testbookLayout.git

			@@ -1,5 +1,5 @@
			<template>
			<div class="chapter" num="2">
			<div class="chapter" num="3">
			<!-- 第二单元首页 -->
			<div class="page-box" page="38">
			<div v-if="showPageList.indexOf(38) > -1">
			@@ -67,7 +67,6 @@
			</div>
			</div>
			</div>

			<!-- 033 -->
			<div class="page-box" page="40">
			<div v-if="showPageList.indexOf(40) > -1">
			@@ -226,7 +225,6 @@
			</div>
			</div>
			</div>

			<!-- 034 -->
			<div class="page-box" page="41">
			<div v-if="showPageList.indexOf(41) > -1">
			@@ -270,32 +268,76 @@
			<img class="img-gn2" alt="" src="../../assets/images/hzjl.jpg" />
			</p>
			</div>
			<p class="block">请你自己尝试证明推论2和推论3，并与同学进行交流讨论.</p>
			<examinations :cardList="questionData[41]" sourceType="json" inputBc="#d3edfa"
			v-if="questionData"></examinations>
			</div>
			<p>
			<span class="zt-ls"><b>例1</b></span>　已知<i>a</i>＞<i>b</i>＞0.
			</p>
			<p>（1）比较2<i>a</i>与2<i>b</i>的大小；</p>
			<p>（2）比较-2<i>a</i>与-2<i>b</i>的大小；</p>
			<p>（3）比较<i>ac</i>与<i>bc</i>的大小.</p>
			<p>
			<p class="p-btn">
			（1）比较2a与2b的大小；
			<span class="btn-box" @click="isShowAnswer0 = !isShowAnswer0">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p v-if="isShowAnswer0">
			<span class="zt-ls"><b>解</b></span>（1）因为<i>a</i>＞<i>b</i>，2＞0，根据性质2，有2<i>a</i>＞2<i>b</i>.
			</p>
			<p>
			<p class="p-btn">
			（2）比较-2a与-2b的大小；
			<span class="btn-box" @click="isShowAnswer1 = !isShowAnswer1">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p v-if="isShowAnswer1">
			<span class="zt-ls"><b>解</b></span>
			（2）
			因为<i>a</i>＞<i>b</i>，-2＜0，根据性质3，有-2<i>a</i>＜-2<i>b</i>.
			</p>
			<p>（3）若<i>c</i>＞0，根据性质2，有<i>ac</i>＞<i>bc</i>.</p>
			<p>若<i>c</i>＜0，根据性质3，有<i>ac</i>＜<i>bc</i>.</p>
			<p>若<i>c</i>=0，则有<i>ac</i>=<i>bc</i>=0，所以<i>ac</i>=<i>bc</i>.</p>
			<p>
			<span class="zt-ls"><b>例2</b></span>　已知<i>a</i>＞<i>b</i>，比较<i>a</i>-1与<i>b</i>-2的大小.
			<p class="p-btn">
			（3）比较ac与bc的大小.
			<span class="btn-box" @click="isShowAnswer2 = !isShowAnswer2">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span> 因为<i>a</i>＞<i>b</i>，-1＞-2，
			<div v-if="isShowAnswer2">
			<p>
			<span class="zt-ls"><b>解</b></span>
			（3）若<i>c</i>＞0，根据性质2，有<i>ac</i>＞<i>bc</i>.
			</p>
			<p>若<i>c</i>＜0，根据性质3，有<i>ac</i>＜<i>bc</i>.</p>
			<p>若<i>c</i>=0，则有<i>ac</i>=<i>bc</i>=0，所以<i>ac</i>=<i>bc</i>.</p>
			</div>
			<p class="p-btn">
			<span class="zt-ls"><b>例2</b></span>
			<span class="t1">已知a＞b，比较a-1与b-2的大小.</span>
			<span class="btn-box" @click="isShowAnswer3 = !isShowAnswer3">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>根据推论1，有<i>a</i>+（-1）＞<i>b</i>+（-2），</p>
			<p>即<i>a</i>-1＞<i>b</i>-2.</p>
			<div v-if="isShowAnswer3">
			<p>
			<span class="zt-ls"><b>解</b></span> 因为<i>a</i>＞<i>b</i>，-1＞-2，
			</p>
			<p>根据推论1，有<i>a</i>+（-1）＞<i>b</i>+（-2），</p>
			<p>即<i>a</i>-1＞<i>b</i>-2.</p>
			</div>
			</div>
			</div>
			</div>
			@@ -313,24 +355,8 @@
			<div class="padding-116">
			<p class="left"><img class="img-gn" alt="" src="../../assets/images/stlx.jpg" /></p>
			<div class="bj">
			<p>1.用“＞”或“＜”填空.</p>
			<p>
			（1） <i>a</i>+5___<i>b</i>+5（<i>a</i>＜<i>b</i>）；（2）
			<i>x</i>+5___<i>x</i>+2；
			</p>
			<p>
			（3） m+1___<i>m</i>-1；（4）
			-5<i>p</i>___-5<i>q</i>（<i>p</i>＜<i>q</i>）.
			</p>
			<p>2.用“＞”或“＜”填空.</p>
			<p>
			（1）若4<i>x</i>＜2，则<i>x</i>___<math display="0">
			<mfrac>
			<mn>1</mn>
			<mn>2</mn>
			</mfrac>
			</math>；（2）若<i>a</i>＜0，则2<i>a</i>___<i>a</i>.
			</p>
			<examinations :cardList="questionData[42]" sourceType="json" inputBc="#d3edfa"
			v-if="questionData"></examinations>
			</div>
			<h3 id="c013">2.1.2 作差比较法<span class="fontsz2">＞＞＞</span></h3>
			<p class="left"><img class="img-gn" alt="" src="../../assets/images/fxlj.jpg" /></p>
			@@ -349,100 +375,110 @@
			<p>
			因为（<i>a</i><sup>2</sup>+1）-2<i>a</i>=<i>a</i><sup>2</sup>-2<i>a</i>+1=（<i>a</i>-1）<sup>2</sup>，且当<i>a</i>≠1时，（<i>a</i>-1）<sup>2</sup>＞0，所以<i>a</i><sup>2</sup>+1＞2<i>a</i>.
			</p>
			<p>
			<span class="zt-ls"><b>例1</b></span>　分析本节“问题提出”中的问题.
			<p class="p-btn">
			<span class="zt-ls"><b>例1</b></span>
			<span class="t1">分析本节“问题提出”中的问题.</span>
			<span class="btn-box" @click="isShowAnswer4 = !isShowAnswer4">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span> 作差可得<math display="0">
			<mfrac>
			<mn>98</mn>
			<mn>166</mn>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mrow>
			<div v-if="isShowAnswer4">
			<p>
			<span class="zt-ls"><b>解</b></span> 作差可得<math display="0">
			<mfrac>
			<mn>98</mn>
			<mo>+</mo>
			<mn>8</mn>
			</mrow>
			<mrow>
			<mn>166</mn>
			<mo>+</mo>
			<mn>8</mn>
			</mrow>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mn>98</mn>
			<mn>166</mn>
			</mfrac>
			<mo>−</mo>
			<mfrac>
			<mn>106</mn>
			<mn>174</mn>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mrow>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mrow>
			<mn>98</mn>
			<mo>+</mo>
			<mn>8</mn>
			</mrow>
			<mrow>
			<mn>166</mn>
			<mo>+</mo>
			<mn>8</mn>
			</mrow>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mn>98</mn>
			<mo>×</mo>
			<mn>174</mn>
			<mo>−</mo>
			<mn>166</mn>
			</mfrac>
			<mo>−</mo>
			<mfrac>
			<mn>106</mn>
			<mo>×</mo>
			<mn>166</mn>
			</mrow>
			<mrow>
			<mn>166</mn>
			<mo>×</mo>
			<mn>174</mn>
			</mrow>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mrow>
			<mo>−</mo>
			<mn>544</mn>
			</mrow>
			<mrow>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mrow>
			<mn>98</mn>
			<mo>×</mo>
			<mn>174</mn>
			<mo>−</mo>
			<mn>106</mn>
			<mo>×</mo>
			<mn>166</mn>
			</mrow>
			<mrow>
			<mn>166</mn>
			<mo>×</mo>
			<mn>174</mn>
			</mrow>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mrow>
			<mo>−</mo>
			<mn>544</mn>
			</mrow>
			<mrow>
			<mn>166</mn>
			<mo>×</mo>
			<mn>174</mn>
			</mrow>
			</mfrac>
			<mo>＜</mo>
			<mn>0</mn>
			</math>，所以<math display="0">
			<mfrac>
			<mn>98</mn>
			<mn>166</mn>
			<mo>×</mo>
			</mfrac>
			<mo>＜</mo>
			<mfrac>
			<mn>106</mn>
			<mn>174</mn>
			</mrow>
			</mfrac>
			<mo>＜</mo>
			<mn>0</mn>
			</math>，所以<math display="0">
			<mfrac>
			<mn>98</mn>
			<mn>166</mn>
			</mfrac>
			<mo>＜</mo>
			<mfrac>
			<mn>106</mn>
			<mn>174</mn>
			</mfrac>
			</math>.
			</p>
			<p>
			又因为<math display="0">
			<mfrac>
			<mn>98</mn>
			<mn>166</mn>
			</mfrac>
			<mo>≈</mo>
			<mn>0.590</mn>
			<mn>4</mn>
			</math>，<math display="0">
			<mfrac>
			<mn>106</mn>
			<mn>174</mn>
			</mfrac>
			<mo>≈</mo>
			<mn>0.690</mn>
			<mn>2</mn>
			</math>，所以立起脚尖后，该芭蕾舞演员的下半身长与全身长的比值更接近0.618.
			</p>
			</mfrac>
			</math>.
			</p>
			<p>
			又因为<math display="0">
			<mfrac>
			<mn>98</mn>
			<mn>166</mn>
			</mfrac>
			<mo>≈</mo>
			<mn>0.590</mn>
			<mn>4</mn>
			</math>，<math display="0">
			<mfrac>
			<mn>106</mn>
			<mn>174</mn>
			</mfrac>
			<mo>≈</mo>
			<mn>0.690</mn>
			<mn>2</mn>
			</math>，所以立起脚尖后，该芭蕾舞演员的下半身长与全身长的比值更接近0.618.
			</p>
			</div>
			<div class="bk">
			<div class="bj1">
			<p class="left">
			@@ -538,9 +574,10 @@
			</math>.
			</p>
			</div>

			<p>
			<span class="zt-ls"><b>例2</b></span>　已知<i>b</i>＞<i>a</i>＞0，<i>c</i>＞0，比较<math display="0">
			<p class="p-btn">
			<span class="zt-ls"><b>例2</b></span>
			<span calss="t1">已知b＞a＞0，c＞0，比较</span>
			<math display="0">
			<mfrac>
			<mrow>
			<mi>a</mi>
			@@ -559,174 +596,155 @@
			<mi>b</mi>
			</mfrac>
			</math>的大小.
			<span class="btn-box" @click="isShowAnswer5 = !isShowAnswer5">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span> 作差可得<math display="0">
			<mfrac>
			<mrow>
			<mi>a</mi>
			<mo>+</mo>
			<mi>c</mi>
			</mrow>
			<mrow>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			</mrow>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mi>a</mi>
			<mi>b</mi>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<div v-if="isShowAnswer5">
			<p>
			<span class="zt-ls"><b>解</b></span> 作差可得<math display="0">
			<mfrac>
			<mrow>
			<mi>a</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mi>b</mi>
			</mrow>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mrow>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mi>b</mi>
			</mrow>
			</mfrac>
			<mo>−</mo>
			<mfrac>
			<mrow>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mi>a</mi>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</mrow>
			<mrow>
			<mi>b</mi>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mi>a</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</mrow>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mi>b</mi>
			<mo>−</mo>
			</mrow>
			</mfrac>
			<mo>−</mo>
			<mfrac>
			<mrow>
			<mi>a</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</mrow>
			<mi>c</mi>
			</mrow>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mrow>
			<mi>b</mi>
			<mo>+</mo>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</mrow>
			</mfrac>
			<mo>=</mo>
			<mfrac>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mi>b</mi>
			<mo>−</mo>
			<mi>a</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mi>b</mi>
			</mrow>
			</mfrac>
			</math>.
			</p>
			<p>
			因为<i>b</i>＞<i>a</i>＞0，所以<i>b</i>-<i>a</i>＞0.又因为<i>c</i>＞0，所以<math display="0">
			<mfrac>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mi>b</mi>
			<mo>−</mo>
			</mrow>
			</mfrac>
			</math>.
			</p>
			<p>
			因为<i>b</i>＞<i>a</i>＞0，所以<i>b</i>-<i>a</i>＞0.又因为<i>c</i>＞0，所以<math display="0">
			<mfrac>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mi>b</mi>
			<mo>−</mo>
			<mi>a</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mi>c</mi>
			</mrow>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mi>b</mi>
			</mrow>
			</mfrac>
			<mo>＞</mo>
			<mn>0</mn>
			</math>，
			</p>
			<p>
			即<math display="0">
			<mfrac>
			<mrow>
			<mi>a</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			<mo>+</mo>
			<mi>c</mi>
			</mrow>
			<mi>c</mi>
			</mrow>
			<mrow>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mrow>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mi>b</mi>
			</mrow>
			</mfrac>
			<mo>＞</mo>
			<mn>0</mn>
			</math>，
			</p>
			<p>
			即<math display="0">
			<mfrac>
			<mrow>
			</mfrac>
			<mo>−</mo>
			<mfrac>
			<mi>a</mi>
			<mo>+</mo>
			<mi>c</mi>
			</mrow>
			<mrow>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			</mrow>
			</mfrac>
			<mo>−</mo>
			<mfrac>
			<mi>a</mi>
			<mi>b</mi>
			</mfrac>
			<mo>＞</mo>
			<mn>0</mn>
			</math>，所以<math display="0">
			<mfrac>
			<mrow>
			<mi>a</mi>
			<mo>+</mo>
			<mi>c</mi>
			</mrow>
			<mrow>
			<mi>b</mi>
			<mo>+</mo>
			<mi>c</mi>
			</mrow>
			</mfrac>
			<mo>＞</mo>
			<mfrac>
			<mi>a</mi>
			<mi>b</mi>
			</mfrac>
			</math>.
			</p>
			<div class="bk-hzjl">
			<div class="bj1-hzjl">
			<p class="left">
			<img class="img-gn2" alt="" src="../../assets/images/hzjl.jpg" />
			</p>
			</div>
			<p class="block">
			1.例2中，如果<i>a</i>，<i>b</i>，<i>c</i>是任意不等于0的数，能否得出<math display="0">
			</mfrac>
			<mo>＞</mo>
			<mn>0</mn>
			</math>，所以<math display="0">
			<mfrac>
			<mrow>
			<mi>a</mi>
			@@ -744,68 +762,23 @@
			<mi>a</mi>
			<mi>b</mi>
			</mfrac>
			</math>的结论？如果能，请写出证明过程；如果不能，请举出反例.
			</math>.
			</p>
			<p class="block">
			2.本单元开篇的实例中，设窗户的有效透光面积为<i>a</i>，室内地面面积为<i>b</i>.若<i>a</i>，<i>b</i>同时增加<i>m</i>，能保证<math display="0">
			<mfrac>
			<mrow>
			<mi>a</mi>
			<mo>+</mo>
			<mi>m</mi>
			</mrow>
			<mrow>
			<mi>b</mi>
			<mo>+</mo>
			<mi>m</mi>
			</mrow>
			</mfrac>
			<mo>≥</mo>
			<mfrac>
			<mi>a</mi>
			<mi>b</mi>
			</mfrac>
			</math>吗？你能证明吗？
			</p>
			</div>
			<div class="bk-hzjl">
			<div class="bj1-hzjl">
			<p class="left">
			<img class="img-gn2" alt="" src="../../assets/images/hzjl.jpg" />
			</p>
			</div>
			<examinations :cardList="questionData[43] ? questionData[43][1] : []" sourceType="json"
			v-if="questionData">
			</examinations>
			</div>
			<p class="left"><img class="img-gn" alt="" src="../../assets/images/stlx.jpg" /></p>
			<div class="bj">
			<p>1.比较下列一组数的大小.</p>
			<p>
			<math display="0">
			<mfrac>
			<mn>9</mn>
			<mn>8</mn>
			</mfrac>
			</math>，-3，<math display="0">
			<mfrac>
			<mn>10</mn>
			<mn>9</mn>
			</mfrac>
			</math>，-π.
			</p>
			<p>2.用“＞”或“＜”填空.</p>
			<p>
			（1） <i>a</i>-1__<i>a</i>+1；（2）若<i>a</i>＞<i>b</i>＞0，则<math display="0">
			<mfrac>
			<mn>3</mn>
			<mi>a</mi>
			</mfrac>
			</math>__<math display="0">
			<mfrac>
			<mn>3</mn>
			<mi>b</mi>
			</mfrac>
			</math>.
			</p>
			<p>
			3.比较<i>x</i><sup>2</sup>-<i>x</i>与（<i>x</i>+1）（<i>x</i>-2）
			的大小.
