.774,0,0,1,.549.234l.942.939a.427.427,0,0,1,.228.324.74.74,0,0,1-.228.618A.774.774,0,0,1,3777.859-14316.514Zm2.9-6.351h-1.414c-.469-.158-.784-.474-.784-.784a.743.743,0,0,1,.784-.784h1.414a.743.743,0,0,1,.784.784A.743.743,0,0,1,3780.761-14322.864Zm-17.566-.158h-1.41c-.469-.157-.784-.473-.784-.784a.743.743,0,0,1,.784-.784h1.41a.743.743,0,0,1,.784.784A.743.743,0,0,1,3763.195-14323.022Zm13.861-5.723a.759.759,0,0,1-.529-.237.776.776,0,0,1-.235-.549.772.772,0,0,1,.235-.549l.939-.938a.44.44,0,0,1,.413-.238.759.759,0,0,1,.529.238.772.772,0,0,1,.235.549.772.772,0,0,1-.235.548l-.942.939A.435.435,0,0,1,3777.055-14328.745Zm-11.429,0a.776.776,0,0,1-.55-.237l-.939-1.1a.678.678,0,0,1-.235-.469.678.678,0,0,1,.235-.47.772.772,0,0,1,.549-.238.772.772,0,0,1,.549.238l.939,1.1a.675.675,0,0,1,.238.47.675.675,0,0,1-.238.47A.767.767,0,0,1,3765.626-14328.745Zm5.724-2.273a.743.743,0,0,1-.784-.785v-1.413c.157-.469.473-.784.784-.784a.743.743,0,0,1,.784.784v1.413A.743.743,0,0,1,3771.35-14331.019Z"
			transform="translate(-3761 14334.001)" />
			</svg>
			</span>
			</p>
			<p class="p-btn">
			（1）画出该函数图像；
			<span class="btn-box" @click="isShowAnswer9 = !isShowAnswer9">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p class="p-btn">
			（2）
			指出该函数图像上纵坐标分别为<i>y</i>=0，<i>y</i>＞0，<i>y</i>＜0的所有点；
			指出该函数图像上纵坐标分别为y=0，y＞0，y＜0的所有点；
			<span class="btn-box" @click="isShowAnswer10 = !isShowAnswer10">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			<p class="p-btn">
			（3）
			根据函数图像写出<i>y</i>=0，<i>y</i>＞0，<i>y</i>＜0时所对应的<i>x</i>的值或取值范围.
			根据函数图像写出y=0，y＞0，y＜0时所对应的x的值或取值范围.
			<span class="btn-box" @click="isShowAnswer11 = !isShowAnswer11">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p class="block">
			<span
			class="zt-ls2"><b>分析</b></span>　①根据<i>x</i><sup>2</sup>的系数判断函数图像（抛物线）的开口方向；②用判别式判定出一元二次方程<i>x</i><sup>2</sup>-2<i>x</i>-3=0的解的情况，从而确定二次函数<i>y</i>=<i>x</i><sup>2</sup>-2<i>x</i>-3的图像与<i>x</i>轴的交点个数和交点坐标；③计算二次函数图像的顶点坐标、与<i>y</i>轴的交点坐标；④求出二次函数图像的对称轴方程，并利用函数图像的对称性再找出一些点；⑤最后根据上述信息画出函数图像.
			</p>
			<p class="block">
			画出图像后，<i>y</i>=0，<i>y</i>＞0，<i>y</i>＜0分别对应函数图像与<i>x</i>轴相交、函数图像在<i>x</i>轴上方、函数图像在<i>x</i>轴下方三种情形，根据图像完成（2）（3）
			两个问题.
			</p>
			<iframe src="https://www.geogebra.org/calculator" frameborder="0" class="iframe-box"></iframe>
			</div>
			</div>
			</div>
			@@ -1165,23 +1283,59 @@
			<li>上册</li>
			</ul>
			<div class="padding-116">
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0055-1.jpg" /></p>
			<p class="img">图2-3</p>
			<p>
			<span class="zt-ls"><b>解</b></span>（1）因为<i>a</i>=1＞0，所以函数图像为开口向上的抛物线.
			</p>
			<p>
			因为<i>Δ</i>=<i>b</i><sup>2</sup>-4<i>ac</i>=（-2）<sup>2</sup>-4×1×（-3）=16＞0，
			</p>
			<p>
			所以一元二次方程<i>x</i><sup>2</sup>-2<i>x</i>-3=0有两个不相等的实数解.
			</p>
			<p>解方程，得<i>x</i><sub>1</sub>=-1，<i>x</i><sub>2</sub>=3.</p>
			<p>所以抛物线与<i>x</i>轴的交点坐标为（-1，0），（3，0）.</p>
			<p>
			抛物线的顶点坐标为<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<div v-if="isShowAnswer9">
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0055-1.jpg" /></p>
			<p class="img">图2-3</p>
			<p>
			<span class="zt-ls"><b>解</b></span>（1）因为<i>a</i>=1＞0，所以函数图像为开口向上的抛物线.
			</p>
			<p>
			因为<i>Δ</i>=<i>b</i><sup>2</sup>-4<i>ac</i>=（-2）<sup>2</sup>-4×1×（-3）=16＞0，
			</p>
			<p>
			所以一元二次方程<i>x</i><sup>2</sup>-2<i>x</i>-3=0有两个不相等的实数解.
			</p>
			<p>解方程，得<i>x</i><sub>1</sub>=-1，<i>x</i><sub>2</sub>=3.</p>
			<p>所以抛物线与<i>x</i>轴的交点坐标为（-1，0），（3，0）.</p>
			<p>
			抛物线的顶点坐标为<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mo>−</mo>
			<mfrac>
			<mi>b</mi>
			<mrow>
			<mn>2</mn>
			<mi>a</mi>
			</mrow>
			</mfrac>
			<mo>，</mo>
			<mfrac>
			<mrow>
			<mn>4</mn>
			<mi>a</mi>
			<mi>c</mi>
			<mo>−</mo>
			<msup>
			<mi>b</mi>
			<mrow>
			<mn>2</mn>
			</mrow>
			</msup>
			</mrow>
			<mrow>
			<mn>4</mn>
			<mi>a</mi>
			</mrow>
			</mfrac>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>，即（1，-4）.
			</p>
			<p>
			抛物线的对称轴方程为<math display="0">
			<mi>x</mi>
			<mo>=</mo>
			<mo>−</mo>
			<mfrac>
			<mi>b</mi>
			@@ -1190,78 +1344,44 @@
			<mi>a</mi>
			</mrow>
			</mfrac>
			<mo>，</mo>
			<mfrac>
			<mrow>
			<mn>4</mn>
			<mi>a</mi>
			<mi>c</mi>
			<mo>−</mo>
			<msup>
			<mi>b</mi>
			<mrow>
			<mn>2</mn>
			</mrow>
			</msup>
			</mrow>
			<mrow>
			<mn>4</mn>
			<mi>a</mi>
			</mrow>
			</mfrac>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>，即（1，-4）.
			</p>
			<p>
			抛物线的对称轴方程为<math display="0">
			<mi>x</mi>
			<mo>=</mo>
			<mo>−</mo>
			<mfrac>
			<mi>b</mi>
			<mrow>
			<mn>2</mn>
			<mi>a</mi>
			</mrow>
			</mfrac>
			</math>，即<i>x</i>=1.抛物线与<i>y</i>轴的交点坐标为（0，<i>c</i>），即（0，-3）.根据函数的对称性，可以再取一些点，如（2，-3）.
			</p>
			<p>
			根据以上信息，就可以画出函数<i>y</i>=<i>x</i><sup>2</sup>-2<i>x</i>-3的图像（如图2-3所示）.
			</p>
			<p>
			</math>，即<i>x</i>=1.抛物线与<i>y</i>轴的交点坐标为（0，<i>c</i>），即（0，-3）.根据函数的对称性，可以再取一些点，如（2，-3）.
			</p>
			<p>
			根据以上信息，就可以画出函数<i>y</i>=<i>x</i><sup>2</sup>-2<i>x</i>-3的图像（如图2-3所示）.
			</p>
			</div>
			<p v-if="isShowAnswer10">
			（2）
			观察图像可知，满足<i>y</i>=0的点是抛物线与<i>x</i>轴的交点；满足<i>y</i>＞0的点是抛物线在<i>x</i>轴上方的所有点；满足<i>y</i>＜0的点是抛物线在<i>x</i>轴下方的所有点.
			</p>
			<p>
			（3）
			观察图像可知，当<i>y</i>=0时，对应抛物线与<i>x</i>轴的两个交点，此时<i>x</i>有两个取值，<i>x</i><sub>1</sub>=-1，<i>x</i><sub>2</sub>=3；
			</p>
			<p>
			当<i>y</i>＞0时，对应抛物线在<i>x</i>轴上方的所有点，此时<i>x</i>的取值范围是<i>x</i>＜-1或<i>x</i>＞3；
			</p>
			<p>
			当<i>y</i>＜0时，对应抛物线在<i>x</i>轴下方的所有点，此时<i>x</i>的取值范围是-1＜<i>x</i>＜3.
			</p>
			<div v-if="isShowAnswer11">
			<p>
			（3）
			观察图像可知，当<i>y</i>=0时，对应抛物线与<i>x</i>轴的两个交点，此时<i>x</i>有两个取值，<i>x</i><sub>1</sub>=-1，<i>x</i><sub>2</sub>=3；
			</p>
			<p>
			当<i>y</i>＞0时，对应抛物线在<i>x</i>轴上方的所有点，此时<i>x</i>的取值范围是<i>x</i>＜-1或<i>x</i>＞3；
			</p>
			<p>
			当<i>y</i>＜0时，对应抛物线在<i>x</i>轴下方的所有点，此时<i>x</i>的取值范围是-1＜<i>x</i>＜3.