			</p>
			<p>
			4.我们知道，如果在一杯糖水中继续加入一些糖，那么待糖全部溶解后，
			这杯糖水就会变得更甜.你能借助不等式的知识来解释其中的道理吗？
			</p>
			<examinations :cardList="questionData[43] ? questionData[43][2] : []" sourceType="json"
			inputBc="#d3edfa" v-if="questionData"></examinations>
			</div>
			</div>
			</div>
			@@ -823,104 +796,10 @@
			</ul>
			<div class="padding-116">
			<h3 id="c014">习题2.1<span class="fontsz2">＞＞＞</span></h3>
			<p>
			<span class="bj-sp"><b>水平一</b></span>
			</p>
			<p>1.比较下列各组数的大小.</p>
			<p>
			（1）
			<math display="0">
			<mo>−</mo>
			<mfrac>
			<mn>5</mn>
			<mn>6</mn>
			</mfrac>
			</math>与<math display="0">
			<mo>−</mo>
			<mfrac>
			<mn>4</mn>
			<mn>5</mn>
			</mfrac>
			</math>；（2）
			<math display="0">
			<mfrac>
			<mn>90</mn>
			<mn>165</mn>
			</mfrac>
			</math>与<math display="0">
			<mfrac>
			<mn>98</mn>
			<mn>173</mn>
			</mfrac>
			</math>.
			</p>
			<p>
			2.设<math display="0">
			<mi>a</mi>
			<mo>=</mo>
			<mfrac>
			<mn>7</mn>
			<mn>2</mn>
			</mfrac>
			</math>，<i>b</i>=3，<i>c</i>=2，比较下列一组数的大小，并在数轴上排列出来：<i>ab</i>，<i>bc</i>，<i>ca</i>，<i>a</i><sup>2</sup>，<i>b</i><sup>2</sup>，<i>c</i><sup>2</sup>.
			</p>
			<p>
			3.比较（<i>x</i>+1）（<i>x</i>+5）与（<i>x</i>+3）<sup>2</sup>的大小.
			</p>
			<p>4.比较<i>x</i><sup>2</sup>-2<i>x</i>与-5的大小.</p>
			<p>5.比较3<i>a</i>与2<i>a</i>+1的大小.</p>
			<p>
			<span class="bj-sp"><b>水平二</b></span>
			</p>
			<p>
			1.若<i>a</i>＞<i>b</i>，<i>c</i>＞<i>d</i>，则下列不等关系中<span class="u">不一定</span>成立的是（　）.
			</p>
			<p>
			<i>A</i>.<i>a</i>-<i>b</i>＞<i>d</i>-<i>c B</i>.<i>a</i>+<i>d</i>＞<i>b</i>+<i>c
			C</i>.<i>a</i>-<i>c</i>＞<i>b</i>-<i>c D</i>.<i>a</i>-<i>c</i>＜<i>a</i>-<i>d</i>
			</p>
			<p>2.比较<i>a</i>（<i>a</i>-2）+1与（<i>a</i>+1）<sup>2</sup>的大小.</p>
			<p>3.分别举一个反例，说明下列推理不正确.</p>
			<p>
			（1） <i>ac</i>＞<i>bc</i>⇒<i>a</i>＞<i>b</i>；（2）
			<math display="0">
			<mfrac>
			<mi>a</mi>
			<mi>c</mi>
			</mfrac>
			<mo>＞</mo>
			<mfrac>
			<mi>b</mi>
			<mi>c</mi>
			</mfrac>
			<mo stretchy="false">⇒</mo>
			<mi>a</mi>
			<mo>＞</mo>
			<mi>b</mi>
			</math>.
			</p>
			<p>
			4.已知<i>a</i>＞<i>b</i>＞<i>c</i>＞<i>d</i>，比较<math display="0">
			<mfrac>
			<mn>1</mn>
			<mrow>
			<mi>a</mi>
			<mo>−</mo>
			<mi>d</mi>
			</mrow>
			</mfrac>
			</math>与<math display="0">
			<mfrac>
			<mn>1</mn>
			<mrow>
			<mi>b</mi>
			<mo>−</mo>
			<mi>c</mi>
			</mrow>
			</mfrac>
			</math>的大小.
			</p>
			<p>5.比较<i>a</i><sup>2</sup>+<i>a</i>与2<i>a</i>-1的大小.</p>
			<div class="bj">
			<examinations :cardList="questionData[44]" sourceType="json" inputBc="#d3edfa"
			v-if="questionData"></examinations>
			</div>
			<h2 id="b008">2.2 区间<span class="fontsz1">＞＞＞＞＞＞＞＞</span></h2>
			<div class="bk">
			<div class="bj1">
			@@ -987,7 +866,7 @@
			<p>第二单元不等式</p>
			</li>
			<li>
			<p><span>039</span></p>
			<p><span>039-041</span></p>
			</li>
			</ul>
			<div class="padding-116">
			@@ -1001,8 +880,16 @@
			区间也是一个集合，它是实数集的一个子集.但并非所有的数集都能用区间表示.例如，集合{1，3，4，5，7，8，11，12}、自然数集<b>N</b>、整数集<b>Z</b>就不能用区间表示.
			</p>
			</div>
			<p>
			<span class="zt-ls"><b>例1</b></span>　把下列集合用区间表示出来，并指出区间的类型.
			<p class="p-btn">
			<span class="zt-ls"><b>例1</b></span>
			<span class="t1">把下列集合用区间表示出来，并指出区间的类型.</span>
			<span class="btn-box" @click="isShowAnswer6 = !isShowAnswer6">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>（1） {<i>x</i>\|-3≤<i>x</i>≤1}；（2） {<i>x</i>\|-1＜<i>x</i>＜2}；</p>
			<p>
			@@ -1047,206 +934,125 @@
			</math>；
			</p>
			<p>（5） {<i>x</i>\|<i>x</i>≥2}；（6） {<i>x</i>\|<i>x</i>＜1}.</p>
			<p>
			<span class="zt-ls"><b>解</b></span>（1）［-3，1］，是闭区间；
			</p>
			<p>（2）（-1，2），是开区间；</p>
			<p>
			（3）
			<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">[</mo>
			<mfrac>
			<mn>3</mn>
			<mn>2</mn>
			</mfrac>
			<mo>，</mo>
			<mn>4</mn>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>，是左闭右开区间；
			</p>
			<p>
			（4）
			<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mo>−</mo>
			<mn>6</mn>
			<mo>，</mo>
			<mo>−</mo>
			<mfrac>
			<mn>1</mn>
			<mn>2</mn>
			</mfrac>
			<mo data-mjx-texclass="CLOSE">]</mo>
			</mrow>
			</math>，是左开右闭区间；
			</p>
			<p>（5）［2，+∞），是左闭右开区间；</p>
			<p>（6）（-∞，1），是开区间.</p>
			<p>
			<span class="zt-ls"><b>例2</b></span>　用区间表示不等式3<i>x</i>＜9<i>x</i>+4的解集，并在数轴上表示出来.
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span> 解不等式3<i>x</i>＜9<i>x</i>+4，得
			</p>
			<math display="block">
			<mi>x</mi>
			<mo>＞</mo>
			<mo>−</mo>
			<mfrac>
			<mn>2</mn>
			<mn>3</mn>
			</mfrac>
			<mo>.</mo>
			</math>
			<p>
			所以不等式的解集用区间表示为<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mo>−</mo>
			<mfrac>
			<mn>2</mn>
			<mn>3</mn>
			</mfrac>
			<mo>，</mo>
			<mo>+</mo>
			<mi mathvariant="normal">∞</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>，表示在数轴上如图2-1所示.
			</p>
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0050-7.jpg" /></p>
			<p class="img">图2-1</p>
			<p>
			<span
			class="zt-ls"><b>例3</b></span>　设<b>R</b>为全集，集合<i>A</i>={<i>x</i>\|-5＜<i>x</i>＜6}，<i>B</i>={<i>x</i>\|<i>x</i>≥3或<i>x</i>≤-3}，用区间表示<i>A</i>∩<i>B</i>.
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span>
			在数轴上将集合<i>A</i>，<i>B</i>表示出来，如图2-2所示.
			</p>
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0050-8.jpg" /></p>
			<p class="img">图2-2</p>
			<p>
			<i>A</i>∩<i>B</i>={<i>x</i>\|-5＜<i>x</i>＜6}∩{<i>x</i>\|<i>x</i>≥3或<i>x</i>≤-3}
			</p>
			<p>={<i>x</i>\|-5＜<i>x</i>≤-3}∪{<i>x</i>\|3≤<i>x</i>＜6}</p>
			<p>=（-5，-3］∪［3，6）.</p>
			</div>
			</div>
			</div>
			<!-- 040 -->
			<div class="page-box" page="47">
			<div v-if="showPageList.indexOf(47) > -1">
			<ul class="page-header-odd fl al-end">
			<li>040</li>
			<li>数学.基础模块</li>
			<li>上册</li>
			</ul>
			<div class="padding-116">
			<p class="left"><img class="img-gn" alt="" src="../../assets/images/stlx.jpg" /></p>
			<div class="bj">
			<p>1.用区间表示下列集合.</p>
			<p>（1） <i>A</i>={<i>x</i>\|<i>x</i>＞0}；</p>
			<p>（2） <i>B</i>={<i>x</i>\|<i>x</i>＜0}；</p>
			<p>（3） <i>M</i>={<i>x</i>\|-1＜<i>x</i>≤0}.</p>
			<p>2.填空题.</p>
			<p>（1） {<i>x</i>\|-π≤<i>x</i>≤π}用区间表示为______；</p>
			<p>（2） {<i>x</i>\|-π＜<i>x</i>＜π}用区间表示为______；</p>
			<p>（3） {<i>x</i>\|-π＜<i>x</i>≤π}用区间表示为______；</p>
			<p>（4） {<i>x</i>\|-π≤<i>x</i>＜π}用区间表示为______；</p>
			<p>（5） {<i>x</i>\|<i>x</i>≥π}用区间表示为______；</p>
			<p>（6） {<i>x</i>\|<i>x</i>＜-π}用区间表示为______.</p>
			<div v-if="isShowAnswer6">
			<p>
			3.设<b>R</b>为全集，集合<i>M</i>={<i>x</i>\|4<i>x</i>＞2<i>x</i>+4}，<i>P</i>={<i>x</i>\|-1≤<i>x</i>≤1}，用区间表示下列集合.
			<span class="zt-ls"><b>解</b></span>（1）［-3，1］，是闭区间；
			</p>
			<p>
			（1） <i>M</i>∪<i>P</i>，<i>M</i>∩<i>P</i>；（2） ∁<i><sub><b>R</b></sub>M</i>，∁<i><sub><b>R</b></sub>P</i>.
			</p>
			</div>
			<h3 id="c015">习题2.2<span class="fontsz2">＞＞＞</span></h3>
			<div class="bj">
			<p>
			<span class="bj-sp"><b>水平一</b></span>
			</p>
			<p>1.集合{<i>x</i>\|0＜<i>x</i>≤2}用区间表示为（　）.</p>
			<p>
			<i>A</i>.（0，2） <i>B</i>.［0，2］ <i>C</i>.（0，2］
			<i>D</i>.［0，2）
			</p>
			<p>2.解集是区间［2，+∞）的不等式是（　）.</p>
			<p>
			<i>A</i>.2<i>x</i>-4＞0 <i>B</i>.3<i>x</i>-6≥0 <i>C</i>.4<i>x</i>≥2<i>x D</i>.3<i>x</i>-6≤0
			</p>
			<p>3.集合{<i>x</i>\|<i>x</i>＞1}用区间表示为________.</p>
			<p>4.已知区间<i>A</i>=［1，2］，<i>B</i>=（3，4），则π属于哪个区间？</p>
			<p>
			5.设<b>R</b>为全集，集合<i>M</i>={<i>x</i>\|3<i>x</i>＞4}，<math display="0">
			<mi>P</mi>
			<mo>=</mo>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">{</mo>
			<mi>x</mi>
			<mrow>
			<mo stretchy="false">\|</mo>
			</mrow>
			<mi>x</mi>
			<mo>≤</mo>
			<msqrt>
			<mn>2</mn>
			</msqrt>
			<mo data-mjx-texclass="CLOSE">}</mo>
			</mrow>
			</math>，用区间表示下列集合.
			</p>
			<p>
			（1） ∁<i><sub><b>R</b></sub>M</i>，∁<i><sub><b>R</b></sub>P</i>；（2） <i>M</i>∪<i>P</i>，<i>M</i>∩<i>P</i>.
			</p>

			</div>
			</div>
			</div>
			</div>
			<!-- 041 -->
			<div class="page-box" page="48">
			<div v-if="showPageList.indexOf(48) > -1">
			<ul class="page-header-box">
			<li>
			<p>第二单元不等式</p>
			</li>
			<li>
			<p><span>041</span></p>
			</li>
			</ul>
			<div class="padding-116">
			<div class="bj">
			<p>
			<span class="bj-sp"><b>水平二</b></span>
			</p>
			<p>1.用符号“⊆”“⊇”或“≠”填空.</p>
			<p>（1）［1，2］____（3，4）；</p>
			<p>（2）［0，2］____（0，2）；</p>
			<p>（3）（-∞，0］____［-100，0）.</p>
			<p>
			2.已知区间<i>A</i>=[0，<i>a</i>]，<i>B</i>=[0，15]，且<i>A</i>⫋<i>B</i>，求<i>a</i>所在的区间.
			</p>
			<p>
			3.设<b>R</b>为全集，集合<i>M</i>={<i>x</i>\|2<i>x</i>＞<i>x</i>+3}，<i>P</i>={<i>x</i>\|-1≤<i>x</i>≤2}，用区间表示下列集合.
			</p>
			<p>
			（1） ∁<i><sub><b>R</b></sub>M</i>，∁<i><sub><b>R</b></sub>P</i>；
			</p>
			<p>（2） <i>M</i>∪<i>P</i>，<i>M</i>∩<i>P</i>；</p>
			<p>（2）（-1，2），是开区间；</p>
			<p>
			（3）
			∁<i><sub><b>R</b></sub></i>（<i>M</i>∩<i>P</i>），（∁<i><sub><b>R</b></sub>M</i>）∪（∁<i><sub><b>R</b></sub>P</i>）；
			<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">[</mo>
			<mfrac>
			<mn>3</mn>
			<mn>2</mn>
			</mfrac>
			<mo>，</mo>
			<mn>4</mn>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>，是左闭右开区间；
			</p>
			<p>
			（4）
			∁<i><sub><b>R</b></sub></i>（<i>M</i>∪<i>P</i>），（∁<i><sub><b>R</b></sub>M</i>）∩（∁<i><sub><b>R</b></sub>P</i>）.
			<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mo>−</mo>
			<mn>6</mn>
			<mo>，</mo>
			<mo>−</mo>
			<mfrac>
			<mn>1</mn>
			<mn>2</mn>
			</mfrac>
			<mo data-mjx-texclass="CLOSE">]</mo>
			</mrow>
			</math>，是左开右闭区间；
			</p>
			<p>（5）［2，+∞），是左闭右开区间；</p>
			<p>（6）（-∞，1），是开区间.</p>
			</div>
			<p class="p-btn">
			<span class="zt-ls"><b>例2</b></span>
			<span class="t1">用区间表示不等式3<i>x</i>＜9<i>x</i>+4的解集，并在数轴上表示出来.</span>
			<span class="btn-box" @click="isShowAnswer7 = !isShowAnswer7">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<div v-if="isShowAnswer7">
			<p>
			<span class="zt-ls"><b>解</b></span> 解不等式3<i>x</i>＜9<i>x</i>+4，得
			</p>
			<math display="block">
			<mi>x</mi>
			<mo>＞</mo>
			<mo>−</mo>
			<mfrac>
			<mn>2</mn>
			<mn>3</mn>
			</mfrac>
			<mo>.</mo>
			</math>
			<p>
			所以不等式的解集用区间表示为<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mo>−</mo>
			<mfrac>
			<mn>2</mn>
			<mn>3</mn>
			</mfrac>
			<mo>，</mo>
			<mo>+</mo>
			<mi mathvariant="normal">∞</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>，表示在数轴上如图2-1所示.
			</p>
			<p class="center"><img class="img-f" alt="" src="../../assets/images/0050-7.jpg" /></p>
			<p class="img">图2-1</p>
			</div>
			<p class="p-btn">
			<span class="zt-ls"><b>例3</b></span>
			<span class="t1">设<b>R</b>为全集，集合A={x\|-5＜x＜6}，B={x\|x≥3或x≤-3}，用区间表示A∩B.</span>
			<span class="btn-box" @click="isShowAnswer8 = !isShowAnswer8">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<div v-if="isShowAnswer8">
			<p>
			<span class="zt-ls"><b>解</b></span>
			在数轴上将集合<i>A</i>，<i>B</i>表示出来，如图2-2所示.
			</p>
			<p class="center"><img class="img-d" alt="" src="../../assets/images/0050-8.jpg" /></p>
			<p class="img">图2-2</p>
			<p>
			<i>A</i>∩<i>B</i>={<i>x</i>\|-5＜<i>x</i>＜6}∩{<i>x</i>\|<i>x</i>≥3或<i>x</i>≤-3}
			</p>
			<p>={<i>x</i>\|-5＜<i>x</i>≤-3}∪{<i>x</i>\|3≤<i>x</i>＜6}</p>
			<p>=（-5，-3］∪［3，6）.</p>
			</div>
			<p class="left">
			<img class="img-gn" alt="" src="../../assets/images/stlx.jpg" />
			</p>
			<div class="bj">
			<examinations :cardList="questionData[47] ? questionData[47][1] : []" sourceType="json"
			inputBc="#d3edfa" v-if="questionData"></examinations>
			</div>
			<h3 id="c015">习题2.2<span class="fontsz2">＞＞＞</span></h3>
			<div class="bj">
			<examinations :cardList="questionData[47] ? questionData[47][2] : []" sourceType="json"
			inputBc="#d3edfa" v-if="questionData"></examinations>
			</div>
			<h2 id="b009">
			2.3 一元二次不等式<span class="fontsz1">＞＞＞＞＞＞＞＞</span>
			@@ -1269,6 +1075,12 @@
			</p>
			</div>
			</div>
			</div>
			<!-- 040 -->
			<div class="page-box hidePage" page="47">
			</div>
			<!-- 041 -->
			<div class="page-box hidePage" page="48">
			</div>
			<!-- 042 -->
			<div class="page-box" page="49">
			@@ -1406,24 +1218,135 @@
			</math>，与<i>y</i>轴的交点坐标为（0，<i>c</i>）.
			</p>
			</div>
			<p><b>例</b> 已知二次函数<i>y</i>=<i>x</i><sup>2</sup>-2<i>x</i>-3，</p>
			<p>（1）画出该函数图像；</p>
			<p>
			<p class="p-btn">
			<b>例</b>
			<span>已知二次函数<i>y</i>=<i>x</i><sup>2</sup>-2<i>x</i>-3，</span>
			<span class="btn-box" @click="openDialog(thinkOne)">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.545" height="18.112" viewBox="0 0 20.545 22.112">
			<path class="a"
			d="M3771.2-14311.889a2.356,2.356,0,0,1-1.727-.626c-.027-.054-.053-.1-.079-.148l0-.007c-.123-.224-.2-.371-.076-.629a.869.869,0,0,1,.784-.471.205.205,0,0,1,.158.079.205.205,0,0,0,.158.079.187.187,0,0,0,.038.1.143.143,0,0,0,.117.05h.158a.573.573,0,0,0,.471.158,2.2,2.2,0,0,0,.916-.3l.023-.011a.572.572,0,0,1,.471-.158.575.575,0,0,1,.626.626.526.526,0,0,1,.036.409.664.664,0,0,1-.349.375A3.582,3.582,0,0,1,3771.2-14311.889Zm-1.885-1.723h-.155a.718.718,0,0,1-.784-.63.38.38,0,0,1-.021-.3.976.976,0,0,1,.492-.485l4.86-1.252a1.047,1.047,0,0,1,.784.626c.151.3-.128.61-.471.784l-4.705,1.256Zm-.155-1.885H3769a.716.716,0,0,1-.784-.626c-.149-.3.129-.611.471-.784l4.234-1.1v-.158l-.021.007a7.808,7.808,0,0,1-1.861.31,5.3,5.3,0,0,1-3.137-.942,5.789,5.789,0,0,1-2.666-4.076,6.421,6.421,0,0,1,1.256-5.018,7.038,7.038,0,0,1,2.194-1.568,7.848,7.848,0,0,1,2.666-.472,6.43,6.43,0,0,1,2.979.784,4.958,4.958,0,0,1,2.2,2.194,5.522,5.522,0,0,1,.313,5.177,13.113,13.113,0,0,1-1.256,1.882l-.313.313a2.156,2.156,0,0,0-.78,1.244l0,.012a1.731,1.731,0,0,1-1.727,1.723l-.313.158-3.292.939Zm1.256-6.271v1.256h1.41v-1.256Zm.784-4.234c.718,0,1.1.271,1.1.784a.925.925,0,0,1-.316.783l-.468.156a2.235,2.235,0,0,0-.63.471l-.012.024a2.2,2.2,0,0,0-.3.918v.155h1.1v-.155a1.2,1.2,0,0,1,.313-.629.543.543,0,0,0,.315-.153c.007,0,.315,0,.315-.16a1.226,1.226,0,0,0,.626-.626,2.277,2.277,0,0,0,.313-1.1,1.409,1.409,0,0,0-.626-1.252,2.337,2.337,0,0,0-1.569-.471,2.258,2.258,0,0,0-2.507,2.353l1.252.154A1.121,1.121,0,0,1,3771.2-14326Zm-6.51,9.645a.769.769,0,0,1-.549-.237.772.772,0,0,1-.235-.549.772.772,0,0,1,.235-.548l.939-.939a.781.781,0,0,1,.55-.234.772.772,0,0,1,.547.234.772.772,0,0,1,.238.549.772.772,0,0,1-.238.549l-.939.938A.769.769,0,0,1,3764.686-14316.356Zm13.174-.157a.774.774,0,0,1-.549-.234l-.943-.942a.678.678,0,0,1-.233-.47.678.678,0,0,1,.233-.47.774.774,0,0,1,.549-.234.774.774,0,0,1,.549.234l.942.939a.427.427,0,0,1,.228.324.74.74,0,0,1-.228.618A.774.774,0,0,1,3777.859-14316.514Zm2.9-6.351h-1.414c-.469-.158-.784-.474-.784-.784a.743.743,0,0,1,.784-.784h1.414a.743.743,0,0,1,.784.784A.743.743,0,0,1,3780.761-14322.864Zm-17.566-.158h-1.41c-.469-.157-.784-.473-.784-.784a.743.743,0,0,1,.784-.784h1.41a.743.743,0,0,1,.784.784A.743.743,0,0,1,3763.195-14323.022Zm13.861-5.723a.759.759,0,0,1-.529-.237.776.776,0,0,1-.235-.549.772.772,0,0,1,.235-.549l.939-.938a.44.44,0,0,1,.413-.238.759.759,0,0,1,.529.238.772.772,0,0,1,.235.549.772.772,0,0,1-.235.548l-.942.939A.435.435,0,0,1,3777.055-14328.745Zm-11.429,0a.776.776,0,0,1-.55-.237l-.939-1.1a.678.678,0,0,1-.235-.469.678.678,0,0,1,.235-.47.772.772,0,0,1,.549-.238.772.772,0,0,1,.549.238l.939,1.1a.675.675,0,0,1,.238.47.675.675,0,0,1-.238.47A.767.767,0,0,1,3765.626-14328.745Zm5.724-2.273a.743.743,0,0,1-.784-.785v-1.413c.157-.469.473-.784.784-.784a.743.743,0,0,1,.784.784v1.413A.743.743,0,0,1,3771.35-14331.019Z"
			transform="translate(-3761 14334.001)" />
			</svg>
			</span>
			</p>
			<p class="p-btn">
			（1）画出该函数图像；
			<span class="btn-box" @click="isShowAnswer9 = !isShowAnswer9">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<div v-if="isShowAnswer9">
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0055-1.jpg" /></p>
			<p class="img">图2-3</p>
			<p>
			<span class="zt-ls"><b>解</b></span>（1）因为<i>a</i>=1＞0，所以函数图像为开口向上的抛物线.
			</p>
			<p>
			因为<i>Δ</i>=<i>b</i><sup>2</sup>-4<i>ac</i>=（-2）<sup>2</sup>-4×1×（-3）=16＞0，
			</p>
			<p>
			所以一元二次方程<i>x</i><sup>2</sup>-2<i>x</i>-3=0有两个不相等的实数解.
			</p>
			<p>解方程，得<i>x</i><sub>1</sub>=-1，<i>x</i><sub>2</sub>=3.</p>
			<p>所以抛物线与<i>x</i>轴的交点坐标为（-1，0），（3，0）.</p>
			<p>
			抛物线的顶点坐标为<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mo>−</mo>
			<mfrac>
			<mi>b</mi>
			<mrow>
			<mn>2</mn>
			<mi>a</mi>
			</mrow>
			</mfrac>
			<mo>，</mo>
			<mfrac>
			<mrow>
			<mn>4</mn>
			<mi>a</mi>
			<mi>c</mi>
			<mo>−</mo>
			<msup>
			<mi>b</mi>
			<mrow>
			<mn>2</mn>
			</mrow>
			</msup>
			</mrow>
			<mrow>
			<mn>4</mn>
			<mi>a</mi>
			</mrow>
			</mfrac>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>，即（1，-4）.
			</p>
			<p>
			抛物线的对称轴方程为<math display="0">
			<mi>x</mi>
			<mo>=</mo>
			<mo>−</mo>
			<mfrac>
			<mi>b</mi>
			<mrow>
			<mn>2</mn>
			<mi>a</mi>
			</mrow>
			</mfrac>
			</math>，即<i>x</i>=1.抛物线与<i>y</i>轴的交点坐标为（0，<i>c</i>），即（0，-3）.根据函数的对称性，可以再取一些点，如（2，-3）.
			</p>
			<p>
			根据以上信息，就可以画出函数<i>y</i>=<i>x</i><sup>2</sup>-2<i>x</i>-3的图像（如图2-3所示）.
			</p>
			</div>
			<p class="p-btn">
			（2）
			指出该函数图像上纵坐标分别为<i>y</i>=0，<i>y</i>＞0，<i>y</i>＜0的所有点；
			指出该函数图像上纵坐标分别为y=0，y＞0，y＜0的所有点；
			<span class="btn-box" @click="isShowAnswer10 = !isShowAnswer10">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			<p v-if="isShowAnswer10">
			<span class="zt-ls"><b>解</b></span>
			（2）
			观察图像可知，满足<i>y</i>=0的点是抛物线与<i>x</i>轴的交点；满足<i>y</i>＞0的点是抛物线在<i>x</i>轴上方的所有点；满足<i>y</i>＜0的点是抛物线在<i>x</i>轴下方的所有点.
			</p>
			<p class="p-btn">
			（3）
			根据函数图像写出<i>y</i>=0，<i>y</i>＞0，<i>y</i>＜0时所对应的<i>x</i>的值或取值范围.
			根据函数图像写出y=0，y＞0，y＜0时所对应的x的值或取值范围.
			<span class="btn-box" @click="isShowAnswer11 = !isShowAnswer11">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p class="block">
			<span
			class="zt-ls2"><b>分析</b></span>　①根据<i>x</i><sup>2</sup>的系数判断函数图像（抛物线）的开口方向；②用判别式判定出一元二次方程<i>x</i><sup>2</sup>-2<i>x</i>-3=0的解的情况，从而确定二次函数<i>y</i>=<i>x</i><sup>2</sup>-2<i>x</i>-3的图像与<i>x</i>轴的交点个数和交点坐标；③计算二次函数图像的顶点坐标、与<i>y</i>轴的交点坐标；④求出二次函数图像的对称轴方程，并利用函数图像的对称性再找出一些点；⑤最后根据上述信息画出函数图像.
			</p>
			<p class="block">
			画出图像后，<i>y</i>=0，<i>y</i>＞0，<i>y</i>＜0分别对应函数图像与<i>x</i>轴相交、函数图像在<i>x</i>轴上方、函数图像在<i>x</i>轴下方三种情形，根据图像完成（2）（3）
			两个问题.
			</p>
			<div v-if="isShowAnswer11">
			<p>
			<span class="zt-ls"><b>解</b></span>
			（3）
			观察图像可知，当<i>y</i>=0时，对应抛物线与<i>x</i>轴的两个交点，此时<i>x</i>有两个取值，<i>x</i><sub>1</sub>=-1，<i>x</i><sub>2</sub>=3；
			</p>
			<p>
			当<i>y</i>＞0时，对应抛物线在<i>x</i>轴上方的所有点，此时<i>x</i>的取值范围是<i>x</i>＜-1或<i>x</i>＞3；
			</p>
			<p>
			当<i>y</i>＜0时，对应抛物线在<i>x</i>轴下方的所有点，此时<i>x</i>的取值范围是-1＜<i>x</i>＜3.
			</p>
			</div>
			<iframe src="https://www.geogebra.org/calculator" frameborder="0" class="iframe-box"></iframe>
			</div>
			</div>
			</div>
			@@ -1436,105 +1359,368 @@
			<li>上册</li>
			</ul>
			<div class="padding-116">
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0055-1.jpg" /></p>
			<p class="img">图2-3</p>
			<p>
			<span class="zt-ls"><b>解</b></span>（1）因为<i>a</i>=1＞0，所以函数图像为开口向上的抛物线.
			</p>
			<p>
			因为<i>Δ</i>=<i>b</i><sup>2</sup>-4<i>ac</i>=（-2）<sup>2</sup>-4×1×（-3）=16＞0，
			</p>
			<p>
			所以一元二次方程<i>x</i><sup>2</sup>-2<i>x</i>-3=0有两个不相等的实数解.
			</p>
			<p>解方程，得<i>x</i><sub>1</sub>=-1，<i>x</i><sub>2</sub>=3.</p>
			<p>所以抛物线与<i>x</i>轴的交点坐标为（-1，0），（3，0）.</p>
			<p>
			抛物线的顶点坐标为<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mo>−</mo>
			<mfrac>
			<mi>b</mi>
			<mrow>
			<mn>2</mn>
			<mi>a</mi>
			</mrow>
			</mfrac>
			<mo>，</mo>
			<mfrac>
			<mrow>
			<mn>4</mn>
			<mi>a</mi>
			<mi>c</mi>
			<mo>−</mo>
			<msup>
			<mi>b</mi>
			<mrow>
			<mn>2</mn>
			</mrow>
			</msup>
			</mrow>
			<mrow>
			<mn>4</mn>
			<mi>a</mi>
			</mrow>
			</mfrac>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>，即（1，-4）.
			</p>
			<p>
			抛物线的对称轴方程为<math display="0">
			<mi>x</mi>
			<mo>=</mo>
			<mo>−</mo>
			<mfrac>
			<mi>b</mi>
			<mrow>
			<mn>2</mn>
			<mi>a</mi>
			</mrow>
			</mfrac>
			</math>，即<i>x</i>=1.抛物线与<i>y</i>轴的交点坐标为（0，<i>c</i>），即（0，-3）.根据函数的对称性，可以再取一些点，如（2，-3）.
			</p>
			<p>
			根据以上信息，就可以画出函数<i>y</i>=<i>x</i><sup>2</sup>-2<i>x</i>-3的图像（如图2-3所示）.
			</p>
			<p>
			（2）
			观察图像可知，满足<i>y</i>=0的点是抛物线与<i>x</i>轴的交点；满足<i>y</i>＞0的点是抛物线在<i>x</i>轴上方的所有点；满足<i>y</i>＜0的点是抛物线在<i>x</i>轴下方的所有点.
			</p>
			<p>
			（3）
			观察图像可知，当<i>y</i>=0时，对应抛物线与<i>x</i>轴的两个交点，此时<i>x</i>有两个取值，<i>x</i><sub>1</sub>=-1，<i>x</i><sub>2</sub>=3；
			</p>
			<p>
			当<i>y</i>＞0时，对应抛物线在<i>x</i>轴上方的所有点，此时<i>x</i>的取值范围是<i>x</i>＜-1或<i>x</i>＞3；
			</p>
			<p>
			当<i>y</i>＜0时，对应抛物线在<i>x</i>轴下方的所有点，此时<i>x</i>的取值范围是-1＜<i>x</i>＜3.
			</p>
			<div class="bk-hzjl">
			<div class="bj1-hzjl">
			<p class="left">
			<img class="img-gn2" alt="" src="../../assets/images/hzjl.jpg" />
			</p>
			</div>
			<p class="block">同学互相交流如何画二次函数的简图.</p>
			<examinations :cardList="questionData[51] ? questionData[51][1] : []" sourceType="json"
			inputBc="#d3edfa" v-if="questionData"></examinations>
			</div>
			<p class="left"><img class="img-gn" alt="" src="../../assets/images/stlx.jpg" /></p>
			<div class="bj">
			<p>已知下列二次函数：</p>
			<p>
			①<i>y</i>=<i>x</i><sup>2</sup>-3<i>x</i>-4， ②<i>y</i>=<i>x</i><sup>2</sup>+<i>x</i>+2，
			③<i>y</i>=<i>x</i><sup>2</sup>-6<i>x</i>+9.
			</p>
			<p>①<i>y</i>=<i>x</i><sup>2</sup>-3<i>x</i>-4， ②<i>y</i>=<i>x</i><sup>2</sup>+<i>x</i>+2，
			③<i>y</i>=<i>x</i><sup>2</sup>-6<i>x</i>+9.</p>
			<p>（1）分别画出它们的函数图像；</p>
			<!-- <paint :page="51" :imgUrl="this.config.activeBook.resourceUrl + '/images/a6fe3d63.png'" /> -->
			<graffiti
			:page="51"
			:bcImg="this.config.activeBook.resourceUrl + '/images/a6fe3d63.png'"
			:imgWidth="520"
			:imgHeight="494"
			/>
			<p>
			（2）
			根据函数图像写出<i>y</i>=0，<i>y</i>＞0，<i>y</i>＜0时所对应的<i>x</i>的值或取值范围.
			（2）根据函数图像写出<i>y</i>=0，<i>y</i>＞0，<i>y</i>＜0时所对应的<i>x</i>的值或取值范围.