			</p>
			</div>
			<div class="bk-hzjl">
			<div class="bj1-hzjl">
			<p class="left">
			<img class="img-gn2" alt="" src="../../assets/images/hzjl.jpg" />
			</p>
			</div>
			<examinations :cardList="questionData[51] ? questionData[51][1] : []" :hideCollect="true" sourceType="json" inputBc="#d3edfa"
			v-if="questionData"></examinations>
			<examinations :cardList="questionData[51] ? questionData[51][1] : []" :hideCollect="true" sourceType="json"
			inputBc="#d3edfa" v-if="questionData"></examinations>
			</div>
			<p class="left"><img class="img-gn" alt="" src="../../assets/images/stlx.jpg" /></p>
			<div class="bj">
			<p>已知下列二次函数：</p>
			<p>①<i>y</i>=<i>x</i><sup>2</sup>-3<i>x</i>-4， ②<i>y</i>=<i>x</i><sup>2</sup>+<i>x</i>+2， ③<i>y</i>=<i>x</i><sup>2</sup>-6<i>x</i>+9.</p>
			<p>①<i>y</i>=<i>x</i><sup>2</sup>-3<i>x</i>-4， ②<i>y</i>=<i>x</i><sup>2</sup>+<i>x</i>+2，
			③<i>y</i>=<i>x</i><sup>2</sup>-6<i>x</i>+9.</p>
			<p>（1）分别画出它们的函数图像；</p>
			<paint
			:page="51"
			:imgUrl="this.config.activeBook.resourceUrl + '/images/a6fe3d63.png'"
			/>
			<paint :page="51" :imgUrl="this.config.activeBook.resourceUrl + '/images/a6fe3d63.png'" />
			<p>
			（2）根据函数图像写出<i>y</i>=0，<i>y</i>＞0，<i>y</i>＜0时所对应的<i>x</i>的值或取值范围.
			<span class="btn-box" @click="isShowAnswer = !isShowAnswer">
			@@ -1272,23 +1392,334 @@
			</svg>
			</span>
			</p>
			<el-input type="textarea" placeholder="请输入内容" rows="6" class="question-textarea" ></el-input>
			<el-input type="textarea" placeholder="请输入内容" rows="6" class="question-textarea"></el-input>
			<ul class="table-answer-box" v-if="isShowAnswer">
			<li>答案：</li>
			<li>
			<math display="block"> <mrow> <mo>①</mo> </mrow> <mi>y</mi> <mo>=</mo> <msup> <mi>x</mi> <mrow> <mn>2</mn> </mrow> </msup> <mo>−</mo> <mn>3</mn> <mi>x</mi> <mo>−</mo> <mn>4</mn> <mo>=</mo> <mo stretchy="false">(</mo> <mi>x</mi> <mo>+</mo> <mn>1</mn> <mo stretchy="false">)</mo> <mo stretchy="false">(</mo> <mi>x</mi> <mo>−</mo> <mn>4</mn> <mo stretchy="false">)</mo></math>
			<math display="block"> <mo>当</mo> <mi>y</mi> <mo>=</mo> <mn>0</mn> <mo>时，</mo> <msub> <mi>x</mi> <mrow> <mn>1</mn> </mrow> </msub> <mo>=</mo> <mo>−</mo> <mn>1</mn> <mo>或</mo> <msub> <mi>x</mi> <mrow> <mn>2</mn> </mrow> </msub> <mo>=</mo> <mn>4</mn> <mo>，</mo></math>
			<math display="block"> <mo>当</mo> <mi>y</mi> <mo>></mo> <mn>0</mn> <mo>时，</mo> <mi>x</mi> <mo><</mo> <mo>−</mo> <mn>1</mn> <mo>或</mo> <mi>x</mi> <mo>></mo> <mn>4</mn> <mo>，</mo></math>
			<math display="block"> <mo>当</mo> <mi>y</mi> <mo><</mo> <mn>0</mn> <mo>时，</mo> <mo>−</mo> <mn>1</mn> <mo><</mo> <mi>x</mi> <mo><</mo> <mn>4</mn> <mo>；</mo></math>
			<math display="block"> <mo>因此当</mo> <mi>y</mi> <mo>=</mo> <mn>0</mn> <mo>时，所对应的点为</mo> <mo stretchy="false">(</mo> <mo>−</mo> <mn>1</mn> <mo>,</mo> <mn>0</mn> <mo stretchy="false">)</mo> <mo>,</mo> <mo stretchy="false">(</mo> <mn>4</mn> <mo>,</mo> <mn>0</mn> <mo stretchy="false">)</mo> <mo>;</mo> <mo>当</mo> <mi>y</mi> <mo>></mo> <mn>0</mn> <mo>时，所对应的点为</mo> </math>
			<math display="block"> <mo stretchy="false">(</mo> <msub> <mi>x</mi> <mrow> <mn>0</mn> </mrow> </msub> <mo>,</mo> <mi>y</mi> <mo stretchy="false">)</mo> <mo>，其中，</mo> <msub> <mi>x</mi> <mrow> <mn>0</mn> </mrow> </msub> <mo><</mo> <mo>−</mo> <mn>1</mn> <mo>或</mo> <msub> <mi>x</mi> <mrow> <mn>0</mn> </mrow> </msub> <mo>></mo> <mn>4</mn> <mo>；</mo> </math>
			<math display="block"> <mo>当</mo> <mi>y</mi> <mo><</mo> <mn>0</mn> <mo>时，所对应的点为</mo> <mo stretchy="false">(</mo> <msub> <mi>x</mi> <mrow> <mn>0</mn> </mrow> </msub> <mo>,</mo> <mi>y</mi> <mo stretchy="false">)</mo> <mo>，其中</mo> <mo>−</mo> <mn>1</mn> <mo><</mo> <msub> <mi>x</mi> <mrow> <mn>0</mn> </mrow> </msub> <mo><</mo> <mn>4</mn> <mo>；</mo></math>
			<math display="block"> <mrow> <mo>②</mo> </mrow> <mi>y</mi> <mo>=</mo> <msup> <mi>x</mi> <mrow> <mn>2</mn> </mrow> </msup> <mo>+</mo> <mi>x</mi> <mo>+</mo> <mn>2</mn> <mo>=</mo> <mo stretchy="false">(</mo> <mi>x</mi> <mo>+</mo> <mfrac> <mn>1</mn> <mn>2</mn> </mfrac> <msup> <mo stretchy="false">)</mo> <mrow> <mn>2</mn> </mrow> </msup> <mo>+</mo> <mfrac> <mn>7</mn> <mn>4</mn> </mfrac> <mo>></mo> <mn>0</mn> <mo>；</mo></math>
			<math display="block"> <mo>当</mo> <mi>y</mi> <mo>=</mo> <mn>0</mn> <mo>，</mo> <mi>y</mi> <mo><</mo> <mn>0</mn> <mo>时，没有对应的点；当</mo> <mi>y</mi> <mo>></mo> <mn>0</mn> <mo>时，所对应的点为</mo> <mo stretchy="false">(</mo> <msub> <mi>x</mi> <mrow> <mn>0</mn> </mrow> </msub> <mo>,</mo> <mi>y</mi> <mo stretchy="false">)</mo> </math>
			<math> <mo>，其中</mo> <msub> <mi>x</mi> <mrow> <mn>0</mn> </mrow> </msub> <mo>∈</mo> <mi>R</mi> <mo>.</mo></math>
			<math display="block"> <mrow> <mo>③</mo> </mrow> <mi>y</mi> <mo>=</mo> <msup> <mi>x</mi> <mrow> <mn>2</mn> </mrow> </msup> <mo>−</mo> <mn>6</mn> <mi>x</mi> <mo>+</mo> <mn>9</mn> <mo>=</mo> <mo stretchy="false">(</mo> <mi>x</mi> <mo>−</mo> <mn>3</mn> <msup> <mo stretchy="false">)</mo> <mrow> <mn>2</mn> </mrow> </msup> <mo>.</mo></math>
			<math display="block"> <mo>当</mo> <mi>y</mi> <mo>=</mo> <mn>0</mn> <mo>时</mo> <mo>,</mo> <mo>所对应的点为</mo> <mo stretchy="false">(</mo> <mn>3</mn> <mo>,</mo> <mn>0</mn> <mo stretchy="false">)</mo> <mo>；当</mo> <mi>y</mi> <mo>></mo> <mn>0</mn> <mo>时，所对应的点为</mo> <mo stretchy="false">(</mo> <msub> <mi>x</mi> <mrow> <mn>0</mn> </mrow> </msub> <mo>,</mo> <mi>y</mi> <mo stretchy="false">)</mo> </math>
			<math display="block"> <mo>，其中</mo> <msub> <mi>x</mi> <mrow> <mn>0</mn> </mrow> </msub> <mo>≠</mo> <mn>3</mn> <mo>；当</mo> <mi>y</mi> <mo><</mo> <mn>0</mn> <mo>时，没有对应的点</mo> <mo>.</mo></math>
			<math display="block">
			<mrow>
			<mo>①</mo>
			</mrow>
			<mi>y</mi>
			<mo>=</mo>
			<msup>
			<mi>x</mi>
			<mrow>
			<mn>2</mn>
			</mrow>
			</msup>
			<mo>−</mo>
			<mn>3</mn>
			<mi>x</mi>
			<mo>−</mo>
			<mn>4</mn>
			<mo>=</mo>
			<mo stretchy="false">(</mo>
			<mi>x</mi>
			<mo>+</mo>
			<mn>1</mn>
			<mo stretchy="false">)</mo>
			<mo stretchy="false">(</mo>
			<mi>x</mi>
			<mo>−</mo>
			<mn>4</mn>
			<mo stretchy="false">)</mo>
			</math>
			<math display="block">
			<mo>当</mo>
			<mi>y</mi>
			<mo>=</mo>
			<mn>0</mn>
			<mo>时，</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>1</mn>
			</mrow>
			</msub>
			<mo>=</mo>
			<mo>−</mo>
			<mn>1</mn>
			<mo>或</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>2</mn>
			</mrow>
			</msub>
			<mo>=</mo>
			<mn>4</mn>
			<mo>，</mo>
			</math>
			<math display="block">
			<mo>当</mo>
			<mi>y</mi>
			<mo>></mo>
			<mn>0</mn>
			<mo>时，</mo>
			<mi>x</mi>
			<mo><</mo>
			<mo>−</mo>
			<mn>1</mn>
			<mo>或</mo>
			<mi>x</mi>
			<mo>></mo>
			<mn>4</mn>
			<mo>，</mo>
			</math>
			<math display="block">