			<span class="btn-box" @click="isShowAnswer = !isShowAnswer">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<el-input type="textarea" placeholder="请输入内容" rows="6" class="question-textarea"></el-input>
			<ul class="table-answer-box" v-if="isShowAnswer">
			<li>答案：</li>
			<li>
			<math display="block">
			<mrow>
			<mo>①</mo>
			</mrow>
			<mi>y</mi>
			<mo>=</mo>
			<msup>
			<mi>x</mi>
			<mrow>
			<mn>2</mn>
			</mrow>
			</msup>
			<mo>−</mo>
			<mn>3</mn>
			<mi>x</mi>
			<mo>−</mo>
			<mn>4</mn>
			<mo>=</mo>
			<mo stretchy="false">(</mo>
			<mi>x</mi>
			<mo>+</mo>
			<mn>1</mn>
			<mo stretchy="false">)</mo>
			<mo stretchy="false">(</mo>
			<mi>x</mi>
			<mo>−</mo>
			<mn>4</mn>
			<mo stretchy="false">)</mo>
			</math>
			<math display="block">
			<mo>当</mo>
			<mi>y</mi>
			<mo>=</mo>
			<mn>0</mn>
			<mo>时，</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>1</mn>
			</mrow>
			</msub>
			<mo>=</mo>
			<mo>−</mo>
			<mn>1</mn>
			<mo>或</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>2</mn>
			</mrow>
			</msub>
			<mo>=</mo>
			<mn>4</mn>
			<mo>，</mo>
			</math>
			<math display="block">
			<mo>当</mo>
			<mi>y</mi>
			<mo>></mo>
			<mn>0</mn>
			<mo>时，</mo>
			<mi>x</mi>
			<mo><</mo>
			<mo>−</mo>
			<mn>1</mn>
			<mo>或</mo>
			<mi>x</mi>
			<mo>></mo>
			<mn>4</mn>
			<mo>，</mo>
			</math>
			<math display="block">
			<mo>当</mo>
			<mi>y</mi>
			<mo><</mo>
			<mn>0</mn>
			<mo>时，</mo>
			<mo>−</mo>
			<mn>1</mn>
			<mo><</mo>
			<mi>x</mi>
			<mo><</mo>
			<mn>4</mn>
			<mo>；</mo>
			</math>
			<math display="block">
			<mo>因此当</mo>
			<mi>y</mi>
			<mo>=</mo>
			<mn>0</mn>
			<mo>时，所对应的点为</mo>
			<mo stretchy="false">(</mo>
			<mo>−</mo>
			<mn>1</mn>
			<mo>,</mo>
			<mn>0</mn>
			<mo stretchy="false">)</mo>
			<mo>,</mo>
			<mo stretchy="false">(</mo>
			<mn>4</mn>
			<mo>,</mo>
			<mn>0</mn>
			<mo stretchy="false">)</mo>
			<mo>;</mo>
			<mo>当</mo>
			<mi>y</mi>
			<mo>></mo>
			<mn>0</mn>
			<mo>时，所对应的点为</mo>
			</math>
			<math display="block">
			<mo stretchy="false">(</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>0</mn>
			</mrow>
			</msub>
			<mo>,</mo>
			<mi>y</mi>
			<mo stretchy="false">)</mo>
			<mo>，其中，</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>0</mn>
			</mrow>
			</msub>
			<mo><</mo>
			<mo>−</mo>
			<mn>1</mn>
			<mo>或</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>0</mn>
			</mrow>
			</msub>
			<mo>></mo>
			<mn>4</mn>
			<mo>；</mo>
			</math>
			<math display="block">
			<mo>当</mo>
			<mi>y</mi>
			<mo><</mo>
			<mn>0</mn>
			<mo>时，所对应的点为</mo>
			<mo stretchy="false">(</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>0</mn>
			</mrow>
			</msub>
			<mo>,</mo>
			<mi>y</mi>
			<mo stretchy="false">)</mo>
			<mo>，其中</mo>
			<mo>−</mo>
			<mn>1</mn>
			<mo><</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>0</mn>
			</mrow>
			</msub>
			<mo><</mo>
			<mn>4</mn>
			<mo>；</mo>
			</math>
			<math display="block">
			<mrow>
			<mo>②</mo>
			</mrow>
			<mi>y</mi>
			<mo>=</mo>
			<msup>
			<mi>x</mi>
			<mrow>
			<mn>2</mn>
			</mrow>
			</msup>
			<mo>+</mo>
			<mi>x</mi>
			<mo>+</mo>
			<mn>2</mn>
			<mo>=</mo>
			<mo stretchy="false">(</mo>
			<mi>x</mi>
			<mo>+</mo>
			<mfrac>
			<mn>1</mn>
			<mn>2</mn>
			</mfrac>
			<msup>
			<mo stretchy="false">)</mo>
			<mrow>
			<mn>2</mn>
			</mrow>
			</msup>
			<mo>+</mo>
			<mfrac>
			<mn>7</mn>
			<mn>4</mn>
			</mfrac>
			<mo>></mo>
			<mn>0</mn>
			<mo>；</mo>
			</math>
			<math display="block">
			<mo>当</mo>
			<mi>y</mi>
			<mo>=</mo>
			<mn>0</mn>
			<mo>，</mo>
			<mi>y</mi>
			<mo><</mo>
			<mn>0</mn>
			<mo>时，没有对应的点；当</mo>
			<mi>y</mi>
			<mo>></mo>
			<mn>0</mn>
			<mo>时，所对应的点为</mo>
			<mo stretchy="false">(</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>0</mn>
			</mrow>
			</msub>
			<mo>,</mo>
			<mi>y</mi>
			<mo stretchy="false">)</mo>
			</math>
			<math>
			<mo>，其中</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>0</mn>
			</mrow>
			</msub>
			<mo>∈</mo>
			<mi>R</mi>
			<mo>.</mo>
			</math>
			<math display="block">
			<mrow>
			<mo>③</mo>
			</mrow>
			<mi>y</mi>
			<mo>=</mo>
			<msup>
			<mi>x</mi>
			<mrow>
			<mn>2</mn>
			</mrow>
			</msup>
			<mo>−</mo>
			<mn>6</mn>
			<mi>x</mi>
			<mo>+</mo>
			<mn>9</mn>
			<mo>=</mo>
			<mo stretchy="false">(</mo>
			<mi>x</mi>
			<mo>−</mo>
			<mn>3</mn>
			<msup>
			<mo stretchy="false">)</mo>
			<mrow>
			<mn>2</mn>
			</mrow>
			</msup>
			<mo>.</mo>
			</math>
			<math display="block">
			<mo>当</mo>
			<mi>y</mi>
			<mo>=</mo>
			<mn>0</mn>
			<mo>时</mo>
			<mo>,</mo>
			<mo>所对应的点为</mo>
			<mo stretchy="false">(</mo>
			<mn>3</mn>
			<mo>,</mo>
			<mn>0</mn>
			<mo stretchy="false">)</mo>
			<mo>；当</mo>
			<mi>y</mi>
			<mo>></mo>
			<mn>0</mn>
			<mo>时，所对应的点为</mo>
			<mo stretchy="false">(</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>0</mn>
			</mrow>
			</msub>
			<mo>,</mo>
			<mi>y</mi>
			<mo stretchy="false">)</mo>
			</math>
			<math display="block">
			<mo>，其中</mo>
			<msub>
			<mi>x</mi>
			<mrow>
			<mn>0</mn>
			</mrow>
			</msub>
			<mo>≠</mo>
			<mn>3</mn>
			<mo>；当</mo>
			<mi>y</mi>
			<mo><</mo>
			<mn>0</mn>
			<mo>时，没有对应的点</mo>
			<mo>.</mo>
			</math>
			</li>
			</ul>
			</div>
			</div>
			</div>
			@@ -1746,34 +1932,57 @@
			上面的情形表明，二次函数图像的开口方向及其与<i>x</i>轴的交点坐标，可以确定其对应的一元二次不等式的解集.
			</p>
			<p><b>例</b> 利用二次函数的图像解下列一元二次不等式.</p>
			<p>
			（1） -<i>x</i><sup>2</sup>+3<i>x</i>+4＜0；（2） <i>x</i><sup>2</sup>-2<i>x</i>+3＞0.
			<p class="p-btn" >
			<span>（1） -<i>x</i><sup>2</sup>+3<i>x</i>+4＜0；</span>
			<span class="btn-box" @click="isShowAnswer12 = !isShowAnswer12">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0057-1.jpg" /></p>
			<p class="img">图2-5</p>
			<p>
			<span class="zt-ls"><b>解</b></span>（1）
			Δ=<i>b</i><sup>2</sup>-4<i>ac</i>=3<sup>2</sup>-4×（-1）×4=25＞0，所以函数<i>y</i>=-<i>x</i><sup>2</sup>+3<i>x</i>+4的图像与<i>x</i>轴有两个交点.解方程-<i>x</i><sup>2</sup>+3<i>x</i>+4=0可得，<i>x</i>1=-1，<i>x</i>2=4.
			<div v-if="isShowAnswer12" >
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0057-1.jpg" /></p>
			<p class="img">图2-5</p>
			<p>
			<span class="zt-ls"><b>解</b></span>（1）
			Δ=<i>b</i><sup>2</sup>-4<i>ac</i>=3<sup>2</sup>-4×（-1）×4=25＞0，所以函数<i>y</i>=-<i>x</i><sup>2</sup>+3<i>x</i>+4的图像与<i>x</i>轴有两个交点.解方程-<i>x</i><sup>2</sup>+3<i>x</i>+4=0可得，<i>x</i>1=-1，<i>x</i>2=4.
			</p>
			<p>
			函数<i>y</i>=-<i>x</i><sup>2</sup>+3<i>x</i>+4的图像是开口向下的抛物线，与<i>x</i>轴的交点坐标是（-1，0），（4，0），函数<i>y</i>=-<i>x</i><sup>2</sup>+3<i>x</i>+4的图像如图2-5所示.
			</p>
			</div>
			<p class="p-btn" >
			<span>（2） <i>x</i><sup>2</sup>-2<i>x</i>+3＞0.</span>
			<span class="btn-box" @click="isShowAnswer13 = !isShowAnswer13">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			函数<i>y</i>=-<i>x</i><sup>2</sup>+3<i>x</i>+4的图像是开口向下的抛物线，与<i>x</i>轴的交点坐标是（-1，0），（4，0），函数<i>y</i>=-<i>x</i><sup>2</sup>+3<i>x</i>+4的图像如图2-5所示.
			</p>
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0057-2.jpg" /></p>
			<p class="img">图2-6</p>
			<p>
			观察图像可得，不等式-<i>x</i><sup>2</sup>+3<i>x</i>+4＜0的解集是（-∞，
			-1）∪（4， +∞）.
			</p>
			<p>
			（2）
			<i>Δ</i>=<i>b</i><sup>2</sup>-4<i>ac</i>=（-2）<sup>2</sup>-4×1×3=-8＜0，所以函数<i>y</i>=<i>x</i><sup>2</sup>-2<i>x</i>+3的图像与<i>x</i>轴无交点.
			</p>
			<p>
			函数<i>y</i>=<i>x</i><sup>2</sup>-2<i>x</i>+3的图像是开口向上的抛物线，与<i>x</i>轴无交点，其简图如图2-6所示.
			</p>
			<p>
			观察图像可得，不等式<i>x</i><sup>2</sup>-2<i>x</i>+3＞0的解集为<b>R</b>.
			</p>
			<div v-if="isShowAnswer13" >
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0057-2.jpg" /></p>
			<p class="img">图2-6</p>
			<p>
			<span class="zt-ls"><b>解</b></span>
			观察图像可得，不等式-<i>x</i><sup>2</sup>+3<i>x</i>+4＜0的解集是（-∞，
			-1）∪（4， +∞）.
			</p>
			<p>
			（2）
			<i>Δ</i>=<i>b</i><sup>2</sup>-4<i>ac</i>=（-2）<sup>2</sup>-4×1×3=-8＜0，所以函数<i>y</i>=<i>x</i><sup>2</sup>-2<i>x</i>+3的图像与<i>x</i>轴无交点.
			</p>
			<p>
			函数<i>y</i>=<i>x</i><sup>2</sup>-2<i>x</i>+3的图像是开口向上的抛物线，与<i>x</i>轴无交点，其简图如图2-6所示.
			</p>
			<p>
			观察图像可得，不等式<i>x</i><sup>2</sup>-2<i>x</i>+3＞0的解集为<b>R</b>.
			</p>
			</div>
			<iframe src="https://www.geogebra.org/calculator" frameborder="0" class="iframe-box"></iframe>
			<div class="bk">
			<div class="bj1">
			<p class="left">
			@@ -1805,7 +2014,6 @@
			<p><span>047</span></p>
			</li>
			</ul>

			<div class="padding-116">
			<p class="img">续表</p>
			<p class="center"><img class="img-a" alt="" src="../../assets/images/0058-1.jpg" /></p>
			@@ -1815,9 +2023,9 @@
			<img class="img-gn2" alt="" src="../../assets/images/hzjl.jpg" />
			</p>
			</div>
			<p class="block">
			表2-5中要求<i>a</i>＞0，如果<i>a</i>＜0，应该怎样分析呢？请结合具体的例子进行思考，并将你的发现与同学进行交流讨论.
			</p>
			<examinations :cardList="questionData[54] ? questionData[54][1] : []" sourceType="json"
			v-if="questionData">
			</examinations>
			</div>
			<p class="left"><img class="img-gn" alt="" src="../../assets/images/cxgk.jpg" /></p>
			<p>
			@@ -1830,13 +2038,9 @@
			第二步：画出二次函数<i>y</i>=<i>ax</i><sup>2</sup>+<i>bx</i>+<i>c</i>的简图.
			</p>
			<p>第三步：观察简图，写出不等式的解集.</p>
			<p class="left"><img class="img-gn" alt="" src="../../assets/images/stlx.jpg" /></p>
			<div class="bj">
			<p>利用二次函数的图像解下列一元二次不等式.</p>
			<p>
			（1） <i>x</i><sup>2</sup>-9＞0；（2） <i>x</i><sup>2</sup>+4<i>x</i>＜0；（3） <i>x</i><sup>2</sup>≤4；
			</p>

			<examinations :cardList="questionData[54] ? questionData[54][2] : []" sourceType="json"
			inputBc="#d3edfa" v-if="questionData"></examinations>
			</div>
			</div>
			</div>
			@@ -1850,15 +2054,6 @@
			<li>上册</li>
			</ul>
			<div class="padding-116">
			<div class="bj">
			<p>
			（4） <i>x</i><sup>2</sup>-3<i>x</i>-4＞0；（5） <i>x</i><sup>2</sup>-<i>x</i>-2≤0；（6）
			-<i>x</i><sup>2</sup>-3<i>x</i>＜0；
			</p>
			<p>
			（7） -<i>x</i><sup>2</sup>+5<i>x</i>-6＜0；（8） -3<i>x</i><sup>2</sup>+2<i>x</i>-1＞0.
			</p>
			</div>
			<h3 id="c018">
			2.3.3 特殊类型一元二次不等式的解法<span class="fontsz2">＞＞＞</span>
			</h3>
			@@ -2011,55 +2206,100 @@
			<p>
			<span class="zt-ls"><b>例1</b></span>　解下列不等式.
			</p>
			<p>
			（1）（<i>x</i>+3）（<i>x</i>+1）＜0；（2）（6-<i>x</i>）（<i>x</i>+4）≤0.
			<p class="p-btn" >
			<span>（1）（<i>x</i>+3）（<i>x</i>+1）＜0；</span>
			<span class="btn-box" @click="isShowAnswer14 = !isShowAnswer14">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span>（1）（<i>x</i>+3）（<i>x</i>+1）＜0，即［<i>x</i>-（-3）］［<i>x</i>-（-1）］＜0.
			<div v-if="isShowAnswer14" >
			<p >
			<span class="zt-ls"><b>解</b></span>（1）（<i>x</i>+3）（<i>x</i>+1）＜0，即［<i>x</i>-（-3）］［<i>x</i>-（-1）］＜0.
			</p>
			<p >所以不等式的解集为（-3，-1）.</p>
			</div>
			<p class="p-btn" >
			<span>（2）（6-<i>x</i>）（<i>x</i>+4）≤0.</span>
			<span class="btn-box" @click="isShowAnswer15 = !isShowAnswer15">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>所以不等式的解集为（-3，-1）.</p>
			<p>
			<div v-if="isShowAnswer15" >
			<p>
			<span class="zt-ls"><b>解</b></span>
			（2）
			由（6-<i>x</i>）（<i>x</i>+4）≤0得（<i>x</i>-6）（<i>x</i>+4）≥0，即
			由（6-<i>x</i>）（<i>x</i>+4）≤0得（<i>x</i>-6）（<i>x</i>+4）≥0，即
			</p>
			<p class="center">（<i>x</i>-6）［<i>x</i>-（-4）］≥0.</p>
			<p>所以不等式的解集为（-∞，-4］∪［6，+∞）.</p>
			</div>
			<p class="p-btn" >
			<span>
			<span class="zt-ls"><b>例2</b></span>　解下列不等式.
			</span>
			<span class="btn-box" @click="openDialog(thinkTwo)">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.545" height="18.112" viewBox="0 0 20.545 22.112">
			<path class="a"
			d="M3771.2-14311.889a2.356,2.356,0,0,1-1.727-.626c-.027-.054-.053-.1-.079-.148l0-.007c-.123-.224-.2-.371-.076-.629a.869.869,0,0,1,.784-.471.205.205,0,0,1,.158.079.205.205,0,0,0,.158.079.187.187,0,0,0,.038.1.143.143,0,0,0,.117.05h.158a.573.573,0,0,0,.471.158,2.2,2.2,0,0,0,.916-.3l.023-.011a.572.572,0,0,1,.471-.158.575.575,0,0,1,.626.626.526.526,0,0,1,.036.409.664.664,0,0,1-.349.375A3.582,3.582,0,0,1,3771.2-14311.889Zm-1.885-1.723h-.155a.718.718,0,0,1-.784-.63.38.38,0,0,1-.021-.3.976.976,0,0,1,.492-.485l4.86-1.252a1.047,1.047,0,0,1,.784.626c.151.3-.128.61-.471.784l-4.705,1.256Zm-.155-1.885H3769a.716.716,0,0,1-.784-.626c-.149-.3.129-.611.471-.784l4.234-1.1v-.158l-.021.007a7.808,7.808,0,0,1-1.861.31,5.3,5.3,0,0,1-3.137-.942,5.789,5.789,0,0,1-2.666-4.076,6.421,6.421,0,0,1,1.256-5.018,7.038,7.038,0,0,1,2.194-1.568,7.848,7.848,0,0,1,2.666-.472,6.43,6.43,0,0,1,2.979.784,4.958,4.958,0,0,1,2.2,2.194,5.522,5.522,0,0,1,.313,5.177,13.113,13.113,0,0,1-1.256,1.882l-.313.313a2.156,2.156,0,0,0-.78,1.244l0,.012a1.731,1.731,0,0,1-1.727,1.723l-.313.158-3.292.939Zm1.256-6.271v1.256h1.41v-1.256Zm.784-4.234c.718,0,1.1.271,1.1.784a.925.925,0,0,1-.316.783l-.468.156a2.235,2.235,0,0,0-.63.471l-.012.024a2.2,2.2,0,0,0-.3.918v.155h1.1v-.155a1.2,1.2,0,0,1,.313-.629.543.543,0,0,0,.315-.153c.007,0,.315,0,.315-.16a1.226,1.226,0,0,0,.626-.626,2.277,2.277,0,0,0,.313-1.1,1.409,1.409,0,0,0-.626-1.252,2.337,2.337,0,0,0-1.569-.471,2.258,2.258,0,0,0-2.507,2.353l1.252.154A1.121,1.121,0,0,1,3771.2-14326Zm-6.51,9.645a.769.769,0,0,1-.549-.237.772.772,0,0,1-.235-.549.772.772,0,0,1,.235-.548l.939-.939a.781.781,0,0,1,.55-.234.772.772,0,0,1,.547.234.772.772,0,0,1,.238.549.772.772,0,0,1-.238.549l-.939.938A.769.769,0,0,1,3764.686-14316.356Zm13.174-.157a.774.774,0,0,1-.549-.234l-.943-.942a.678.678,0,0,1-.233-.47.678.678,0,0,1,.233-.47.774.774,0,0,1,.549-.234.774.774,0,0,1,.549.234l.942.939a.427.427,0,0,1,.228.324.74.74,0,0,1-.228.618A.774.774,0,0,1,3777.859-14316.514Zm2.9-6.351h-1.414c-.469-.158-.784-.474-.784-.784a.743.743,0,0,1,.784-.784h1.414a.743.743,0,0,1,.784.784A.743.743,0,0,1,3780.761-14322.864Zm-17.566-.158h-1.41c-.469-.157-.784-.473-.784-.784a.743.743,0,0,1,.784-.784h1.41a.743.743,0,0,1,.784.784A.743.743,0,0,1,3763.195-14323.022Zm13.861-5.723a.759.759,0,0,1-.529-.237.776.776,0,0,1-.235-.549.772.772,0,0,1,.235-.549l.939-.938a.44.44,0,0,1,.413-.238.759.759,0,0,1,.529.238.772.772,0,0,1,.235.549.772.772,0,0,1-.235.548l-.942.939A.435.435,0,0,1,3777.055-14328.745Zm-11.429,0a.776.776,0,0,1-.55-.237l-.939-1.1a.678.678,0,0,1-.235-.469.678.678,0,0,1,.235-.47.772.772,0,0,1,.549-.238.772.772,0,0,1,.549.238l.939,1.1a.675.675,0,0,1,.238.47.675.675,0,0,1-.238.47A.767.767,0,0,1,3765.626-14328.745Zm5.724-2.273a.743.743,0,0,1-.784-.785v-1.413c.157-.469.473-.784.784-.784a.743.743,0,0,1,.784.784v1.413A.743.743,0,0,1,3771.35-14331.019Z"
			transform="translate(-3761 14334.001)" />
			</svg>
			</span>
			</p>
			<p class="center">（<i>x</i>-6）［<i>x</i>-（-4）］≥0.</p>
			<p>所以不等式的解集为（-∞，-4］∪［6，+∞）.</p>
			<p>
			<span class="zt-ls"><b>例2</b></span>　解下列不等式.
			<p class="p-btn" >
			<span>（1）（<i>x</i>+1）<sup>2</sup>≥4；</span>
			<span class="btn-box" @click="isShowAnswer16 = !isShowAnswer16">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			（1）（<i>x</i>+1）<sup>2</sup>≥4；（2）（2<i>x</i>-3）<sup>2</sup>＜9.
			<div v-if="isShowAnswer16" >
			<p>
			<span class="zt-ls"><b>解</b></span>（1）
			由（<i>x</i>+1）<sup>2</sup>≥4得（<i>x</i>+1）<sup>2</sup>-2<sup>2</sup>≥0，
			</p>
			<p>从而　　［（<i>x</i>+1）+2］［（<i>x</i>+1）-2］≥0，</p>
			<p>化简得（<i>x</i>+3）（<i>x</i>-1）≥0，</p>
			<p>即　　　［<i>x</i>-（-3）］（<i>x</i>-1）≥0，</p>
			<p>所以不等式的解集为（-∞，-3］∪［1，+∞）.</p>
			</div>
			<p class="p-btn" >
			<span>（2）（2<i>x</i>-3）<sup>2</sup>＜9.</span>
			<span class="btn-box" @click="isShowAnswer17 = !isShowAnswer17">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p class="block">
			<span
			class="zt-ls2"><b>分析</b></span>　由（<i>x</i>+1）<sup>2</sup>≥4得<i>x</i><sup>2</sup>+2<i>x</i>+1≥4，即<i>x</i><sup>2</sup>+2<i>x</i>-3≥0，从而可以利用二次函数<i>y</i>=<i>x</i><sup>2</sup>+2<i>x</i>-3的图像进行求解；注意到4=2<sup>2</sup>，也可以考虑将（<i>x</i>+1）<sup>2</sup>≥4整理为（<i>x</i>+1）<sup>2</sup>-4≥0，并使用平方差公式，即（<i>x</i>+1）<sup>2</sup>-2<sup>2</sup>≥0，得到（<i>x</i>+3）（<i>x</i>-1）≥0，此时可以借助上面的结论直接求解.下面我们将使用后一种方法进行求解.
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span>（1）
			由（<i>x</i>+1）<sup>2</sup>≥4得（<i>x</i>+1）<sup>2</sup>-2<sup>2</sup>≥0，
			</p>
			<p>从而　　［（<i>x</i>+1）+2］［（<i>x</i>+1）-2］≥0，</p>
			<p>化简得（<i>x</i>+3）（<i>x</i>-1）≥0，</p>
			<p>即　　　［<i>x</i>-（-3）］（<i>x</i>-1）≥0，</p>
			<p>所以不等式的解集为（-∞，-3］∪［1，+∞）.</p>
			<p>
			（2）
			由（2<i>x</i>-3）<sup>2</sup>＜9得（2<i>x</i>-3）<sup>2</sup>-3<sup>2</sup>＜0，
			</p>
			<p>从而　　［（2<i>x</i>-3）+3］［（2<i>x</i>-3）-3］＜0，</p>
			<p>化简得　2<i>x</i>（2<i>x</i>-6）＜0，</p>
			<p>即　　　<i>x</i>（<i>x</i>-3）＜0，</p>
			<p>即（<i>x</i>-0）（<i>x</i>-3）＜0，</p>
			<p>所以不等式的解集为（0，3）.</p>
			<div v-if="isShowAnswer17" >
			<p>
			<span class="zt-ls"><b>解</b></span>
			（2）
			由（2<i>x</i>-3）<sup>2</sup>＜9得（2<i>x</i>-3）<sup>2</sup>-3<sup>2</sup>＜0，
			</p>
			<p>从而　　［（2<i>x</i>-3）+3］［（2<i>x</i>-3）-3］＜0，</p>
			<p>化简得　2<i>x</i>（2<i>x</i>-6）＜0，</p>
			<p>即　　　<i>x</i>（<i>x</i>-3）＜0，</p>
			<p>即（<i>x</i>-0）（<i>x</i>-3）＜0，</p>
			<p>所以不等式的解集为（0，3）.</p>
			</div>
			<p class="left"><img class="img-gn" alt="" src="../../assets/images/stlx.jpg" /></p>
			<div class="bj">
			<p>解下列一元二次不等式.</p>
			<p>
			（1）（<i>x</i>+2）（<i>x</i>-3）≥0；（2）（5-<i>x</i>）（4+<i>x</i>）＞0；
			</p>
			<p>
			（3）（<i>x</i>-1）<sup>2</sup>≤100；（4）（<i>x</i>+5）<sup>2</sup>＞36.
			</p>
			<examinations :cardList="questionData[56]" sourceType="json" inputBc="#d3edfa"
			v-if="questionData"></examinations>
			</div>
			</div>
			</div>
			@@ -2075,67 +2315,8 @@
			<div class="padding-116">
			<h3 id="c019">习题2.3<span class="fontsz2">＞＞＞</span></h3>
			<div class="bj">
			<p>
			<span class="bj-sp"><b>水平一</b></span>
			</p>
			<p>1.选择题.</p>
			<p>（1）下列四个不等式，其中解集为<b>R</b>的是（　）.</p>
			<p>
			①-<i>x</i><sup>2</sup>+<i>x</i>+1≥0； ②<i>x</i><sup>2</sup>-5<i>x</i>+5＞0；
			</p>
			<p>
			③<i>x</i><sup>2</sup>+6<i>x</i>+10＞0； ④2<i>x</i><sup>2</sup>-3<i>x</i>+4＜1.
			</p>
			<p>A.④</p>
			<p>B.③</p>
			<p>C.②</p>
			<p>D.①</p>
			<p>（2）不等式<i>x</i><sup>2</sup>-2<i>x</i>+1＞0的解集是（　）.</p>
			<p>A.（-∞，+∞）</p>
			<p>B.（-∞，0）∪（0，+∞）</p>
			<p>C.（0，+∞）</p>
			<p>D.（-∞，1）∪（1，+∞）</p>
			<p>2.填空题.</p>
			<p>（1）不等式<i>x</i><sup>2</sup>+3<i>x</i>+2＞0的解集是________；</p>
			<p>（2）不等式<i>x</i>（<i>x</i>-1）＜1的解集是________.</p>
			<p>3.求下列一元二次不等式的解集.</p>
			<p>
			（1） <i>x</i><sup>2</sup>＜2；（2） <i>x</i><sup>2</sup>＞5；（3）
			<i>x</i><sup>2</sup>＞<i>x</i>；
			</p>
			<p>
			（4） <i>x</i><sup>2</sup>＜2<i>x</i>；（5） <i>x</i><sup>2</sup>＞3<i>x</i>；（6） <i>x</i><sup>2</sup>≤4<i>x</i>.
			</p>
			<p>4.解下列一元二次不等式.</p>
			<p>
			（1） <i>x</i><sup>2</sup>+5<i>x</i>-6＞0；（2） <i>x</i><sup>2</sup>+4<i>x</i>-5＜0；
			</p>
			<p>
			（3） -<i>x</i><sup>2</sup>+4<i>x</i>-4≤0；（4） -<i>x</i><sup>2</sup>+3<i>x</i>＞0；
			</p>
			<p>
			（5） -3<i>x</i><sup>2</sup>+2<i>x</i>-1＞0；（6）（2-3<i>x</i>）（2<i>x</i>+1）＞2.
			</p>
			<p>
			<span class="bj-sp"><b>水平二</b></span>
			</p>
			<p>1.选择题.</p>
			<p>
			（1）
			已知集合<i>M</i>={<i>x</i>\|<i>x</i><sup>2</sup>-3<i>x</i>-28≤0}，<i>P</i>={<i>x</i>\|<i>x</i><sup>2</sup>-<i>x</i>-6＞0}，则<i>M</i>∩<i>P</i>=（　）.
			</p>
			<p>A.［-4，-2）∪（3，7］</p>
			<p>B.（-4，-2］∪［3，7）</p>
			<p>C.（-∞，-2］∪（3，+∞）</p>
			<p>D.（-∞，-2）∪［3，+∞）</p>
			<p>（2）下列不等式中，解集为（2，3］的是（　）.</p>
			<p>A.（<i>x</i>-3）（2-<i>x</i>）＞0</p>
			<p>B.（<i>x</i>-3）（2-<i>x</i>）≥0</p>
			<p>C.<i>x</i><sup>2</sup>-5<i>x</i>+6≤0</p>
			<p>D.0＜<i>x</i>-2≤1</p>
			<p>
			2.如果不等式<i>x</i><sup>2</sup>-<i>ax</i>+1＞0的解集是（-∞，+∞），求<i>a</i>的取值范围.
			</p>
			<examinations :cardList="questionData[57]" sourceType="json" inputBc="#d3edfa"
			v-if="questionData"></examinations>
			</div>
			</div>
			</div>
			@@ -2382,64 +2563,73 @@
			</li>
			</ul>
			<div class="padding-116">
			<p><b>例</b> 解不等式\|2<i>x</i>\|＜5.</p>
			<p>
			<span class="zt-ls"><b>解</b></span>
			由\|2<i>x</i>\|＜5得-5＜2<i>x</i>＜5，
			<p class="p-btn" >
			<span>
			<b>例</b> 解不等式\|2<i>x</i>\|＜5.
			</span>
			<span class="btn-box" @click="isShowAnswer18 = !isShowAnswer18">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			即　<math display="0">
			<mo>−</mo>
			<mfrac>
			<mn>5</mn>
			<mn>2</mn>
			</mfrac>
			<mo>＜</mo>
			<mi>x</mi>
			<mo>＜</mo>
			<mfrac>
			<mn>5</mn>
			<mn>2</mn>
			</mfrac>
			</math>.
			</p>
			<p>
			所以不等式的解集是<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<div v-if="isShowAnswer18" >
			<p>
			<span class="zt-ls"><b>解</b></span>
			由\|2<i>x</i>\|＜5得-5＜2<i>x</i>＜5，
			</p>
			<p>
			即　<math display="0">
			<mo>−</mo>
			<mfrac>
			<mn>5</mn>
			<mn>2</mn>
			</mfrac>
			<mo>，</mo>
			<mo>＜</mo>
			<mi>x</mi>
			<mo>＜</mo>
			<mfrac>
			<mn>5</mn>
			<mn>2</mn>
			</mfrac>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>.
			</p>
			</math>.
			</p>
			<p>
			所以不等式的解集是<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mo>−</mo>
			<mfrac>
			<mn>5</mn>
			<mn>2</mn>
			</mfrac>
			<mo>，</mo>
			<mfrac>
			<mn>5</mn>
			<mn>2</mn>
			</mfrac>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>.
			</p>
			</div>
			<div class="bk-hzjl">
			<div class="bj1-hzjl">
			<p class="left">
			<img class="img-gn2" alt="" src="../../assets/images/hzjl.jpg" />
			</p>
			</div>
			<p class="block">
			1.仿照上面的分析，你能列出\|<i>x</i>\|＜<i>a</i>（<i>a</i>＞0）和\|<i>x</i>\|≥<i>a</i>（<i>a</i>＞0）
			的解的情况吗？将你的发现与同学交流讨论.
			</p>
			<p class="block">
			2.如果把<i>a</i>＞0改为<i>a</i>＜0或者<i>a</i>=0，你能对上述不等式进行分析和求解吗？将你的发现与同学交流讨论.
			</p>
			<examinations :cardList="questionData[60] ? questionData[60][1] : []" sourceType="json"
			inputBc="#d3edfa" v-if="questionData"></examinations>
			</div>
			<p class="left"><img class="img-gn" alt="" src="../../assets/images/stlx.jpg" /></p>
			<p class="left">
			<img class="img-gn" alt="" src="../../assets/images/stlx.jpg" />
			</p>
			<div class="bj">
			<p>解下列不等式.</p>
			<p>（1） \|<i>x</i>\|≥2；（2） \|<i>x</i>\|≤3；</p>
			<p>（3） \|2<i>x</i>\|＜3；（4） \|6<i>x</i>\|＞8.</p>
			<examinations :cardList="questionData[60] ? questionData[60][2] : []" sourceType="json"
			inputBc="#d3edfa" v-if="questionData"></examinations>
			</div>
			<h3 id="c021">
			2.4.2
			@@ -2449,23 +2639,49 @@
			<p>
			求解此类不等式时，可以将<i>ax</i>+<i>b</i>看作一个整体，再利用含绝对值不等式的基本解法，去掉绝对值，然后进行求解.
			</p>
			<p>
			<span class="zt-ls"><b>例1</b></span>　解不等式\|2<i>x</i>-1\|＜5.
			<p class="p-btn" >
			<span>
			<span class="zt-ls"><b>例1</b></span>　解不等式\|2<i>x</i>-1\|＜5.
			</span>
			<span class="btn-box" @click="isShowAnswer19 = !isShowAnswer19">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span>
			由\|2<i>x</i>-1\|＜5得-5＜2<i>x</i>-1＜5，
			<div v-if="isShowAnswer19" >
			<p>
			<span class="zt-ls"><b>解</b></span>
			由\|2<i>x</i>-1\|＜5得-5＜2<i>x</i>-1＜5，
			</p>
			<p>即　-4＜2<i>x</i>＜6，</p>
			<p>　　-2＜<i>x</i>＜3.</p>
			<p>所以不等式的解集是（-2，3）.</p>
			</div>
			<p class="p-btn" >
			<span>
			<span class="zt-ls"><b>例2</b></span>　解不等式\|1-2<i>x</i>\|＜3.
			</span>
			<span class="btn-box" @click="isShowAnswer20 = !isShowAnswer20">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>即　-4＜2<i>x</i>＜6，</p>
			<p>　　-2＜<i>x</i>＜3.</p>
			<p>所以不等式的解集是（-2，3）.</p>
			<p>
			<span class="zt-ls"><b>例2</b></span>　解不等式\|1-2<i>x</i>\|＜3.