			<mo>当</mo>
			<mi>y</mi>
			<mo><</mo>
			<mn>0</mn>
			<mo>时，</mo>
			<mo>−</mo>
			<mn>1</mn>
			<mo><</mo>
			<mi>x</mi>
			<mo><</mo>
			<mn>4</mn>
			<mo>；</mo>
			</math>
			<math display="block">
			<mo>因此当</mo>
			<mi>y</mi>
			<mo>=</mo>
			<mn>0</mn>
			<mo>时，所对应的点为</mo>
			<mo stretchy="false">(</mo>
			<mo>−</mo>
			<mn>1</mn>
			<mo>,</mo>
			<mn>0</mn>
			<mo stretchy="false">)</mo>
			<mo>,</mo>
			<mo stretchy="false">(</mo>
			<mn>4</mn>
			<mo>,</mo>
			<mn>0</mn>
			<mo stretchy="false">)</mo>
			<mo>;</mo>
			<mo>当</mo>
			<mi>y</mi>
			<mo>></mo>
			<mn>0</mn>
			<mo>时，所对应的点为</mo>
			</math>
			<math display="block">
			<mo stretchy="false">(</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>0</mn>
			</mrow>
			</msub>
			<mo>,</mo>
			<mi>y</mi>
			<mo stretchy="false">)</mo>
			<mo>，其中，</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>0</mn>
			</mrow>
			</msub>
			<mo><</mo>
			<mo>−</mo>
			<mn>1</mn>
			<mo>或</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>0</mn>
			</mrow>
			</msub>
			<mo>></mo>
			<mn>4</mn>
			<mo>；</mo>
			</math>
			<math display="block">
			<mo>当</mo>
			<mi>y</mi>
			<mo><</mo>
			<mn>0</mn>
			<mo>时，所对应的点为</mo>
			<mo stretchy="false">(</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>0</mn>
			</mrow>
			</msub>
			<mo>,</mo>
			<mi>y</mi>
			<mo stretchy="false">)</mo>
			<mo>，其中</mo>
			<mo>−</mo>
			<mn>1</mn>
			<mo><</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>0</mn>
			</mrow>
			</msub>
			<mo><</mo>
			<mn>4</mn>
			<mo>；</mo>
			</math>
			<math display="block">
			<mrow>
			<mo>②</mo>
			</mrow>
			<mi>y</mi>
			<mo>=</mo>
			<msup>
			<mi>x</mi>
			<mrow>
			<mn>2</mn>
			</mrow>
			</msup>
			<mo>+</mo>
			<mi>x</mi>
			<mo>+</mo>
			<mn>2</mn>
			<mo>=</mo>
			<mo stretchy="false">(</mo>
			<mi>x</mi>
			<mo>+</mo>
			<mfrac>
			<mn>1</mn>
			<mn>2</mn>
			</mfrac>
			<msup>
			<mo stretchy="false">)</mo>
			<mrow>
			<mn>2</mn>
			</mrow>
			</msup>
			<mo>+</mo>
			<mfrac>
			<mn>7</mn>
			<mn>4</mn>
			</mfrac>
			<mo>></mo>
			<mn>0</mn>
			<mo>；</mo>
			</math>
			<math display="block">
			<mo>当</mo>
			<mi>y</mi>
			<mo>=</mo>
			<mn>0</mn>
			<mo>，</mo>
			<mi>y</mi>
			<mo><</mo>
			<mn>0</mn>
			<mo>时，没有对应的点；当</mo>
			<mi>y</mi>
			<mo>></mo>
			<mn>0</mn>
			<mo>时，所对应的点为</mo>
			<mo stretchy="false">(</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>0</mn>
			</mrow>
			</msub>
			<mo>,</mo>
			<mi>y</mi>
			<mo stretchy="false">)</mo>
			</math>
			<math>
			<mo>，其中</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>0</mn>
			</mrow>
			</msub>
			<mo>∈</mo>
			<mi>R</mi>
			<mo>.</mo>
			</math>
			<math display="block">
			<mrow>
			<mo>③</mo>
			</mrow>
			<mi>y</mi>
			<mo>=</mo>
			<msup>
			<mi>x</mi>
			<mrow>
			<mn>2</mn>
			</mrow>
			</msup>
			<mo>−</mo>
			<mn>6</mn>
			<mi>x</mi>
			<mo>+</mo>
			<mn>9</mn>
			<mo>=</mo>
			<mo stretchy="false">(</mo>
			<mi>x</mi>
			<mo>−</mo>
			<mn>3</mn>
			<msup>
			<mo stretchy="false">)</mo>
			<mrow>
			<mn>2</mn>
			</mrow>
			</msup>
			<mo>.</mo>
			</math>
			<math display="block">
			<mo>当</mo>
			<mi>y</mi>
			<mo>=</mo>
			<mn>0</mn>
			<mo>时</mo>
			<mo>,</mo>
			<mo>所对应的点为</mo>
			<mo stretchy="false">(</mo>
			<mn>3</mn>
			<mo>,</mo>
			<mn>0</mn>
			<mo stretchy="false">)</mo>
			<mo>；当</mo>
			<mi>y</mi>
			<mo>></mo>
			<mn>0</mn>
			<mo>时，所对应的点为</mo>
			<mo stretchy="false">(</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>0</mn>
			</mrow>
			</msub>
			<mo>,</mo>
			<mi>y</mi>
			<mo stretchy="false">)</mo>
			</math>
			<math display="block">
			<mo>，其中</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>0</mn>
			</mrow>
			</msub>
			<mo>≠</mo>
			<mn>3</mn>
			<mo>；当</mo>
			<mi>y</mi>
			<mo><</mo>
			<mn>0</mn>
			<mo>时，没有对应的点</mo>
			<mo>.</mo>
			</math>
			</li>
			</ul>
			</div>
			@@ -1502,34 +1933,56 @@
			上面的情形表明，二次函数图像的开口方向及其与<i>x</i>轴的交点坐标，可以确定其对应的一元二次不等式的解集.
			</p>
			<p><b>例</b> 利用二次函数的图像解下列一元二次不等式.</p>
			<p>
			（1） -<i>x</i><sup>2</sup>+3<i>x</i>+4＜0；（2） <i>x</i><sup>2</sup>-2<i>x</i>+3＞0.
			<p class="p-btn" >
			<span>（1） -<i>x</i><sup>2</sup>+3<i>x</i>+4＜0；</span>
			<span class="btn-box" @click="isShowAnswer12 = !isShowAnswer12">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0057-1.jpg" /></p>
			<p class="img">图2-5</p>
			<p>
			<span class="zt-ls"><b>解</b></span>（1）
			Δ=<i>b</i><sup>2</sup>-4<i>ac</i>=3<sup>2</sup>-4×（-1）×4=25＞0，所以函数<i>y</i>=-<i>x</i><sup>2</sup>+3<i>x</i>+4的图像与<i>x</i>轴有两个交点.解方程-<i>x</i><sup>2</sup>+3<i>x</i>+4=0可得，<i>x</i>1=-1，<i>x</i>2=4.
			<p class="p-btn" >
			<span>（2） <i>x</i><sup>2</sup>-2<i>x</i>+3＞0.</span>
			<span class="btn-box" @click="isShowAnswer13 = !isShowAnswer13">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			函数<i>y</i>=-<i>x</i><sup>2</sup>+3<i>x</i>+4的图像是开口向下的抛物线，与<i>x</i>轴的交点坐标是（-1，0），（4，0），函数<i>y</i>=-<i>x</i><sup>2</sup>+3<i>x</i>+4的图像如图2-5所示.
			</p>
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0057-2.jpg" /></p>
			<p class="img">图2-6</p>
			<p>
			观察图像可得，不等式-<i>x</i><sup>2</sup>+3<i>x</i>+4＜0的解集是（-∞，
			-1）∪（4， +∞）.
			</p>
			<p>
			（2）
			<i>Δ</i>=<i>b</i><sup>2</sup>-4<i>ac</i>=（-2）<sup>2</sup>-4×1×3=-8＜0，所以函数<i>y</i>=<i>x</i><sup>2</sup>-2<i>x</i>+3的图像与<i>x</i>轴无交点.
			</p>
			<p>
			函数<i>y</i>=<i>x</i><sup>2</sup>-2<i>x</i>+3的图像是开口向上的抛物线，与<i>x</i>轴无交点，其简图如图2-6所示.
			</p>
			<p>
			观察图像可得，不等式<i>x</i><sup>2</sup>-2<i>x</i>+3＞0的解集为<b>R</b>.
			</p>
			<iframe src="https://www.geogebra.org/calculator" frameborder="0" class="iframe-box"></iframe>
			<div v-if="isShowAnswer12" >
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0057-1.jpg" /></p>
			<p class="img">图2-5</p>
			<p>
			<span class="zt-ls"><b>解</b></span>（1）
			Δ=<i>b</i><sup>2</sup>-4<i>ac</i>=3<sup>2</sup>-4×（-1）×4=25＞0，所以函数<i>y</i>=-<i>x</i><sup>2</sup>+3<i>x</i>+4的图像与<i>x</i>轴有两个交点.解方程-<i>x</i><sup>2</sup>+3<i>x</i>+4=0可得，<i>x</i>1=-1，<i>x</i>2=4.
			</p>
			<p>
			函数<i>y</i>=-<i>x</i><sup>2</sup>+3<i>x</i>+4的图像是开口向下的抛物线，与<i>x</i>轴的交点坐标是（-1，0），（4，0），函数<i>y</i>=-<i>x</i><sup>2</sup>+3<i>x</i>+4的图像如图2-5所示.
			</p>
			</div>
			<div v-if="isShowAnswer13" >
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0057-2.jpg" /></p>
			<p class="img">图2-6</p>
			<p>
			观察图像可得，不等式-<i>x</i><sup>2</sup>+3<i>x</i>+4＜0的解集是（-∞，
			-1）∪（4， +∞）.
			</p>
			<p>
			（2）
			<i>Δ</i>=<i>b</i><sup>2</sup>-4<i>ac</i>=（-2）<sup>2</sup>-4×1×3=-8＜0，所以函数<i>y</i>=<i>x</i><sup>2</sup>-2<i>x</i>+3的图像与<i>x</i>轴无交点.
			</p>
			<p>
			函数<i>y</i>=<i>x</i><sup>2</sup>-2<i>x</i>+3的图像是开口向上的抛物线，与<i>x</i>轴无交点，其简图如图2-6所示.