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span> 因为\|1-2<i>x</i>\|=\|2<i>x</i>-1\|，
			</p>
			<p>所以由\|1-2<i>x</i>\|＜3得\|2<i>x</i>-1\|＜3.</p>
			<div v-if="isShowAnswer20" >
			<p>
			<span class="zt-ls"><b>解</b></span> 因为\|1-2<i>x</i>\|=\|2<i>x</i>-1\|，
			</p>
			<p>所以由\|1-2<i>x</i>\|＜3得\|2<i>x</i>-1\|＜3.</p>
			<p>由\|2<i>x</i>-1\|＜3得-3＜2<i>x</i>-1＜3，</p>
			<p>即　-2＜2<i>x</i>＜4，</p>
			<p>　　-1＜<i>x</i>＜2.</p>
			<p>所以不等式的解集是（-1，2）.</p>
			</div>
			</div>
			</div>
			</div>
			@@ -2477,63 +2693,61 @@
			<li>数学.基础模块</li>
			<li>上册</li>
			</ul>

			<div class="padding-116">
			<p>由\|2<i>x</i>-1\|＜3得-3＜2<i>x</i>-1＜3，</p>
			<p>即　-2＜2<i>x</i>＜4，</p>
			<p>　　-1＜<i>x</i>＜2.</p>
			<p>所以不等式的解集是（-1，2）.</p>
			<p>
			<span class="zt-ls"><b>例3</b></span>　解不等式\|<i>x</i>+3\|≥2.
			<p class="p-btn" >
			<span>
			<span class="zt-ls"><b>例3</b></span>　解不等式\|<i>x</i>+3\|≥2.
			</span>
			<span class="btn-box" @click="isShowAnswer21 = !isShowAnswer21">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span>
			由\|<i>x</i>+3\|≥2得<i>x</i>+3≤-2或<i>x</i>+3≥2，
			<div v-if="isShowAnswer21" >
			<p>
			<span class="zt-ls"><b>解</b></span>
			由\|<i>x</i>+3\|≥2得<i>x</i>+3≤-2或<i>x</i>+3≥2，
			</p>
			<p>即　<i>x</i>≤-5或<i>x</i>≥-1.</p>
			<p>所以不等式的解集是（-∞，-5］∪［-1，+∞）.</p>
			<p>
			现在我们回到本节开始的问题，解不等式\|<i>x</i>-100\|≤3得97≤<i>x</i>≤103，解不等式\|<i>x</i>-100\|＞3得<i>x</i>＞103或<i>x</i>＜97.如果产权登记面积在97
			m<sup>2</sup>和103 m<sup>2</sup>之间（包含97 m<sup>2</sup>和103
			m<sup>2</sup>）
			时，李先生按照产权登记面积结算房款；如果产权登记面积小于97
			m<sup>2</sup>或大于103 m<sup>2</sup>时，李先生有权退房.
			</p>
			</div>
			<p class="p-btn" >
			<span>
			<span class="zt-ls"><b>例4</b></span>　解不等式\|3<i>x</i>-（<i>x</i>-2）\|≤2.
			</span>
			<span class="btn-box" @click="isShowAnswer22 = !isShowAnswer22">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>即　<i>x</i>≤-5或<i>x</i>≥-1.</p>
			<p>所以不等式的解集是（-∞，-5］∪［-1，+∞）.</p>
			<p>
			现在我们回到本节开始的问题，解不等式\|<i>x</i>-100\|≤3得97≤<i>x</i>≤103，解不等式\|<i>x</i>-100\|＞3得<i>x</i>＞103或<i>x</i>＜97.如果产权登记面积在97
			m<sup>2</sup>和103 m<sup>2</sup>之间（包含97 m<sup>2</sup>和103
			m<sup>2</sup>）
			时，李先生按照产权登记面积结算房款；如果产权登记面积小于97
			m<sup>2</sup>或大于103 m<sup>2</sup>时，李先生有权退房.
			</p>
			<p>
			<span class="zt-ls"><b>例4</b></span>　解不等式\|3<i>x</i>-（<i>x</i>-2）\|≤2.
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span>
			由\|3<i>x</i>-（<i>x</i>-2）\|≤2得\|3<i>x</i>-<i>x</i>+2\|≤2，
			</p>
			<p>即　　\|2<i>x</i>+2\|≤2，</p>
			<p>从而　-2≤2<i>x</i>+2≤2，</p>
			<p>　　　-4≤2<i>x</i>≤0，</p>
			<p>　　　-2≤<i>x</i>≤0.</p>
			<p>所以不等式的解集是［-2，0］.</p>
			<div v-if="isShowAnswer22">
			<p>
			<span class="zt-ls"><b>解</b></span>
			由\|3<i>x</i>-（<i>x</i>-2）\|≤2得\|3<i>x</i>-<i>x</i>+2\|≤2，
			</p>
			<p>即　　\|2<i>x</i>+2\|≤2，</p>
			<p>从而　-2≤2<i>x</i>+2≤2，</p>
			<p>　　　-4≤2<i>x</i>≤0，</p>
			<p>　　　-2≤<i>x</i>≤0.</p>
			<p>所以不等式的解集是［-2，0］.</p>
			</div>
			<p class="left"><img class="img-gn" alt="" src="../../assets/images/stlx.jpg" /></p>
			<div class="bj">
			<p>1.解下列不等式.</p>
			<p>（1） \|<i>x</i>+1\|≥2；（2） \|<i>x</i>-1\|≤3；</p>
			<p>（3） \|<i>x</i>-2\|＜3；（4） \|<i>x</i>+3\|＞8.</p>
			<p>2.解下列不等式.</p>
			<p>
			（1） \|3<i>x</i>-1\|≤2；（2）
			<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">\|</mo>
			<mfrac>
			<mn>1</mn>
			<mn>3</mn>
			</mfrac>
			<mi>x</mi>
			<mo data-mjx-texclass="CLOSE">\|</mo>
			</mrow>
			<mo>＞</mo>
			<mn>2</mn>
			</math>；
			</p>
			<p>（3） \|2<i>x</i>-2\|≥7；（4） \|1-3<i>x</i>\|＞2.</p>
			<examinations :cardList="questionData[61]" sourceType="json" inputBc="#d3edfa"
			v-if="questionData"></examinations>
			</div>
			</div>
			</div>
			@@ -2552,203 +2766,8 @@
			<div class="padding-116">
			<h3 id="c022">习题2.4<span class="fontsz2">＞＞＞</span></h3>
			<div class="bj">
			<p>
			<span class="bj-sp"><b>水平一</b></span>
			</p>
			<p>
			1.在数轴上，满足方程\|<i>x</i>-3\|=1的<i>x</i>对应的点到原点的距离是（　）.
			</p>
			<p>A.4</p>
			<p>B.2</p>
			<p>C.4或2</p>
			<p>D.0</p>
			<p>2.不等式\|5<i>x</i>\|＜3的解集用区间表示是（　）.</p>
			<p>
			A.<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mo>−</mo>
			<mi mathvariant="normal">∞</mi>
			<mo>，</mo>
			<mfrac>
			<mn>3</mn>
			<mn>5</mn>
			</mfrac>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>
			</p>
			<p>
			B.<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mo>−</mo>
			<mfrac>
			<mn>3</mn>
			<mn>5</mn>
			</mfrac>
			<mo>，</mo>
			<mo>+</mo>
			<mi mathvariant="normal">∞</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>
			</p>
			<p>
			C.<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mo>−</mo>
			<mfrac>
			<mn>3</mn>
			<mn>5</mn>
			</mfrac>
			<mo>，</mo>
			<mfrac>
			<mn>3</mn>
			<mn>5</mn>
			</mfrac>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>
			</p>
			<p>
			D.<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mo>−</mo>
			<mi mathvariant="normal">∞</mi>
			<mo>，</mo>
			<mo>−</mo>
			<mfrac>
			<mn>3</mn>
			<mn>5</mn>
			</mfrac>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mo>∪</mo>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mfrac>
			<mn>3</mn>
			<mn>5</mn>
			</mfrac>
			<mo>，</mo>
			<mo>+</mo>
			<mi mathvariant="normal">∞</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>
			</p>
			<p>
			3.在数轴上，<i>x</i>对应的点<i>P</i>与<i>y</i>对应的点<i>Q</i>之间的距离为______.
			</p>
			<p>4.不等式\|1-3<i>x</i>\|＞1的解集用区间表示为______.</p>
			<p>
			<span class="bj-sp"><b>水平二</b></span>
			</p>
			<p>解下列不等式.</p>
			<p>
			（1）<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">\|</mo>
			<mfrac>
			<mrow>
			<mn>1</mn>
			<mo>−</mo>
			<mn>3</mn>
			<mi>x</mi>
			</mrow>
			<mn>3</mn>
			</mfrac>
			<mo data-mjx-texclass="CLOSE">\|</mo>
			</mrow>
			<mo>＞</mo>
			<mn>1</mn>
			</math>；（2）<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">\|</mo>
			<mfrac>
			<mn>1</mn>
			<mn>2</mn>
			</mfrac>
			<mo>−</mo>
			<mn>3</mn>
			<mi>x</mi>
			<mo data-mjx-texclass="CLOSE">\|</mo>
			</mrow>
			<mo>≥</mo>
			<mn>3</mn>
			</math>；（3）<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">\|</mo>
			<mn>2</mn>
			<mi>x</mi>
			<mo>−</mo>
			<mfrac>
			<mn>1</mn>
			<mn>3</mn>
			</mfrac>
			<mo data-mjx-texclass="CLOSE">\|</mo>
			</mrow>
			<mo>＜</mo>
			<mfrac>
			<mn>1</mn>
			<mn>2</mn>
			</mfrac>
			</math>；
			</p>
			<p>
			（4）<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">\|</mo>
			<mfrac>
			<mn>2</mn>
			<mn>5</mn>
			</mfrac>
			<mi>x</mi>
			<mo>−</mo>
			<mn>2</mn>
			<mo data-mjx-texclass="CLOSE">\|</mo>
			</mrow>
			<mo>≥</mo>
			<mn>1</mn>
			</math>；（5）<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">\|</mo>
			<mfrac>
			<mn>1</mn>
			<mn>3</mn>
			</mfrac>
			<mi>x</mi>
			<mo>−</mo>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mi>x</mi>
			<mo>−</mo>
			<mn>2</mn>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mo data-mjx-texclass="CLOSE">\|</mo>
			</mrow>
			<mo>≤</mo>
			<mn>2</mn>
			</math>；（6）<math display="0">
			<mn>4</mn>
			<mo>≤</mo>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">\|</mo>
			<mn>5</mn>
			<mo>−</mo>
			<mfrac>
			<mn>2</mn>
			<mn>3</mn>
			</mfrac>
			<mi>x</mi>
			<mo data-mjx-texclass="CLOSE">\|</mo>
			</mrow>
			</math>.
			</p>
			<examinations :cardList="questionData[62]" sourceType="json" inputBc="#d3edfa"
			v-if="questionData"></examinations>
			</div>
			<h2 id="b011">
			2.5 不等式的应用<span class="fontsz1">＞＞＞＞＞＞＞＞</span>
			@@ -2758,11 +2777,20 @@
			</h3>
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0066-11.jpg" /></p>
			<p class="img">图2-12</p>
			<p>
			<span class="zt-ls"><b>例1</b></span>　用篱笆在墙边围一块矩形小花坛，其中一边靠墙（如图2-12所示），篱笆总长为8m.若小花坛的面积不小于6
			m<sup>2</sup>，则小花坛垂直于墙的一边的长度范围是多少？
			<p class="p-btn" >
			<span>
			<span class="zt-ls"><b>例1</b></span>　用篱笆在墙边围一块矩形小花坛，其中一边靠墙（如图2-12所示），篱笆总长为8m.若小花坛的面积不小于6
			m<sup>2</sup>，则小花坛垂直于墙的一边的长度范围是多少？
			</span>
			<span class="btn-box" @click="isShowAnswer23 = !isShowAnswer23">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			<p v-if="isShowAnswer23" >
			<span class="zt-ls"><b>解</b></span>
			设小花坛垂直于墙的一边的长度为<i>x</i>（m），则与墙平行的一边的长度为（8-2<i>x</i>）m.考虑到实际情况，有<i>x</i>＞0，并且8-2<i>x</i>＞0，所以<i>x</i>满足0＜<i>x</i>＜4.
			</p>
			@@ -2778,32 +2806,46 @@
			<li>上册</li>
			</ul>
			<div class="padding-116">
			<p>设小花坛的面积为<i>S</i>（m<sup>2</sup>），则</p>
			<p class="center"><i>S</i>=<i>x</i>（8-2<i>x</i>），</p>
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0067-1.jpg" /></p>
			<p class="img">图2-13</p>
			<p>整理得 <i>S</i>=-2<i>x</i><sup>2</sup>+8<i>x</i>.</p>
			<p>
			由题意得 <i>S</i>=-2<i>x</i><sup>2</sup>+8<i>x</i>≥6，即<i>x</i><sup>2</sup>-4<i>x</i>+3≤0.
			</p>
			<p>
			画出二次函数<i>y</i>=<i>x</i><sup>2</sup>-4<i>x</i>+3的简图（如图2-13所示）.
			</p>
			<p>由图像得不等式的解为{<i>x</i>\|1≤<i>x</i>≤3}.</p>
			<p>结合0＜<i>x</i>＜4，得</p>
			<p class="center">
			{<i>x</i>\|0＜<i>x</i>＜4}∩{<i>x</i>\|1≤<i>x</i>≤3}={<i>x</i>\|1≤<i>x</i>≤3}.
			</p>
			<p>所以小花坛垂直于墙的一边的长度在1m至3m之间（含1m和3m）.</p>
			<p>
			<span
			<div v-if="isShowAnswer23">
			<p>设小花坛的面积为<i>S</i>（m<sup>2</sup>），则</p>
			<p class="center"><i>S</i>=<i>x</i>（8-2<i>x</i>），</p>
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0067-1.jpg" /></p>
			<p class="img">图2-13</p>
			<p>整理得 <i>S</i>=-2<i>x</i><sup>2</sup>+8<i>x</i>.</p>
			<p>
			由题意得 <i>S</i>=-2<i>x</i><sup>2</sup>+8<i>x</i>≥6，即<i>x</i><sup>2</sup>-4<i>x</i>+3≤0.
			</p>
			<p>
			画出二次函数<i>y</i>=<i>x</i><sup>2</sup>-4<i>x</i>+3的简图（如图2-13所示）.
			</p>
			<p>由图像得不等式的解为{<i>x</i>\|1≤<i>x</i>≤3}.</p>
			<p>结合0＜<i>x</i>＜4，得</p>
			<p class="center">
			{<i>x</i>\|0＜<i>x</i>＜4}∩{<i>x</i>\|1≤<i>x</i>≤3}={<i>x</i>\|1≤<i>x</i>≤3}.