			</p>
			<p>
			观察图像可得，不等式<i>x</i><sup>2</sup>-2<i>x</i>+3＞0的解集为<b>R</b>.
			</p>
			</div>
			<div class="bk">
			<div class="bj1">
			<p class="left">
			@@ -1570,7 +2023,8 @@
			<img class="img-gn2" alt="" src="../../assets/images/hzjl.jpg" />
			</p>
			</div>
			<examinations :cardList="questionData[54] ? questionData[54][1] : []" :hideCollect="true" sourceType="json" v-if="questionData">
			<examinations :cardList="questionData[54] ? questionData[54][1] : []" :hideCollect="true" sourceType="json"
			v-if="questionData">
			</examinations>
			</div>
			<p class="left"><img class="img-gn" alt="" src="../../assets/images/cxgk.jpg" /></p>
			@@ -1585,8 +2039,8 @@
			</p>
			<p>第三步：观察简图，写出不等式的解集.</p>
			<div class="bj">
			<examinations :cardList="questionData[54] ? questionData[54][2] : []" :hideCollect="true" sourceType="json" inputBc="#d3edfa"
			v-if="questionData"></examinations>
			<examinations :cardList="questionData[54] ? questionData[54][2] : []" :hideCollect="true" sourceType="json"
			inputBc="#d3edfa" v-if="questionData"></examinations>
			</div>
			</div>
			</div>
			@@ -1752,46 +2206,95 @@
			<p>
			<span class="zt-ls"><b>例1</b></span>　解下列不等式.
			</p>
			<p>
			（1）（<i>x</i>+3）（<i>x</i>+1）＜0；（2）（6-<i>x</i>）（<i>x</i>+4）≤0.
			<p class="p-btn" >
			<span>（1）（<i>x</i>+3）（<i>x</i>+1）＜0；</span>
			<span class="btn-box" @click="isShowAnswer14 = !isShowAnswer14">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span>（1）（<i>x</i>+3）（<i>x</i>+1）＜0，即［<i>x</i>-（-3）］［<i>x</i>-（-1）］＜0.
			<p class="p-btn" >
			<span>（2）（6-<i>x</i>）（<i>x</i>+4）≤0.</span>
			<span class="btn-box" @click="isShowAnswer15 = !isShowAnswer15">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>所以不等式的解集为（-3，-1）.</p>
			<p>
			<div v-if="isShowAnswer14" >
			<p >
			<span class="zt-ls"><b>解</b></span>（1）（<i>x</i>+3）（<i>x</i>+1）＜0，即［<i>x</i>-（-3）］［<i>x</i>-（-1）］＜0.
			</p>
			<p >所以不等式的解集为（-3，-1）.</p>
			</div>
			<div v-if="isShowAnswer15" >
			<p>
			<span class="zt-ls"><b>解</b></span>
			（2）
			由（6-<i>x</i>）（<i>x</i>+4）≤0得（<i>x</i>-6）（<i>x</i>+4）≥0，即
			由（6-<i>x</i>）（<i>x</i>+4）≤0得（<i>x</i>-6）（<i>x</i>+4）≥0，即
			</p>
			<p class="center">（<i>x</i>-6）［<i>x</i>-（-4）］≥0.</p>
			<p>所以不等式的解集为（-∞，-4］∪［6，+∞）.</p>
			</div>
			<p class="p-btn" >
			<span>
			<span class="zt-ls"><b>例2</b></span>　解下列不等式.
			</span>
			<span class="btn-box" @click="openDialog(thinkTwo)">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.545" height="18.112" viewBox="0 0 20.545 22.112">
			<path class="a"
			d="M3771.2-14311.889a2.356,2.356,0,0,1-1.727-.626c-.027-.054-.053-.1-.079-.148l0-.007c-.123-.224-.2-.371-.076-.629a.869.869,0,0,1,.784-.471.205.205,0,0,1,.158.079.205.205,0,0,0,.158.079.187.187,0,0,0,.038.1.143.143,0,0,0,.117.05h.158a.573.573,0,0,0,.471.158,2.2,2.2,0,0,0,.916-.3l.023-.011a.572.572,0,0,1,.471-.158.575.575,0,0,1,.626.626.526.526,0,0,1,.036.409.664.664,0,0,1-.349.375A3.582,3.582,0,0,1,3771.2-14311.889Zm-1.885-1.723h-.155a.718.718,0,0,1-.784-.63.38.38,0,0,1-.021-.3.976.976,0,0,1,.492-.485l4.86-1.252a1.047,1.047,0,0,1,.784.626c.151.3-.128.61-.471.784l-4.705,1.256Zm-.155-1.885H3769a.716.716,0,0,1-.784-.626c-.149-.3.129-.611.471-.784l4.234-1.1v-.158l-.021.007a7.808,7.808,0,0,1-1.861.31,5.3,5.3,0,0,1-3.137-.942,5.789,5.789,0,0,1-2.666-4.076,6.421,6.421,0,0,1,1.256-5.018,7.038,7.038,0,0,1,2.194-1.568,7.848,7.848,0,0,1,2.666-.472,6.43,6.43,0,0,1,2.979.784,4.958,4.958,0,0,1,2.2,2.194,5.522,5.522,0,0,1,.313,5.177,13.113,13.113,0,0,1-1.256,1.882l-.313.313a2.156,2.156,0,0,0-.78,1.244l0,.012a1.731,1.731,0,0,1-1.727,1.723l-.313.158-3.292.939Zm1.256-6.271v1.256h1.41v-1.256Zm.784-4.234c.718,0,1.1.271,1.1.784a.925.925,0,0,1-.316.783l-.468.156a2.235,2.235,0,0,0-.63.471l-.012.024a2.2,2.2,0,0,0-.3.918v.155h1.1v-.155a1.2,1.2,0,0,1,.313-.629.543.543,0,0,0,.315-.153c.007,0,.315,0,.315-.16a1.226,1.226,0,0,0,.626-.626,2.277,2.277,0,0,0,.313-1.1,1.409,1.409,0,0,0-.626-1.252,2.337,2.337,0,0,0-1.569-.471,2.258,2.258,0,0,0-2.507,2.353l1.252.154A1.121,1.121,0,0,1,3771.2-14326Zm-6.51,9.645a.769.769,0,0,1-.549-.237.772.772,0,0,1-.235-.549.772.772,0,0,1,.235-.548l.939-.939a.781.781,0,0,1,.55-.234.772.772,0,0,1,.547.234.772.772,0,0,1,.238.549.772.772,0,0,1-.238.549l-.939.938A.769.769,0,0,1,3764.686-14316.356Zm13.174-.157a.774.774,0,0,1-.549-.234l-.943-.942a.678.678,0,0,1-.233-.47.678.678,0,0,1,.233-.47.774.774,0,0,1,.549-.234.774.774,0,0,1,.549.234l.942.939a.427.427,0,0,1,.228.324.74.74,0,0,1-.228.618A.774.774,0,0,1,3777.859-14316.514Zm2.9-6.351h-1.414c-.469-.158-.784-.474-.784-.784a.743.743,0,0,1,.784-.784h1.414a.743.743,0,0,1,.784.784A.743.743,0,0,1,3780.761-14322.864Zm-17.566-.158h-1.41c-.469-.157-.784-.473-.784-.784a.743.743,0,0,1,.784-.784h1.41a.743.743,0,0,1,.784.784A.743.743,0,0,1,3763.195-14323.022Zm13.861-5.723a.759.759,0,0,1-.529-.237.776.776,0,0,1-.235-.549.772.772,0,0,1,.235-.549l.939-.938a.44.44,0,0,1,.413-.238.759.759,0,0,1,.529.238.772.772,0,0,1,.235.549.772.772,0,0,1-.235.548l-.942.939A.435.435,0,0,1,3777.055-14328.745Zm-11.429,0a.776.776,0,0,1-.55-.237l-.939-1.1a.678.678,0,0,1-.235-.469.678.678,0,0,1,.235-.47.772.772,0,0,1,.549-.238.772.772,0,0,1,.549.238l.939,1.1a.675.675,0,0,1,.238.47.675.675,0,0,1-.238.47A.767.767,0,0,1,3765.626-14328.745Zm5.724-2.273a.743.743,0,0,1-.784-.785v-1.413c.157-.469.473-.784.784-.784a.743.743,0,0,1,.784.784v1.413A.743.743,0,0,1,3771.35-14331.019Z"
			transform="translate(-3761 14334.001)" />
			</svg>
			</span>
			</p>
			<p class="center">（<i>x</i>-6）［<i>x</i>-（-4）］≥0.</p>
			<p>所以不等式的解集为（-∞，-4］∪［6，+∞）.</p>
			<p>
			<span class="zt-ls"><b>例2</b></span>　解下列不等式.
			<p class="p-btn" >
			<span>（1）（<i>x</i>+1）<sup>2</sup>≥4；</span>
			<span class="btn-box" @click="isShowAnswer16 = !isShowAnswer16">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			（1）（<i>x</i>+1）<sup>2</sup>≥4；（2）（2<i>x</i>-3）<sup>2</sup>＜9.
			<p class="p-btn" >
			<span>（2）（2<i>x</i>-3）<sup>2</sup>＜9.</span>
			<span class="btn-box" @click="isShowAnswer17 = !isShowAnswer17">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p class="block">
			<span
			class="zt-ls2"><b>分析</b></span>　由（<i>x</i>+1）<sup>2</sup>≥4得<i>x</i><sup>2</sup>+2<i>x</i>+1≥4，即<i>x</i><sup>2</sup>+2<i>x</i>-3≥0，从而可以利用二次函数<i>y</i>=<i>x</i><sup>2</sup>+2<i>x</i>-3的图像进行求解；注意到4=2<sup>2</sup>，也可以考虑将（<i>x</i>+1）<sup>2</sup>≥4整理为（<i>x</i>+1）<sup>2</sup>-4≥0，并使用平方差公式，即（<i>x</i>+1）<sup>2</sup>-2<sup>2</sup>≥0，得到（<i>x</i>+3）（<i>x</i>-1）≥0，此时可以借助上面的结论直接求解.下面我们将使用后一种方法进行求解.