			</p>
			<p>所以小花坛垂直于墙的一边的长度在1m至3m之间（含1m和3m）.</p>
			</div>
			<p class="p-btn" >
			<span>
			<span
			class="zt-ls"><b>例2</b></span>　某网店销售一种电动玩具，成本为10元/个.平时按单价20元销售，日平均销售量为100个.为进一步提升业绩，该网店决定在“双11”期间举办降价促销活动.根据以往的统计，如果该电动玩具的单价每降低0.5元，日平均销售量就会大约增加10个.为了使促销活动期间日平均利润不低于平时，应如何确定降价的范围？
			</span>
			<span class="btn-box" @click="isShowAnswer24 = !isShowAnswer24">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			<span class="btn-box" @click="openDialog(thinkThree)">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.545" height="18.112" viewBox="0 0 20.545 22.112">
			<path class="a"
			d="M3771.2-14311.889a2.356,2.356,0,0,1-1.727-.626c-.027-.054-.053-.1-.079-.148l0-.007c-.123-.224-.2-.371-.076-.629a.869.869,0,0,1,.784-.471.205.205,0,0,1,.158.079.205.205,0,0,0,.158.079.187.187,0,0,0,.038.1.143.143,0,0,0,.117.05h.158a.573.573,0,0,0,.471.158,2.2,2.2,0,0,0,.916-.3l.023-.011a.572.572,0,0,1,.471-.158.575.575,0,0,1,.626.626.526.526,0,0,1,.036.409.664.664,0,0,1-.349.375A3.582,3.582,0,0,1,3771.2-14311.889Zm-1.885-1.723h-.155a.718.718,0,0,1-.784-.63.38.38,0,0,1-.021-.3.976.976,0,0,1,.492-.485l4.86-1.252a1.047,1.047,0,0,1,.784.626c.151.3-.128.61-.471.784l-4.705,1.256Zm-.155-1.885H3769a.716.716,0,0,1-.784-.626c-.149-.3.129-.611.471-.784l4.234-1.1v-.158l-.021.007a7.808,7.808,0,0,1-1.861.31,5.3,5.3,0,0,1-3.137-.942,5.789,5.789,0,0,1-2.666-4.076,6.421,6.421,0,0,1,1.256-5.018,7.038,7.038,0,0,1,2.194-1.568,7.848,7.848,0,0,1,2.666-.472,6.43,6.43,0,0,1,2.979.784,4.958,4.958,0,0,1,2.2,2.194,5.522,5.522,0,0,1,.313,5.177,13.113,13.113,0,0,1-1.256,1.882l-.313.313a2.156,2.156,0,0,0-.78,1.244l0,.012a1.731,1.731,0,0,1-1.727,1.723l-.313.158-3.292.939Zm1.256-6.271v1.256h1.41v-1.256Zm.784-4.234c.718,0,1.1.271,1.1.784a.925.925,0,0,1-.316.783l-.468.156a2.235,2.235,0,0,0-.63.471l-.012.024a2.2,2.2,0,0,0-.3.918v.155h1.1v-.155a1.2,1.2,0,0,1,.313-.629.543.543,0,0,0,.315-.153c.007,0,.315,0,.315-.16a1.226,1.226,0,0,0,.626-.626,2.277,2.277,0,0,0,.313-1.1,1.409,1.409,0,0,0-.626-1.252,2.337,2.337,0,0,0-1.569-.471,2.258,2.258,0,0,0-2.507,2.353l1.252.154A1.121,1.121,0,0,1,3771.2-14326Zm-6.51,9.645a.769.769,0,0,1-.549-.237.772.772,0,0,1-.235-.549.772.772,0,0,1,.235-.548l.939-.939a.781.781,0,0,1,.55-.234.772.772,0,0,1,.547.234.772.772,0,0,1,.238.549.772.772,0,0,1-.238.549l-.939.938A.769.769,0,0,1,3764.686-14316.356Zm13.174-.157a.774.774,0,0,1-.549-.234l-.943-.942a.678.678,0,0,1-.233-.47.678.678,0,0,1,.233-.47.774.774,0,0,1,.549-.234.774.774,0,0,1,.549.234l.942.939a.427.427,0,0,1,.228.324.74.74,0,0,1-.228.618A.774.774,0,0,1,3777.859-14316.514Zm2.9-6.351h-1.414c-.469-.158-.784-.474-.784-.784a.743.743,0,0,1,.784-.784h1.414a.743.743,0,0,1,.784.784A.743.743,0,0,1,3780.761-14322.864Zm-17.566-.158h-1.41c-.469-.157-.784-.473-.784-.784a.743.743,0,0,1,.784-.784h1.41a.743.743,0,0,1,.784.784A.743.743,0,0,1,3763.195-14323.022Zm13.861-5.723a.759.759,0,0,1-.529-.237.776.776,0,0,1-.235-.549.772.772,0,0,1,.235-.549l.939-.938a.44.44,0,0,1,.413-.238.759.759,0,0,1,.529.238.772.772,0,0,1,.235.549.772.772,0,0,1-.235.548l-.942.939A.435.435,0,0,1,3777.055-14328.745Zm-11.429,0a.776.776,0,0,1-.55-.237l-.939-1.1a.678.678,0,0,1-.235-.469.678.678,0,0,1,.235-.47.772.772,0,0,1,.549-.238.772.772,0,0,1,.549.238l.939,1.1a.675.675,0,0,1,.238.47.675.675,0,0,1-.238.47A.767.767,0,0,1,3765.626-14328.745Zm5.724-2.273a.743.743,0,0,1-.784-.785v-1.413c.157-.469.473-.784.784-.784a.743.743,0,0,1,.784.784v1.413A.743.743,0,0,1,3771.35-14331.019Z"
			transform="translate(-3761 14334.001)" />
			</svg>
			</span>
			</p>
			<p class="block">
			<span
			class="zt-ls2"><b>分析</b></span>　利润=（销售单价-成本单价）×销售量.降价过程中，单价降低能够使销售量变大，但也使销售单价与成本单价的差减小，所以降价的范围应保证利润不低于促销前.
			</p>
			<div class="bk">
			<div class="bk mt-60" >
			<div class="bj1">
			<p class="left">
			<img class="img-gn1" alt="" src="../../assets/images/tbts.jpg" />
			@@ -2813,41 +2855,42 @@
			由例1和例2可知，在解决与一元二次不等式有关的实际问题时，不仅要解一元二次不等式，而且要考虑实际背景对未知数的限制.在例1中，实际背景对未知数的限制是0＜<i>x</i>＜4；在例2中，实际背景对未知数的限制是0＜<i>x</i>＜10.
			</p>
			</div>
			<p>
			<span class="zt-ls"><b>解</b></span>
			假设降价<i>x</i>元.考虑到实际情况，价格的降幅应小于10元，即保证销售价高于成本价，所以要求<i>x</i>＞0并且<i>x</i>＜10，即0＜<i>x</i>＜10.
			</p>
			<p>平时的日平均利润为（20-10）×100=1 000（元）.</p>
			<p>
			降价<i>x</i>元后，销售单价为（20-<i>x</i>）元，单个玩具的利润为（20-<i>x</i>）-10=（10-<i>x</i>）元，日平均销售量为<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mn>100</mn>
			<mo>+</mo>
			<mfrac>
			<mn>10</mn>
			<mn>0.5</mn>
			</mfrac>
			<mi>x</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>个.因此，降价<i>x</i>元后的日平均利润为（10-<i>x</i>）（100+20<i>x</i>）元.
			</p>
			<p>由题意得（10-<i>x</i>）（100+20<i>x</i>）≥1 000.</p>
			<p>化简得<i>x</i><sup>2</sup>-5<i>x</i>≤0，即<i>x</i>（<i>x</i>-5）≤0.</p>
			<p>所以不等式的解集为 {<i>x</i>\|0≤<i>x</i>≤5}.</p>
			<p>
			由于0＜<i>x</i>＜10，所以<i>x</i>的范围是{<i>x</i>\|0＜<i>x</i>＜10}∩{<i>x</i>\|0≤<i>x</i>≤5}，即{<i>x</i>\|0＜<i>x</i>≤5}.所以降价的范围应在0至5元之间（含5元，不含0元），即单价定在15元至20元之间（含15元，不含20元），便能满足要求.
			</p>
			<div v-if="isShowAnswer24">
			<p>
			<span class="zt-ls"><b>解</b></span>
			假设降价<i>x</i>元.考虑到实际情况，价格的降幅应小于10元，即保证销售价高于成本价，所以要求<i>x</i>＞0并且<i>x</i>＜10，即0＜<i>x</i>＜10.
			</p>
			<p>平时的日平均利润为（20-10）×100=1 000（元）.</p>
			<p>
			降价<i>x</i>元后，销售单价为（20-<i>x</i>）元，单个玩具的利润为（20-<i>x</i>）-10=（10-<i>x</i>）元，日平均销售量为<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mn>100</mn>
			<mo>+</mo>
			<mfrac>
			<mn>10</mn>
			<mn>0.5</mn>
			</mfrac>
			<mi>x</mi>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			</math>个.因此，降价<i>x</i>元后的日平均利润为（10-<i>x</i>）（100+20<i>x</i>）元.
			</p>
			<p>由题意得（10-<i>x</i>）（100+20<i>x</i>）≥1 000.</p>
			<p>化简得<i>x</i><sup>2</sup>-5<i>x</i>≤0，即<i>x</i>（<i>x</i>-5）≤0.</p>
			<p>所以不等式的解集为 {<i>x</i>\|0≤<i>x</i>≤5}.</p>
			<p>
			由于0＜<i>x</i>＜10，所以<i>x</i>的范围是{<i>x</i>\|0＜<i>x</i>＜10}∩{<i>x</i>\|0≤<i>x</i>≤5}，即{<i>x</i>\|0＜<i>x</i>≤5}.所以降价的范围应在0至5元之间（含5元，不含0元），即单价定在15元至20元之间（含15元，不含20元），便能满足要求.
			</p>
			</div>
			<div class="bk-hzjl">
			<div class="bj1-hzjl">
			<p class="left">
			<img class="img-gn2" alt="" src="../../assets/images/hzjl.jpg" />
			</p>
			</div>
			<p class="block">
			例2中，当<i>x</i>=__元时，利润最大，也就是说，降价__元，即定价__元时，利润最大，最大利润是__元，与同学进行交流.
			</p>
			<examinations :cardList="questionData[63]" sourceType="json" v-if="questionData">
			</examinations>
			</div>
			</div>
			</div>
			@@ -2863,49 +2906,52 @@
			<p><span>057</span></p>
			</li>
			</ul>

			<div class="padding-116">
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0068-1.jpg" /></p>
			<p class="img">第2题图</p>
			<p class="left"><img class="img-gn" alt="" src="../../assets/images/stlx.jpg" /></p>
			<div class="bj">
			<p>
			1.某工厂生产一种产品的总利润<i>y</i>（万元）与产量<i>x</i>（kg
			）满足函数关系：<i>y</i>=-<i>x</i><sup>2</sup>+300<i>x</i>-100，0＜<i>x</i>＜200.如果要使利润超过8
			000万元，那么产量应达到的范围是多少？
			</p>
			<p>
			2.用长度为8m的铝合金材料，做一个日字形两开窗，如图所示.要求窗户的面积不少于2m<sup>2</sup>.如何设计窗户的高度，才能满足要求？（日字形两开窗中间窗棂的宽度忽略不计）
			</p>
			<examinations :cardList="questionData[64]" sourceType="json" v-if="questionData">
			</examinations>
			</div>
			<h3 id="c024">
			2.5.2 不等式与复杂实际问题<span class="fontsz2">＞＞＞</span>
			</h3>
			<p>
			<span
			class="zt-ls"><b>例1</b></span>　我国交通法规对小型汽车驾驶员的年龄限制如下：最低年龄18周岁，最高年龄70周岁.已有研究表明，小型汽车驾驶员对红绿灯变化的反应时间<i>y</i>（ms）
			与驾驶员年龄<i>x</i>（周岁）
			的关系为<i>y</i>=0.005<i>x</i><sup>2</sup>-0.2<i>x</i>+22，其中18≤<i>x</i>≤70.问：反应时间超过24.5ms的驾驶员所处的年龄范围是多少？
			<p class="p-btn" >
			<span>
			<span
			class="zt-ls"><b>例1</b></span>　我国交通法规对小型汽车驾驶员的年龄限制如下：最低年龄18周岁，最高年龄70周岁.已有研究表明，小型汽车驾驶员对红绿灯变化的反应时间<i>y</i>（ms）
			与驾驶员年龄<i>x</i>（周岁）
			的关系为<i>y</i>=0.005<i>x</i><sup>2</sup>-0.2<i>x</i>+22，其中18≤<i>x</i>≤70.问：反应时间超过24.5ms的驾驶员所处的年龄范围是多少？
			</span>
			<span class="btn-box" @click="isShowAnswer25 = !isShowAnswer25">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p>
			<span class="zt-ls"><b>解</b></span> 由题意得，<i>y</i>=0.005<i>x</i><sup>2</sup>-0.2<i>x</i>+22＞24.5，即
			</p>
			<p>　　　　　0.005<i>x</i><sup>2</sup>-0.2<i>x</i>-2.5＞0.</p>
			<p>化简得 <i>x</i><sup>2</sup>-40<i>x</i>-500＞0.</p>
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0068-2.jpg" /></p>
			<p class="img">图2-14</p>
			<p>
			考查二次函数<i>y</i>=<i>x</i><sup>2</sup>-40<i>x</i>-500，<i>a</i>=1＞0，<i>Δ</i>=<i>b</i><sup>2</sup>-4<i>ac</i>=（-40）<sup>2</sup>-4×1×（-500）=3
			600＞0，所以二次函数<i>y</i>=<i>x</i><sup>2</sup>-40<i>x</i>-500的图像开口向上，并且与<i>x</i>轴有两个交点.其简图如图2-14所示.
			</p>
			<p>
			由图像可知，不等式<i>x</i><sup>2</sup>-40<i>x</i>-500＞0的解集为（-∞，-10）∪（50，+∞），这也是不等式0.005<i>x</i><sup>2</sup>-0.2<i>x</i>-2.5＞0的解集.
			</p>
			<p>
			考虑到18≤<i>x</i>≤70，所以<i>x</i>的范围是（50，70］，即反应时间超过24.5
			<i>ms</i>
			的驾驶员所处的年龄范围在50岁至70岁之间（不包含50岁，包含70岁）.
			</p>
			<div v-if="isShowAnswer25" >
			<p>
			<span class="zt-ls"><b>解</b></span> 由题意得，<i>y</i>=0.005<i>x</i><sup>2</sup>-0.2<i>x</i>+22＞24.5，即
			</p>
			<p>　　　　　0.005<i>x</i><sup>2</sup>-0.2<i>x</i>-2.5＞0.</p>
			<p>化简得 <i>x</i><sup>2</sup>-40<i>x</i>-500＞0.</p>
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0068-2.jpg" /></p>
			<p class="img">图2-14</p>
			<p>
			考查二次函数<i>y</i>=<i>x</i><sup>2</sup>-40<i>x</i>-500，<i>a</i>=1＞0，<i>Δ</i>=<i>b</i><sup>2</sup>-4<i>ac</i>=（-40）<sup>2</sup>-4×1×（-500）=3
			600＞0，所以二次函数<i>y</i>=<i>x</i><sup>2</sup>-40<i>x</i>-500的图像开口向上，并且与<i>x</i>轴有两个交点.其简图如图2-14所示.
			</p>
			<p>
			由图像可知，不等式<i>x</i><sup>2</sup>-40<i>x</i>-500＞0的解集为（-∞，-10）∪（50，+∞），这也是不等式0.005<i>x</i><sup>2</sup>-0.2<i>x</i>-2.5＞0的解集.
			</p>
			<p>
			考虑到18≤<i>x</i>≤70，所以<i>x</i>的范围是（50，70］，即反应时间超过24.5
			<i>ms</i>
			的驾驶员所处的年龄范围在50岁至70岁之间（不包含50岁，包含70岁）.
			</p>
			</div>

			<p>
			<span class="zt-ls"><b>例2</b></span>　身体质量指数（Body Mass
			Index，BMI）是衡量人体胖瘦程度的一个常用标准，计算公式为<math display="0">
			@@ -2941,52 +2987,61 @@
			<li>数学.基础模块</li>
			<li>上册</li>
			</ul>

			<div class="padding-116">
			<p>
			生的身体素质，该指标是指学生参加50m跑，立定跳远，力量（男生引体向上、女生1分钟仰卧起坐），耐力跑（男生1
			000m跑、女生800m跑），坐位体前屈等项目的成绩总和.身体素质指标为正数说明身体素质较好.上述研究发现，身体素质指标（<i>y</i>）与BMI（<i>x</i>）
			之间的关系如表2-7所示.
			</p>
			<p>问：身体素质较好的男生和女生，其BMI的范围分别是多少？</p>
			<p class="p-btn" >
			问：身体素质较好的男生和女生，其BMI的范围分别是多少？
			<span class="btn-box" @click="isShowAnswer26 = !isShowAnswer26">
			<svg xmlns="http://www.w3.org/2000/svg" width="16.501" height="16.501" viewBox="0 0 20.501 20.501">
			<path class="a"
			d="M3344.717-15308.5H3337.4a10.186,10.186,0,0,1-7.25-3,10.185,10.185,0,0,1-3-7.25A10.262,10.262,0,0,1,3337.4-15329a10.26,10.26,0,0,1,10.249,10.248,10.129,10.129,0,0,1-2.2,6.341v3.177A.734.734,0,0,1,3344.717-15308.5Zm-9.606-7.29h4.493l.527,1.419c.071.182.156.386.254.608a2.428,2.428,0,0,0,.273.512.986.986,0,0,0,.315.262.971.971,0,0,0,.454.1,1.05,1.05,0,0,0,.773-.327,1.025,1.025,0,0,0,.319-.723,3.3,3.3,0,0,0-.277-1.051l-.062-.161-2.889-7.313c-.119-.321-.228-.607-.335-.873a2.972,2.972,0,0,0-.323-.616,1.56,1.56,0,0,0-.5-.469,1.552,1.552,0,0,0-.781-.181,1.535,1.535,0,0,0-.773.181,1.475,1.475,0,0,0-.5.477,3.674,3.674,0,0,0-.362.739l-.239.627-.054.135-2.824,7.355c-.095.229-.179.46-.25.688a1.529,1.529,0,0,0-.073.477.978.978,0,0,0,.323.72,1.039,1.039,0,0,0,.746.315.838.838,0,0,0,.716-.3,4.676,4.676,0,0,0,.466-.985l.062-.165.527-1.449Zm3.747-1.5h-3.293l1.812-5.124,1.481,5.123Z"
			transform="translate(-3327.144 15329)" />
			</svg>
			</span>
			</p>
			<p class="img">表2-7</p>
			<p class="center"><img class="img-a" alt="" src="../../assets/images/0069-1.jpg" /></p>
			<p>
			<span class="zt-ls"><b>解</b></span>
			先考虑男生的情况.由题意得，<i>y</i>=-0.05<i>x</i><sup>2</sup>+2<i>x</i>-19.2＞0，即
			</p>
			<p class="center">0.05<i>x</i><sup>2</sup>-2<i>x</i>+19.2＜0.</p>
			<p>化简得　<i>x</i><sup>2</sup>-40<i>x</i>+384＜0.</p>
			<p>
			考查二次函数<i>y</i>=<i>x</i><sup>2</sup>-40<i>x</i>+384，<i>a</i>=1＞0，<i>Δ</i>=<i>b</i><sup>2</sup>-4<i>ac</i>=40<sup>2</sup>-4×1×384=64＞0，所以二次函数<i>y</i>=<i>x</i><sup>2</sup>-40<i>x</i>+384的图像开口向上，与<i>x</i>轴有两个交点.
			</p>
			<p>
			所以不等式<i>x</i><sup>2</sup>-40<i>x</i>+384＜0的解集为（16，24），这也是不等式-0.05<i>x</i><sup>2</sup>+2<i>x</i>-19.2＞0的解集.