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span>（1）
			由（<i>x</i>+1）<sup>2</sup>≥4得（<i>x</i>+1）<sup>2</sup>-2<sup>2</sup>≥0，
			</p>
			<p>从而　　［（<i>x</i>+1）+2］［（<i>x</i>+1）-2］≥0，</p>
			<p>化简得（<i>x</i>+3）（<i>x</i>-1）≥0，</p>
			<p>即　　　［<i>x</i>-（-3）］（<i>x</i>-1）≥0，</p>
			<p>所以不等式的解集为（-∞，-3］∪［1，+∞）.</p>
			<p>
			（2）
			由（2<i>x</i>-3）<sup>2</sup>＜9得（2<i>x</i>-3）<sup>2</sup>-3<sup>2</sup>＜0，
			</p>
			<p>从而　　［（2<i>x</i>-3）+3］［（2<i>x</i>-3）-3］＜0，</p>
			<p>化简得　2<i>x</i>（2<i>x</i>-6）＜0，</p>
			<p>即　　　<i>x</i>（<i>x</i>-3）＜0，</p>
			<p>即（<i>x</i>-0）（<i>x</i>-3）＜0，</p>
			<p>所以不等式的解集为（0，3）.</p>
			<div v-if="isShowAnswer16" >
			<p>
			<span class="zt-ls"><b>解</b></span>（1）
			由（<i>x</i>+1）<sup>2</sup>≥4得（<i>x</i>+1）<sup>2</sup>-2<sup>2</sup>≥0，
			</p>
			<p>从而　　［（<i>x</i>+1）+2］［（<i>x</i>+1）-2］≥0，</p>
			<p>化简得（<i>x</i>+3）（<i>x</i>-1）≥0，</p>
			<p>即　　　［<i>x</i>-（-3）］（<i>x</i>-1）≥0，</p>
			<p>所以不等式的解集为（-∞，-3］∪［1，+∞）.</p>
			</div>
			<div v-if="isShowAnswer17" >
			<p>
			<span class="zt-ls"><b>解</b></span>
			（2）
			由（2<i>x</i>-3）<sup>2</sup>＜9得（2<i>x</i>-3）<sup>2</sup>-3<sup>2</sup>＜0，
			</p>
			<p>从而　　［（2<i>x</i>-3）+3］［（2<i>x</i>-3）-3］＜0，</p>
			<p>化简得　2<i>x</i>（2<i>x</i>-6）＜0，</p>
			<p>即　　　<i>x</i>（<i>x</i>-3）＜0，</p>
			<p>即（<i>x</i>-0）（<i>x</i>-3）＜0，</p>
			<p>所以不等式的解集为（0，3）.</p>
			</div>
			<p class="left"><img class="img-gn" alt="" src="../../assets/images/stlx.jpg" /></p>
			<div class="bj">
			<p>解下列一元二次不等式.</p>
			@@ -2060,60 +2563,73 @@
			</li>
			</ul>
			<div class="padding-116">
			<p><b>例</b> 解不等式\|2<i>x</i>\|＜5.</p>
			<p>
			<span class="zt-ls"><b>解</b></span>
			由\|2<i>x</i>\|＜5得-5＜2<i>x</i>＜5，
			<p class="p-btn" >
			<span>
			<b>例</b> 解不等式\|2<i>x</i>\|＜5.
			</span>
			<span class="btn-box" @click="isShowAnswer18 = !isShowAnswer18">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			即　<math display="0">
			<mo>−</mo>
			<mfrac>
			<mn>5</mn>
			<mn>2</mn>
			</mfrac>
			<mo>＜</mo>
			<mi>x</mi>
			<mo>＜</mo>
			<mfrac>
			<mn>5</mn>
			<mn>2</mn>
			</mfrac>
			</math>.
			</p>
			<p>
			所以不等式的解集是<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<div v-if="isShowAnswer18" >
			<p>
			<span class="zt-ls"><b>解</b></span>
			由\|2<i>x</i>\|＜5得-5＜2<i>x</i>＜5，
			</p>
			<p>
			即　<math display="0">
			<mo>−</mo>
			<mfrac>
			<mn>5</mn>
			<mn>2</mn>
			</mfrac>
			<mo>，</mo>
			<mo>＜</mo>
			<mi>x</mi>
			<mo>＜</mo>
			<mfrac>
			<mn>5</mn>
			<mn>2</mn>
			</mfrac>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>.
			</p>
			</math>.
			</p>
			<p>
			所以不等式的解集是<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mo>−</mo>
			<mfrac>
			<mn>5</mn>
			<mn>2</mn>
			</mfrac>
			<mo>，</mo>
			<mfrac>
			<mn>5</mn>
			<mn>2</mn>
			</mfrac>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>.
			</p>
			</div>
			<div class="bk-hzjl">
			<div class="bj1-hzjl">
			<p class="left">
			<img class="img-gn2" alt="" src="../../assets/images/hzjl.jpg" />
			</p>
			</div>
			<examinations :cardList="questionData[60] ? questionData[60][1] : []" :hideCollect="true" sourceType="json" inputBc="#d3edfa"
			v-if="questionData"></examinations>
			<examinations :cardList="questionData[60] ? questionData[60][1] : []" :hideCollect="true" sourceType="json"
			inputBc="#d3edfa" v-if="questionData"></examinations>
			</div>
			<p class="left">
			<img class="img-gn" alt="" src="../../assets/images/stlx.jpg" />
			</p>
			<div class="bj">
			<examinations :cardList="questionData[60] ? questionData[60][2] : []" :hideCollect="true" sourceType="json" inputBc="#d3edfa"
			v-if="questionData"></examinations>
			<examinations :cardList="questionData[60] ? questionData[60][2] : []" :hideCollect="true" sourceType="json"
			inputBc="#d3edfa" v-if="questionData"></examinations>
			</div>
			<h3 id="c021">
			2.4.2
			@@ -2123,23 +2639,49 @@
			<p>
			求解此类不等式时，可以将<i>ax</i>+<i>b</i>看作一个整体，再利用含绝对值不等式的基本解法，去掉绝对值，然后进行求解.
			</p>
			<p>
			<span class="zt-ls"><b>例1</b></span>　解不等式\|2<i>x</i>-1\|＜5.
			<p class="p-btn" >
			<span>
			<span class="zt-ls"><b>例1</b></span>　解不等式\|2<i>x</i>-1\|＜5.
			</span>
			<span class="btn-box" @click="isShowAnswer19 = !isShowAnswer19">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span>
			由\|2<i>x</i>-1\|＜5得-5＜2<i>x</i>-1＜5，
			<div v-if="isShowAnswer19" >
			<p>
			<span class="zt-ls"><b>解</b></span>
			由\|2<i>x</i>-1\|＜5得-5＜2<i>x</i>-1＜5，
			</p>
			<p>即　-4＜2<i>x</i>＜6，</p>
			<p>　　-2＜<i>x</i>＜3.</p>
			<p>所以不等式的解集是（-2，3）.</p>
			</div>
			<p class="p-btn" >
			<span>
			<span class="zt-ls"><b>例2</b></span>　解不等式\|1-2<i>x</i>\|＜3.
			</span>
			<span class="btn-box" @click="isShowAnswer20 = !isShowAnswer20">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>即　-4＜2<i>x</i>＜6，</p>
			<p>　　-2＜<i>x</i>＜3.</p>
			<p>所以不等式的解集是（-2，3）.</p>
			<p>
			<span class="zt-ls"><b>例2</b></span>　解不等式\|1-2<i>x</i>\|＜3.
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span> 因为\|1-2<i>x</i>\|=\|2<i>x</i>-1\|，
			</p>
			<p>所以由\|1-2<i>x</i>\|＜3得\|2<i>x</i>-1\|＜3.</p>
			<div v-if="isShowAnswer20" >
			<p>
			<span class="zt-ls"><b>解</b></span> 因为\|1-2<i>x</i>\|=\|2<i>x</i>-1\|，
			</p>
			<p>所以由\|1-2<i>x</i>\|＜3得\|2<i>x</i>-1\|＜3.</p>
			<p>由\|2<i>x</i>-1\|＜3得-3＜2<i>x</i>-1＜3，</p>
			<p>即　-2＜2<i>x</i>＜4，</p>
			<p>　　-1＜<i>x</i>＜2.</p>
			<p>所以不等式的解集是（-1，2）.</p>
			</div>
			</div>
			</div>
			</div>
			@@ -2152,38 +2694,56 @@
			<li>上册</li>
			</ul>
			<div class="padding-116">
			<p>由\|2<i>x</i>-1\|＜3得-3＜2<i>x</i>-1＜3，</p>
			<p>即　-2＜2<i>x</i>＜4，</p>
			<p>　　-1＜<i>x</i>＜2.</p>
			<p>所以不等式的解集是（-1，2）.</p>
			<p>
			<span class="zt-ls"><b>例3</b></span>　解不等式\|<i>x</i>+3\|≥2.
			<p class="p-btn" >
			<span>
			<span class="zt-ls"><b>例3</b></span>　解不等式\|<i>x</i>+3\|≥2.
			</span>
			<span class="btn-box" @click="isShowAnswer21 = !isShowAnswer21">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span>
			由\|<i>x</i>+3\|≥2得<i>x</i>+3≤-2或<i>x</i>+3≥2，
			<div v-if="isShowAnswer21" >
			<p>
			<span class="zt-ls"><b>解</b></span>
			由\|<i>x</i>+3\|≥2得<i>x</i>+3≤-2或<i>x</i>+3≥2，
			</p>
			<p>即　<i>x</i>≤-5或<i>x</i>≥-1.</p>
			<p>所以不等式的解集是（-∞，-5］∪［-1，+∞）.</p>
			<p>
			现在我们回到本节开始的问题，解不等式\|<i>x</i>-100\|≤3得97≤<i>x</i>≤103，解不等式\|<i>x</i>-100\|＞3得<i>x</i>＞103或<i>x</i>＜97.如果产权登记面积在97
			m<sup>2</sup>和103 m<sup>2</sup>之间（包含97 m<sup>2</sup>和103
			m<sup>2</sup>）
			时，李先生按照产权登记面积结算房款；如果产权登记面积小于97
			m<sup>2</sup>或大于103 m<sup>2</sup>时，李先生有权退房.
			</p>
			</div>
			<p class="p-btn" >
			<span>
			<span class="zt-ls"><b>例4</b></span>　解不等式\|3<i>x</i>-（<i>x</i>-2）\|≤2.
			</span>
			<span class="btn-box" @click="isShowAnswer22 = !isShowAnswer22">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>即　<i>x</i>≤-5或<i>x</i>≥-1.</p>
			<p>所以不等式的解集是（-∞，-5］∪［-1，+∞）.</p>
			<p>
			现在我们回到本节开始的问题，解不等式\|<i>x</i>-100\|≤3得97≤<i>x</i>≤103，解不等式\|<i>x</i>-100\|＞3得<i>x</i>＞103或<i>x</i>＜97.如果产权登记面积在97
			m<sup>2</sup>和103 m<sup>2</sup>之间（包含97 m<sup>2</sup>和103
			m<sup>2</sup>）
			时，李先生按照产权登记面积结算房款；如果产权登记面积小于97
			m<sup>2</sup>或大于103 m<sup>2</sup>时，李先生有权退房.
			</p>
			<p>
			<span class="zt-ls"><b>例4</b></span>　解不等式\|3<i>x</i>-（<i>x</i>-2）\|≤2.
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span>
			由\|3<i>x</i>-（<i>x</i>-2）\|≤2得\|3<i>x</i>-<i>x</i>+2\|≤2，
			</p>
			<p>即　　\|2<i>x</i>+2\|≤2，</p>
			<p>从而　-2≤2<i>x</i>+2≤2，</p>
			<p>　　　-4≤2<i>x</i>≤0，</p>
			<p>　　　-2≤<i>x</i>≤0.</p>
			<p>所以不等式的解集是［-2，0］.</p>
			<div v-if="isShowAnswer22">
			<p>
			<span class="zt-ls"><b>解</b></span>
			由\|3<i>x</i>-（<i>x</i>-2）\|≤2得\|3<i>x</i>-<i>x</i>+2\|≤2，
			</p>
			<p>即　　\|2<i>x</i>+2\|≤2，</p>
			<p>从而　-2≤2<i>x</i>+2≤2，</p>
			<p>　　　-4≤2<i>x</i>≤0，</p>
			<p>　　　-2≤<i>x</i>≤0.</p>
			<p>所以不等式的解集是［-2，0］.</p>
			</div>
			<p class="left"><img class="img-gn" alt="" src="../../assets/images/stlx.jpg" /></p>
			<div class="bj">
			<examinations :cardList="questionData[61]" :hideCollect="true" sourceType="json" inputBc="#d3edfa"
			@@ -2217,11 +2777,20 @@
			</h3>
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0066-11.jpg" /></p>
			<p class="img">图2-12</p>
			<p>
			<span class="zt-ls"><b>例1</b></span>　用篱笆在墙边围一块矩形小花坛，其中一边靠墙（如图2-12所示），篱笆总长为8m.若小花坛的面积不小于6
			m<sup>2</sup>，则小花坛垂直于墙的一边的长度范围是多少？
			<p class="p-btn" >
			<span>
			<span class="zt-ls"><b>例1</b></span>　用篱笆在墙边围一块矩形小花坛，其中一边靠墙（如图2-12所示），篱笆总长为8m.若小花坛的面积不小于6
			m<sup>2</sup>，则小花坛垂直于墙的一边的长度范围是多少？
			</span>
			<span class="btn-box" @click="isShowAnswer23 = !isShowAnswer23">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			<p v-if="isShowAnswer23" >
			<span class="zt-ls"><b>解</b></span>
			设小花坛垂直于墙的一边的长度为<i>x</i>（m），则与墙平行的一边的长度为（8-2<i>x</i>）m.考虑到实际情况，有<i>x</i>＞0，并且8-2<i>x</i>＞0，所以<i>x</i>满足0＜<i>x</i>＜4.
			</p>
			@@ -2237,32 +2806,46 @@
			<li>上册</li>
			</ul>
			<div class="padding-116">
			<p>设小花坛的面积为<i>S</i>（m<sup>2</sup>），则</p>
			<p class="center"><i>S</i>=<i>x</i>（8-2<i>x</i>），</p>
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0067-1.jpg" /></p>
			<p class="img">图2-13</p>
			<p>整理得 <i>S</i>=-2<i>x</i><sup>2</sup>+8<i>x</i>.</p>
			<p>
			由题意得 <i>S</i>=-2<i>x</i><sup>2</sup>+8<i>x</i>≥6，即<i>x</i><sup>2</sup>-4<i>x</i>+3≤0.
			</p>
			<p>
			画出二次函数<i>y</i>=<i>x</i><sup>2</sup>-4<i>x</i>+3的简图（如图2-13所示）.
			</p>
			<p>由图像得不等式的解为{<i>x</i>\|1≤<i>x</i>≤3}.</p>
			<p>结合0＜<i>x</i>＜4，得</p>
			<p class="center">
			{<i>x</i>\|0＜<i>x</i>＜4}∩{<i>x</i>\|1≤<i>x</i>≤3}={<i>x</i>\|1≤<i>x</i>≤3}.
			</p>
			<p>所以小花坛垂直于墙的一边的长度在1m至3m之间（含1m和3m）.</p>
			<p>
			<span
			<div v-if="isShowAnswer23">
			<p>设小花坛的面积为<i>S</i>（m<sup>2</sup>），则</p>
			<p class="center"><i>S</i>=<i>x</i>（8-2<i>x</i>），</p>
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0067-1.jpg" /></p>
			<p class="img">图2-13</p>
			<p>整理得 <i>S</i>=-2<i>x</i><sup>2</sup>+8<i>x</i>.</p>
			<p>
			由题意得 <i>S</i>=-2<i>x</i><sup>2</sup>+8<i>x</i>≥6，即<i>x</i><sup>2</sup>-4<i>x</i>+3≤0.
			</p>
			<p>
			画出二次函数<i>y</i>=<i>x</i><sup>2</sup>-4<i>x</i>+3的简图（如图2-13所示）.
			</p>
			<p>由图像得不等式的解为{<i>x</i>\|1≤<i>x</i>≤3}.</p>
			<p>结合0＜<i>x</i>＜4，得</p>
			<p class="center">
			{<i>x</i>\|0＜<i>x</i>＜4}∩{<i>x</i>\|1≤<i>x</i>≤3}={<i>x</i>\|1≤<i>x</i>≤3}.
			</p>
			<p>所以小花坛垂直于墙的一边的长度在1m至3m之间（含1m和3m）.</p>
			</div>
			<p class="p-btn" >
			<span>
			<span
			class="zt-ls"><b>例2</b></span>　某网店销售一种电动玩具，成本为10元/个.平时按单价20元销售，日平均销售量为100个.为进一步提升业绩，该网店决定在“双11”期间举办降价促销活动.根据以往的统计，如果该电动玩具的单价每降低0.5元，日平均销售量就会大约增加10个.为了使促销活动期间日平均利润不低于平时，应如何确定降价的范围？
			</span>
			<span class="btn-box" @click="isShowAnswer24 = !isShowAnswer24">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			<span class="btn-box" @click="openDialog(thinkThree)">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.545" height="18.112" viewBox="0 0 20.545 22.112">
			<path class="a"
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			transform="translate(-3761 14334.001)" />
			</svg>
			</span>
			</p>
			<p class="block">
			<span
			class="zt-ls2"><b>分析</b></span>　利润=（销售单价-成本单价）×销售量.降价过程中，单价降低能够使销售量变大，但也使销售单价与成本单价的差减小，所以降价的范围应保证利润不低于促销前.
			</p>
			<div class="bk">
			<div class="bk mt-60" >
			<div class="bj1">
			<p class="left">
			<img class="img-gn1" alt="" src="../../assets/images/tbts.jpg" />
			@@ -2272,32 +2855,34 @@
			由例1和例2可知，在解决与一元二次不等式有关的实际问题时，不仅要解一元二次不等式，而且要考虑实际背景对未知数的限制.在例1中，实际背景对未知数的限制是0＜<i>x</i>＜4；在例2中，实际背景对未知数的限制是0＜<i>x</i>＜10.
			</p>
			</div>
			<p>
			<span class="zt-ls"><b>解</b></span>
			假设降价<i>x</i>元.考虑到实际情况，价格的降幅应小于10元，即保证销售价高于成本价，所以要求<i>x</i>＞0并且<i>x</i>＜10，即0＜<i>x</i>＜10.
			</p>
			<p>平时的日平均利润为（20-10）×100=1 000（元）.</p>
			<p>
			降价<i>x</i>元后，销售单价为（20-<i>x</i>）元，单个玩具的利润为（20-<i>x</i>）-10=（10-<i>x</i>）元，日平均销售量为<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mn>100</mn>
			<mo>+</mo>
			<mfrac>
			<mn>10</mn>
			<mn>0.5</mn>
			</mfrac>
			<mi>x</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>个.因此，降价<i>x</i>元后的日平均利润为（10-<i>x</i>）（100+20<i>x</i>）元.
			</p>
			<p>由题意得（10-<i>x</i>）（100+20<i>x</i>）≥1 000.</p>
			<p>化简得<i>x</i><sup>2</sup>-5<i>x</i>≤0，即<i>x</i>（<i>x</i>-5）≤0.</p>
			<p>所以不等式的解集为 {<i>x</i>\|0≤<i>x</i>≤5}.</p>
			<p>
			由于0＜<i>x</i>＜10，所以<i>x</i>的范围是{<i>x</i>\|0＜<i>x</i>＜10}∩{<i>x</i>\|0≤<i>x</i>≤5}，即{<i>x</i>\|0＜<i>x</i>≤5}.所以降价的范围应在0至5元之间（含5元，不含0元），即单价定在15元至20元之间（含15元，不含20元），便能满足要求.
			</p>
			<div v-if="isShowAnswer24">
			<p>
			<span class="zt-ls"><b>解</b></span>
			假设降价<i>x</i>元.考虑到实际情况，价格的降幅应小于10元，即保证销售价高于成本价，所以要求<i>x</i>＞0并且<i>x</i>＜10，即0＜<i>x</i>＜10.
			</p>
			<p>平时的日平均利润为（20-10）×100=1 000（元）.</p>
			<p>
			降价<i>x</i>元后，销售单价为（20-<i>x</i>）元，单个玩具的利润为（20-<i>x</i>）-10=（10-<i>x</i>）元，日平均销售量为<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mn>100</mn>
			<mo>+</mo>
			<mfrac>
			<mn>10</mn>
			<mn>0.5</mn>
			</mfrac>
			<mi>x</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>个.因此，降价<i>x</i>元后的日平均利润为（10-<i>x</i>）（100+20<i>x</i>）元.
			</p>
			<p>由题意得（10-<i>x</i>）（100+20<i>x</i>）≥1 000.</p>
			<p>化简得<i>x</i><sup>2</sup>-5<i>x</i>≤0，即<i>x</i>（<i>x</i>-5）≤0.</p>
			<p>所以不等式的解集为 {<i>x</i>\|0≤<i>x</i>≤5}.</p>
			<p>
			由于0＜<i>x</i>＜10，所以<i>x</i>的范围是{<i>x</i>\|0＜<i>x</i>＜10}∩{<i>x</i>\|0≤<i>x</i>≤5}，即{<i>x</i>\|0＜<i>x</i>≤5}.所以降价的范围应在0至5元之间（含5元，不含0元），即单价定在15元至20元之间（含15元，不含20元），便能满足要求.
			</p>
			</div>
			<div class="bk-hzjl">
			<div class="bj1-hzjl">
			<p class="left">
			@@ -2322,8 +2907,6 @@
			</li>
			</ul>
			<div class="padding-116">
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0068-1.jpg" /></p>
			<p class="img">第2题图</p>
			<p class="left"><img class="img-gn" alt="" src="../../assets/images/stlx.jpg" /></p>
			<div class="bj">
			<examinations :cardList="questionData[64]" :hideCollect="true" sourceType="json" v-if="questionData">
			@@ -2332,31 +2915,43 @@
			<h3 id="c024">
			2.5.2 不等式与复杂实际问题<span class="fontsz2">＞＞＞</span>
			</h3>
			<p>
			<span
			class="zt-ls"><b>例1</b></span>　我国交通法规对小型汽车驾驶员的年龄限制如下：最低年龄18周岁，最高年龄70周岁.已有研究表明，小型汽车驾驶员对红绿灯变化的反应时间<i>y</i>（ms）
			与驾驶员年龄<i>x</i>（周岁）
			的关系为<i>y</i>=0.005<i>x</i><sup>2</sup>-0.2<i>x</i>+22，其中18≤<i>x</i>≤70.问：反应时间超过24.5ms的驾驶员所处的年龄范围是多少？
			<p class="p-btn" >
			<span>
			<span
			class="zt-ls"><b>例1</b></span>　我国交通法规对小型汽车驾驶员的年龄限制如下：最低年龄18周岁，最高年龄70周岁.已有研究表明，小型汽车驾驶员对红绿灯变化的反应时间<i>y</i>（ms）
			与驾驶员年龄<i>x</i>（周岁）
			的关系为<i>y</i>=0.005<i>x</i><sup>2</sup>-0.2<i>x</i>+22，其中18≤<i>x</i>≤70.问：反应时间超过24.5ms的驾驶员所处的年龄范围是多少？
			</span>
			<span class="btn-box" @click="isShowAnswer25 = !isShowAnswer25">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span> 由题意得，<i>y</i>=0.005<i>x</i><sup>2</sup>-0.2<i>x</i>+22＞24.5，即
			</p>
			<p>　　　　　0.005<i>x</i><sup>2</sup>-0.2<i>x</i>-2.5＞0.</p>
			<p>化简得 <i>x</i><sup>2</sup>-40<i>x</i>-500＞0.</p>
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0068-2.jpg" /></p>
			<p class="img">图2-14</p>
			<p>
			考查二次函数<i>y</i>=<i>x</i><sup>2</sup>-40<i>x</i>-500，<i>a</i>=1＞0，<i>Δ</i>=<i>b</i><sup>2</sup>-4<i>ac</i>=（-40）<sup>2</sup>-4×1×（-500）=3
			600＞0，所以二次函数<i>y</i>=<i>x</i><sup>2</sup>-40<i>x</i>-500的图像开口向上，并且与<i>x</i>轴有两个交点.其简图如图2-14所示.
			</p>
			<p>
			由图像可知，不等式<i>x</i><sup>2</sup>-40<i>x</i>-500＞0的解集为（-∞，-10）∪（50，+∞），这也是不等式0.005<i>x</i><sup>2</sup>-0.2<i>x</i>-2.5＞0的解集.
			</p>
			<p>
			考虑到18≤<i>x</i>≤70，所以<i>x</i>的范围是（50，70］，即反应时间超过24.5
			<i>ms</i>
			的驾驶员所处的年龄范围在50岁至70岁之间（不包含50岁，包含70岁）.
			</p>
			<div v-if="isShowAnswer25" >
			<p>
			<span class="zt-ls"><b>解</b></span> 由题意得，<i>y</i>=0.005<i>x</i><sup>2</sup>-0.2<i>x</i>+22＞24.5，即
			</p>
			<p>　　　　　0.005<i>x</i><sup>2</sup>-0.2<i>x</i>-2.5＞0.</p>
			<p>化简得 <i>x</i><sup>2</sup>-40<i>x</i>-500＞0.</p>
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0068-2.jpg" /></p>
			<p class="img">图2-14</p>
			<p>
			考查二次函数<i>y</i>=<i>x</i><sup>2</sup>-40<i>x</i>-500，<i>a</i>=1＞0，<i>Δ</i>=<i>b</i><sup>2</sup>-4<i>ac</i>=（-40）<sup>2</sup>-4×1×（-500）=3
			600＞0，所以二次函数<i>y</i>=<i>x</i><sup>2</sup>-40<i>x</i>-500的图像开口向上，并且与<i>x</i>轴有两个交点.其简图如图2-14所示.
			</p>
			<p>
			由图像可知，不等式<i>x</i><sup>2</sup>-40<i>x</i>-500＞0的解集为（-∞，-10）∪（50，+∞），这也是不等式0.005<i>x</i><sup>2</sup>-0.2<i>x</i>-2.5＞0的解集.
			</p>
			<p>
			考虑到18≤<i>x</i>≤70，所以<i>x</i>的范围是（50，70］，即反应时间超过24.5
			<i>ms</i>
			的驾驶员所处的年龄范围在50岁至70岁之间（不包含50岁，包含70岁）.
			</p>
			</div>

			<p>
			<span class="zt-ls"><b>例2</b></span>　身体质量指数（Body Mass
			Index，BMI）是衡量人体胖瘦程度的一个常用标准，计算公式为<math display="0">
			@@ -2398,44 +2993,55 @@
			000m跑、女生800m跑），坐位体前屈等项目的成绩总和.身体素质指标为正数说明身体素质较好.上述研究发现，身体素质指标（<i>y</i>）与BMI（<i>x</i>）
			之间的关系如表2-7所示.
			</p>
			<p>问：身体素质较好的男生和女生，其BMI的范围分别是多少？</p>
			<p class="p-btn" >
			问：身体素质较好的男生和女生，其BMI的范围分别是多少？
			<span class="btn-box" @click="isShowAnswer26 = !isShowAnswer26">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p class="img">表2-7</p>
			<p class="center"><img class="img-a" alt="" src="../../assets/images/0069-1.jpg" /></p>
			<p>
			<span class="zt-ls"><b>解</b></span>
			先考虑男生的情况.由题意得，<i>y</i>=-0.05<i>x</i><sup>2</sup>+2<i>x</i>-19.2＞0，即
			</p>
			<p class="center">0.05<i>x</i><sup>2</sup>-2<i>x</i>+19.2＜0.</p>
			<p>化简得　<i>x</i><sup>2</sup>-40<i>x</i>+384＜0.</p>
			<p>
			考查二次函数<i>y</i>=<i>x</i><sup>2</sup>-40<i>x</i>+384，<i>a</i>=1＞0，<i>Δ</i>=<i>b</i><sup>2</sup>-4<i>ac</i>=40<sup>2</sup>-4×1×384=64＞0，所以二次函数<i>y</i>=<i>x</i><sup>2</sup>-40<i>x</i>+384的图像开口向上，与<i>x</i>轴有两个交点.
			</p>
			<p>
			所以不等式<i>x</i><sup>2</sup>-40<i>x</i>+384＜0的解集为（16，24），这也是不等式-0.05<i>x</i><sup>2</sup>+2<i>x</i>-19.2＞0的解集.
			</p>
			<p>
			再考虑女生的情况.由题意得，<i>y</i>=-0.01<i>x</i><sup>2</sup>+0.39<i>x</i>-3.68＞0，即
			</p>
			<p class="center">0.01<i>x</i><sup>2</sup>-0.39<i>x</i>+3.68＜0.</p>
			<p>化简得　<i>x</i><sup>2</sup>-39<i>x</i>+368＜0.</p>
			<p>
			考查二次函数<i>y</i>=<i>x</i><sup>2</sup>-39<i>x</i>+368，<i>a</i>=1＞0，<i>Δ</i>=<i>b</i><sup>2</sup>-4<i>ac</i>=（-39）<sup>2</sup>-4×1×368=49＞0，所以二次函数<i>y</i>=<i>x</i><sup>2</sup>-39<i>x</i>+368的图像开口向上，与<i>x</i>轴有两个交点.
			</p>
			<p>
			所以不等式<i>x</i><sup>2</sup>-39<i>x</i>+368＜0的解集为（16，23），这也是不等式-0.01<i>x</i><sup>2</sup>+0.39<i>x</i>-3.68＞0的解集.
			</p>
			<p>
			因此，身体素质较好的男生BMI 的范围是（16，24），身体素质较好的女生BMI
			的范围是（16，23）.
			</p>
			<div v-if="isShowAnswer26" >
			<p>
			<span class="zt-ls"><b>解</b></span>
			先考虑男生的情况.由题意得，<i>y</i>=-0.05<i>x</i><sup>2</sup>+2<i>x</i>-19.2＞0，即
			</p>
			<p class="center">0.05<i>x</i><sup>2</sup>-2<i>x</i>+19.2＜0.</p>
			<p>化简得　<i>x</i><sup>2</sup>-40<i>x</i>+384＜0.</p>
			<p>
			考查二次函数<i>y</i>=<i>x</i><sup>2</sup>-40<i>x</i>+384，<i>a</i>=1＞0，<i>Δ</i>=<i>b</i><sup>2</sup>-4<i>ac</i>=40<sup>2</sup>-4×1×384=64＞0，所以二次函数<i>y</i>=<i>x</i><sup>2</sup>-40<i>x</i>+384的图像开口向上，与<i>x</i>轴有两个交点.
			</p>
			<p>
			所以不等式<i>x</i><sup>2</sup>-40<i>x</i>+384＜0的解集为（16，24），这也是不等式-0.05<i>x</i><sup>2</sup>+2<i>x</i>-19.2＞0的解集.
			</p>
			<p>
			再考虑女生的情况.由题意得，<i>y</i>=-0.01<i>x</i><sup>2</sup>+0.39<i>x</i>-3.68＞0，即
			</p>
			<p class="center">0.01<i>x</i><sup>2</sup>-0.39<i>x</i>+3.68＜0.</p>
			<p>化简得　<i>x</i><sup>2</sup>-39<i>x</i>+368＜0.</p>
			<p>
			考查二次函数<i>y</i>=<i>x</i><sup>2</sup>-39<i>x</i>+368，<i>a</i>=1＞0，<i>Δ</i>=<i>b</i><sup>2</sup>-4<i>ac</i>=（-39）<sup>2</sup>-4×1×368=49＞0，所以二次函数<i>y</i>=<i>x</i><sup>2</sup>-39<i>x</i>+368的图像开口向上，与<i>x</i>轴有两个交点.
			</p>
			<p>
			所以不等式<i>x</i><sup>2</sup>-39<i>x</i>+368＜0的解集为（16，23），这也是不等式-0.01<i>x</i><sup>2</sup>+0.39<i>x</i>-3.68＞0的解集.
			</p>
			<p>
			因此，身体素质较好的男生BMI 的范围是（16，24），身体素质较好的女生BMI
			的范围是（16，23）.
			</p>
			</div>
			<div class="bk-hzjl">
			<div class="bj1-hzjl">
			<p class="left">
			<img class="img-gn2" alt="" src="../../assets/images/hzjl.jpg" />
			</p>
			</div>
			<examinations :cardList="questionData[65]" :hideCollect="true" sourceType="json"
			v-if="questionData" ></examinations>
			<examinations :cardList="questionData[65]" :hideCollect="true" sourceType="json" v-if="questionData">
			</examinations>
			</div>
			</div>
			</div>
			@@ -2456,12 +3062,13 @@
			<img class="img-gn" alt="" src="../../assets/images/stlx.jpg" />
			</p>
			<div class="bj">
			<examinations :cardList="questionData[66] ? questionData[66][1] : []" :hideCollect="true" sourceType="json" inputBc="#d3edfa"
			v-if="questionData"></examinations>
			<examinations :cardList="questionData[66] ? questionData[66][1] : []" :hideCollect="true" sourceType="json"
			inputBc="#d3edfa" v-if="questionData"></examinations>
			</div>
			<h3 id="c025">习题2.5<span class="fontsz2">＞＞＞</span></h3>
			<div class="bj">
			<examinations :cardList="questionData[66] ? questionData[66][2] : []" :hideCollect="true" sourceType="json" v-if="questionData">
			<examinations :cardList="questionData[66] ? questionData[66][2] : []" :hideCollect="true" sourceType="json"
			v-if="questionData">
			</examinations>
			</div>
			</div>
			@@ -2994,10 +3601,67 @@
			<!-- 066 -->
			<div class="page-box hidePage" page="73">
			</div>
			<!-- 解题思路弹窗 -->
			<el-dialog :visible.sync="thinkingDialog" width="40%" :append-to-body="true" :show-close="false"
			@close="closeDialog" class="thinkDialog">
			<div slot="title" class="think-header"
			style="padding: 0; text-align: center; color: #333;display:flex;justify-content: center;">
			<span style=""> 分析 </span>
			<svg style="position: absolute; right:10px;cursor: pointer;" @click="thinkingDialog = false" t="1718596022986"
			class="icon" viewBox="0 0 1024 1024" version="1.1" xmlns="http://www.w3.org/2000/svg" p-id="4252" width="20"
			height="20" xmlns:xlink="http://www.w3.org/1999/xlink">
			<path
			d="M176.661601 817.172881C168.472798 825.644055 168.701706 839.149636 177.172881 847.338438 185.644056 855.527241 199.149636 855.298332 207.338438 846.827157L826.005105 206.827157C834.193907 198.355983 833.964998 184.850403 825.493824 176.661601 817.02265 168.472798 803.517069 168.701706 795.328267 177.172881L176.661601 817.172881Z"
			fill="#979797" p-id="4253"></path>
			<path
			d="M795.328267 846.827157C803.517069 855.298332 817.02265 855.527241 825.493824 847.338438 833.964998 839.149636 834.193907 825.644055 826.005105 817.172881L207.338438 177.172881C199.149636 168.701706 185.644056 168.472798 177.172881 176.661601 168.701706 184.850403 168.472798 198.355983 176.661601 206.827157L795.328267 846.827157Z"
			fill="#979797" p-id="4254"></path>
			</svg>
			</div>
			<ul>
			<li v-for="(item, index) in thinkData" :key="index">
			<div v-if="index <= showIndex" style="display: flex">
			<span style="position: relative">
			<span style="position: absolute; top: 16px; left: 13px; color: #fff">{{ index + 1 }}</span>
			<img src="../../assets/images/icon/blue-group.png" alt="" style="margin-right: 10px"
			v-if="index < thinkOne.length - 1" />
			<img src="../../assets/images/icon/blue.png" alt="" v-if="index == thinkOne.length - 1"
			style="margin-right: 10px" />
			</span>
			<p class="txt-p" v-html="item"></p>
			</div>
			</li>
			</ul>
			<div @click="changeNext" style="
			display: flex;
			flex-direction: column;
			align-items: center;
			justify-content: center;
			">
			<img src="../../assets/images/icon/mouse.png" alt="" v-if="showIndex < thinkData.length - 1" />
			<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" t="1710234570135"
			class="icon" viewBox="0 0 1024 1024" version="1.1" p-id="5067" width="15" height="15">
			<path
			d="M2.257993 493.371555 415.470783 906.584344 512 1003.113561 608.529217 906.584344 1021.742007 493.371555 925.212789 396.842337 512 810.055127 98.787211 396.842337Z"
			fill="#1296db" p-id="5068" />
			<path
			d="M2.257993 117.980154 415.470783 531.192944 512 627.722161 608.529217 531.192944 1021.742007 117.980154 925.212789 21.450937 512 434.663727 98.787211 21.450937Z"
			fill="#1296db" p-id="5069" />
			</svg>
			</div>
			</el-dialog>
			</div>
			</template>

			<script>
			const handleShow = (num) => {
			const obj = {}
			for (let index = 0; index < num; index++) {
			obj['isShowAnswer' + index] = false
			}
			return obj
			}
			const showObj = handleShow(30)
			import paint from '@/components/paint/index.vue'
			import examinations from '@/components/examinations/index.vue'
			export default {
			@@ -3011,14 +3675,47 @@
			type: Object,
			},
			},
			components: { examinations,paint },
			components: { examinations, paint },
			data() {
			return {
			isShowAnswer:false
			collectImg: require('../../assets/images/icon/heart.png'),
			collectCheck: require('../../assets/images/icon/heart-check.png'),
			thinkingDialog: false,
			showIndex: 0,
			thinkData: [],
			thinkOne: [
			'①根据<i>x</i><sup>2</sup>的系数判断函数图像（抛物线）的开口方向；',
			'②用判别式判定出一元二次方程<i>x</i><sup>2</sup>-2<i>x</i>-3=0的解的情况，从而确定二次函数<i>y</i>=<i>x</i><sup>2</sup>-2<i>x</i>-3的图像与<i>x</i>轴的交点个数和交点坐标；',
			'③计算二次函数图像的顶点坐标、与<i>y</i>轴的交点坐标；',
			'④求出二次函数图像的对称轴方程，并利用函数图像的对称性再找出一些点；⑤最后根据上述信息画出函数图像.',
			'画出图像后，<i>y</i>=0，<i>y</i>＞0，<i>y</i>＜0分别对应函数图像与<i>x</i>轴相交、函数图像在<i>x</i>轴上方、函数图像在<i>x</i>轴下方三种情形，根据图像完成（2）（3）两个问题.'
			],
			thinkTwo:[
			'由（<i>x</i>+1）<sup>2</sup>≥4得<i>x</i><sup>2</sup>+2<i>x</i>+1≥4，即<i>x</i><sup>2</sup>+2<i>x</i>-3≥0，从而可以利用二次函数<i>y</i>=<i>x</i><sup>2</sup>+2<i>x</i>-3的图像进行求解；注意到4=2<sup>2</sup>，也可以考虑将（<i>x</i>+1）<sup>2</sup>≥4整理为（<i>x</i>+1）<sup>2</sup>-4≥0，并使用平方差公式，即（<i>x</i>+1）<sup>2</sup>-2<sup>2</sup>≥0，得到（<i>x</i>+3）（<i>x</i>-1）≥0，此时可以借助上面的结论直接求解.下面我们将使用后一种方法进行求解.'
			],
			thinkThree:[
			'利润=（销售单价-成本单价）×销售量.降价过程中，单价降低能够使销售量变大，但也使销售单价与成本单价的差减小，所以降价的范围应保证利润不低于促销前.'
			],
			isShowAnswer: false,
			isShowAnswerOne: false,
			...showObj
			};
			},
			mounted() { },
			methods: {},
			mounted() {
			console.log(2, this);
			},
			methods: {
			openDialog(queryData) {
			this.thinkData = queryData
			this.thinkingDialog = !this.thinkingDialog
			},
			closeDialog() {
			this.showIndex = 0
			},
			changeNext() {
			if (this.showIndex < this.thinkData.length - 1) this.showIndex = this.showIndex + 1
			}
			},
			};
			</script>

			@@ -3033,15 +3730,21 @@
			top: 0;
			width: 140px;
			}

			.question-textarea {
			margin-left: 20px;
			width: 94%;
			border-color:#DCDFE6;
			border-color: #DCDFE6;
			}

			.table-answer-box {
			math {
			width: max-content;
			height: 36px;
			}
			}

			li {
			list-style: none;
			}
			</style>