			</p>
			<p>
			再考虑女生的情况.由题意得，<i>y</i>=-0.01<i>x</i><sup>2</sup>+0.39<i>x</i>-3.68＞0，即
			</p>
			<p class="center">0.01<i>x</i><sup>2</sup>-0.39<i>x</i>+3.68＜0.</p>
			<p>化简得　<i>x</i><sup>2</sup>-39<i>x</i>+368＜0.</p>
			<p>
			考查二次函数<i>y</i>=<i>x</i><sup>2</sup>-39<i>x</i>+368，<i>a</i>=1＞0，<i>Δ</i>=<i>b</i><sup>2</sup>-4<i>ac</i>=（-39）<sup>2</sup>-4×1×368=49＞0，所以二次函数<i>y</i>=<i>x</i><sup>2</sup>-39<i>x</i>+368的图像开口向上，与<i>x</i>轴有两个交点.
			</p>
			<p>
			所以不等式<i>x</i><sup>2</sup>-39<i>x</i>+368＜0的解集为（16，23），这也是不等式-0.01<i>x</i><sup>2</sup>+0.39<i>x</i>-3.68＞0的解集.
			</p>
			<p>
			因此，身体素质较好的男生BMI 的范围是（16，24），身体素质较好的女生BMI
			的范围是（16，23）.
			</p>
			<div v-if="isShowAnswer26" >
			<p>
			<span class="zt-ls"><b>解</b></span>
			先考虑男生的情况.由题意得，<i>y</i>=-0.05<i>x</i><sup>2</sup>+2<i>x</i>-19.2＞0，即
			</p>
			<p class="center">0.05<i>x</i><sup>2</sup>-2<i>x</i>+19.2＜0.</p>
			<p>化简得　<i>x</i><sup>2</sup>-40<i>x</i>+384＜0.</p>
			<p>
			考查二次函数<i>y</i>=<i>x</i><sup>2</sup>-40<i>x</i>+384，<i>a</i>=1＞0，<i>Δ</i>=<i>b</i><sup>2</sup>-4<i>ac</i>=40<sup>2</sup>-4×1×384=64＞0，所以二次函数<i>y</i>=<i>x</i><sup>2</sup>-40<i>x</i>+384的图像开口向上，与<i>x</i>轴有两个交点.
			</p>
			<p>
			所以不等式<i>x</i><sup>2</sup>-40<i>x</i>+384＜0的解集为（16，24），这也是不等式-0.05<i>x</i><sup>2</sup>+2<i>x</i>-19.2＞0的解集.
			</p>
			<p>
			再考虑女生的情况.由题意得，<i>y</i>=-0.01<i>x</i><sup>2</sup>+0.39<i>x</i>-3.68＞0，即
			</p>
			<p class="center">0.01<i>x</i><sup>2</sup>-0.39<i>x</i>+3.68＜0.</p>
			<p>化简得　<i>x</i><sup>2</sup>-39<i>x</i>+368＜0.</p>
			<p>
			考查二次函数<i>y</i>=<i>x</i><sup>2</sup>-39<i>x</i>+368，<i>a</i>=1＞0，<i>Δ</i>=<i>b</i><sup>2</sup>-4<i>ac</i>=（-39）<sup>2</sup>-4×1×368=49＞0，所以二次函数<i>y</i>=<i>x</i><sup>2</sup>-39<i>x</i>+368的图像开口向上，与<i>x</i>轴有两个交点.
			</p>
			<p>
			所以不等式<i>x</i><sup>2</sup>-39<i>x</i>+368＜0的解集为（16，23），这也是不等式-0.01<i>x</i><sup>2</sup>+0.39<i>x</i>-3.68＞0的解集.
			</p>
			<p>
			因此，身体素质较好的男生BMI 的范围是（16，24），身体素质较好的女生BMI
			的范围是（16，23）.
			</p>
			</div>
			<div class="bk-hzjl">
			<div class="bj1-hzjl">
			<p class="left">
			<img class="img-gn2" alt="" src="../../assets/images/hzjl.jpg" />
			</p>
			</div>
			<p class="block">
			小组合作收集用一元二次不等式解决的实际问题，并探究解决这类问题的一般步骤和注意事项.
			</p>
			<examinations :cardList="questionData[65]" sourceType="json" v-if="questionData">
			</examinations>
			</div>
			</div>
			</div>
			@@ -2999,135 +3054,29 @@
			<p>第二单元不等式</p>
			</li>
			<li>
			<p><span>059</span></p>
			<p><span>059-060</span></p>
			</li>
			</ul>
			<div class="padding-116">
			<p class="left"><img class="img-gn" alt="" src="../../assets/images/stlx.jpg" /></p>
			<p class="left">
			<img class="img-gn" alt="" src="../../assets/images/stlx.jpg" />
			</p>
			<div class="bj">
			<p>
			如图，在运动会标枪项目中，运动员将标枪掷出后，设标枪在飞行过程中距离地面的高度为<i>y</i>（m），标枪飞出的水平距离为<i>x</i>（m），若<i>y</i>与<i>x</i>之间的关系是：
			</p>
			<math display="block">
			<mi>y</mi>
			<mo>=</mo>
			<mo>−</mo>
			<mfrac>
			<mn>1</mn>
			<mn>16</mn>
			</mfrac>
			<msup>
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">(</mo>
			<mi>x</mi>
			<mo>−</mo>
			<mn>13</mn>
			<mo data-mjx-texclass="CLOSE">)</mo>
			</mrow>
			<mrow>
			<mn>2</mn>
			</mrow>
			</msup>
			<mo>+</mo>
			<mfrac>
			<mn>49</mn>
			<mn>4</mn>
			</mfrac>
			<mo>，</mo>
			<mn>0</mn>
			<mo>≤</mo>
			<mi>x</mi>
			<mo>≤</mo>
			<mn>27.</mn>
			</math>
			<p>问：标枪飞出的水平距离在什么范围时，标枪距离地面的高度超过3.75m？</p>
			<p class="center">
			<img class="img-c" alt="" src="../../assets/images/0070-2.jpg" />
			</p>
			<examinations :cardList="questionData[66] ? questionData[66][1] : []" sourceType="json"
			inputBc="#d3edfa" v-if="questionData"></examinations>
			</div>
			<h3 id="c025">习题2.5<span class="fontsz2">＞＞＞</span></h3>
			<div class="bj">
			<p>
			<span class="bj-sp"><b>水平一</b></span>
			</p>
			<p>
			1.一家快递仓库的地面为正方形，原有面积100
			m<sup>2</sup>，因业务量增加，现在需要在仓库增加一块长方形区域（如图所示）.如果希望扩建后仓库的总面积不小于300
			m<sup>2</sup>，那么<i>x</i>的范围是多少？
			</p>
			<p class="center">
			<img class="img-c" alt="" src="../../assets/images/0070-3.jpg" />
			</p>
			<p class="img">第1题图</p>
			<p class="center">
			<img class="img-c" alt="" src="../../assets/images/0070-4.jpg" />
			</p>
			<p class="img">第2题图</p>
			<p>
			2.某度假酒店计划设计一个小型户外游泳池，长6 m、宽3 m
			，同时希望在游泳池四周设计宽度为<i>x</i>（m）的平台（如图所示）.如果平台的总面积不超过22
			m<sup>2</sup>，则<i>x</i>的范围是多少？
			</p>
			<p>
			3.某服装公司生产一种服装，利润<i>y</i>（元）与销售单价<i>x</i>（元）之间的关系是<i>y</i>=-10<i>x</i><sup>2</sup>+1 500<i>x</i>-50
			000，那么单价在什么范围时利润会大于零？
			</p>
			<examinations :cardList="questionData[66] ? questionData[66][2] : []" sourceType="json"
			v-if="questionData">
			</examinations>
			</div>
			</div>
			</div>
			</div>
			<!-- 060 -->
			<div class="page-box" page="67">
			<div v-if="showPageList.indexOf(67) > -1">
			<ul class="page-header-odd fl al-end">
			<li>060</li>
			<li>数学.基础模块</li>
			<li>上册</li>
			</ul>
			<div class="padding-116">
			<div class="bj">
			<p>
			4.某中等职业学校毕业生小孙到某公司应聘，公司要他为一个长3 m、宽2 m
			的工作台设计一块长方形台布，作为考核他的项目.具体要求是：台布的面积不超过台面面积的
			2
			倍，且使台布四边垂下的长度相等，如图所示.问：垂下的长度应该在什么范围内？
			</p>
			<p class="center">
			<img class="img-c" alt="" src="../../assets/images/0071-1.jpg" />
			</p>
			<p class="img">第4题图</p>
			<p>
			<span class="bj-sp"><b>水平二</b></span>
			</p>
			<p>
			1.某种鱼在出生后的40天内，身长<i>L</i>（cm ）
			与其出生的天数<i>x</i>（天）满足下列函数关系：
			</p>
			<p class="center">
			<i>L</i>=0.002<i>x</i><sup>2</sup>+0.15<i>x</i>+2.3，0≤<i>x</i>≤40.
			</p>
			<p>问：该种鱼出生多少天时身长会在4～10 cm ？</p>
			<p>
			2.矮寨大桥是湖南省湘西土家族苗族自治州境内的高速通道，位于德夯大峡谷之上.大桥上的索缆和桥面的距离<i>y</i>（m）与索缆和大桥起点的水平距离<i>x</i>（m）满足<i>y</i>=0.000
			2（<i>x</i>-890）<sup>2</sup>+8，0≤<i>x</i>≤1
			780.大桥上有部分桥面上方的索缆距离桥面距离大于58
			m，那么这部分桥面的总长度是多少？
			</p>
			<p class="center">
			<img class="img-c" alt="" src="../../assets/images/0071-2.jpg" />
			</p>
			<p class="img">第2题图</p>
			<p>
			3.已有研究表明，小型汽车驾驶员对红绿灯变化的反应时间<i>y</i><sub>1</sub>（ms）与驾驶员年龄<i>x</i>（周岁）
			的关系为<i>y</i><sub>1</sub>=0.005<i>x</i><sup>2</sup>-0.2<i>x</i>+22，18≤<i>x</i>≤70，对消防车警笛的反应时间<i>y</i><sub>2</sub>2（<i>ms</i>
			）与驾驶员年龄<i>x</i>（周岁）的关系为<i>y</i><sub>2</sub>=0.005 1<i>x</i><sup>2</sup>-0.3<i>x</i>+15，18≤<i>x</i>≤70.
			</p>
			<p>
			问：哪个年龄段的驾驶员对红绿灯变化的反应时间要长于对消防车警笛的反应时间？
			</p>
			</div>
			</div>
			</div>
			<div class="page-box hidePage" page="67">

			</div>
			<!-- 061 -->
			<div class="page-box" page="68">
			@@ -3532,11 +3481,10 @@
			<p><span>063</span></p>
			</li>
			</ul>

			<div class="padding-116">
			<h2 id="b013">单元小结<span class="fontsz1">＞＞＞＞＞＞＞＞</span></h2>
			<p class="bj2"><b>学习导图</b></p>
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0074-1.jpg" /></p>
			<p class="center"><img class="img-a" alt="" src="../../assets/images/0074-1.jpg" /></p>
			<p class="bj2"><b>学习指导</b></p>
			<p>1.不等式的基本性质.</p>
			<p>（1）比较数（式）的大小常用“作差比较法”.</p>
			@@ -3638,139 +3586,85 @@
			<p>第二单元不等式</p>
			</li>
			<li>
			<p><span>065</span></p>
			<p><span>065-066</span></p>
			</li>
			</ul>

			<div class="padding-116">
			<h2 id="b014">单元检测<span class="fontsz1">＞＞＞＞＞＞＞＞</span></h2>
			<div class="bj">
			<p>
			<span class="bj-sp"><b>水平一</b></span>
			</p>
			<p>1.选择题.</p>
			<p>（1）不等式<i>x</i><sup>2</sup>-3<i>x</i>-10＞0的解集是（　）.</p>
			<p>A.<b>R</b></p>
			<p>B.∅</p>
			<p>C.（-∞，5）∪（5，+∞）</p>
			<p>D.（-∞，-2）∪（5，+∞）</p>
			<p>
			（2）
			设集合<i>A</i>={<i>x</i>\|3<i>x</i>-2-<i>x</i><sup>2</sup>＜0}，<i>B</i>={<i>x</i>\|<i>x</i>-<i>a</i>＜0}，若<i>B</i>⊆<i>A</i>，则<i>a</i>的取值范围是（　）.
			</p>
			<p>A.（-∞，1］</p>
			<p>B.［1，2］</p>
			<p>C.（2，+∞）</p>
			<p>D.（-∞，2］</p>
			<p>2.填空题.</p>
			<p>
			（1）
			若集合<i>A</i>={<i>x</i>\|<i>x</i><sup>2</sup>-4<i>x</i>+3＜0}，<i>B</i>={<i>x</i>\|（<i>x</i>-2）（<i>x</i>-5）＜0}，则<i>A</i>∩<i>B</i>=
			_________；
			</p>
			<p>
			（2）若\|<i>x</i>\|＞<i>a</i><sup>2</sup>+1，则<i>x</i>的取值范围是______.
			</p>
			<p>3.解下列一元二次不等式.</p>
			<p>
			（1） 3<i>x</i><sup>2</sup>-2<i>x</i>-3≥0；（2） -<i>x</i><sup>2</sup>-2<i>x</i>+3≥0.
			</p>
			<p>
			4.求同时满足不等式<i>x</i><sup>2</sup>-2<i>x</i>＜8和<i>x</i><sup>2</sup>-2<i>x</i>≥3的整数解的集合.
			</p>
			<p>
			5.已知集合<i>A</i>={<i>x</i>\|\|<i>x</i>-1\|＜7}，<i>B</i>={<i>x</i>\|\|<i>x</i>-3\|＞4}，求<i>A</i>∩<i>B</i>.
			</p>
			<p>
			6.设不等式<math display="0">
			<mrow data-mjx-texclass="INNER">
			<mo data-mjx-texclass="OPEN">\|</mo>
			<mfrac>
			<mn>1</mn>
			<mn>2</mn>
			</mfrac>
			<mi>x</mi>
			<mo>+</mo>
			<mn>1</mn>
			<mo data-mjx-texclass="CLOSE">\|</mo>
			</mrow>
			<mo>＜</mo>
			<mn>3</mn>
			</math>的解集为<i>A</i>，不等式（<i>x</i>+1）<sup>2</sup>-（<i>x</i>-1）<sup>2</sup>＞1的解集为<i>B</i>，求<i>A</i>∩<i>B</i>.
			</p>
			<p>
			7.某中等职业学校学生小王暑假在一家商店进行社会实践，经理请小王帮助解决一些销售问题.有一种商品的进价是40元/kg
			，现在的售价是60元/kg ，每周可卖出300 kg
			.根据市场调查，该商品每涨价1元，每周要少卖出10 kg
			；每降价1元，每周可多卖出20 kg
			.如果要对该商品涨价，那么涨价的范围是多少，才能使每周的利润不少于6
			240元？如果要对该商品降价，那么降价的范围是多少，才能使每周的利润不少于6
			240元？
			</p>
			<p>
			<span class="bj-sp"><b>水平二</b></span>
			</p>
			<p>
			1.已知两个圆的半径分别为2和3，圆心距<i>d</i>满足<i>d</i><sup>2</sup>-6<i>d</i>+5＜0，判断这两个圆的位置关系.
			</p>
			<examinations :cardList="questionData[72]" sourceType="json" v-if="questionData">
			</examinations>
			</div>
			</div>
			</div>
			</div>
			<!-- 066 -->
			<div class="page-box" page="73">
			<div v-if="showPageList.indexOf(73) > -1">
			<ul class="page-header-odd fl al-end">
			<li>066</li>
			<li>数学.基础模块</li>
			<li>上册</li>
			</ul>
			<div class="padding-116">
			<p class="center"><img class="img-c" alt="" src="../../assets/images/0077-1.jpg" /></p>
			<p class="img">第2题图</p>
			<div class="bj">
			<p>
			2.如图所示，要在边长为20
			m的正方形场地中心位置建一个正方形花圃，要使花圃的面积既不小于16
			m<sup>2</sup>，也不大于36
			m<sup>2</sup>，则花圃与正方形场地的对应边应相距多远？
			</p>
			<p>
			3.设全集为<b>R</b>，集合<i>A</i>={<i>x</i>\|\|<i>x</i>\|＜4}，<i>B</i>={<i>x</i>\|\|<i>x</i>-2\|≥1}，求（∁<i><sub><b>R</b></sub>A</i>）∩（∁<i><sub><b>R</b></sub>B</i>）.
			</p>
			<p>
			4.不等式\|<i>x</i>-1\|≤2与<i>ax</i><sup>2</sup>+<i>bx</i>-2≤0有相同的解集，求<i>a</i>，<i>b</i>的值.
			</p>
			<p>
			5.现新建一个圆形喷水池，要在池中心<i>O</i>竖直安装一根水管，在水管的顶端<i>A</i>安一个喷水头，使喷出的抛物线水柱在与池中心<i>O</i>的水平距离为1
			m处达到最高点<i>B</i>，高度为3
			m，且水柱落地处<i>C</i>与池中心<i>O</i>的水平距离为3 m，如图所示.
			</p>
			<p>
			（1）
			求水柱的高度<i>y</i>（m）与池中心<i>O</i>到水柱的水平距离<i>x</i>（m）的关系式，并画出其图像；
			</p>
			<p>（2）求水管的高度<i>h</i>（m）；</p>
			<p>
			（3）当水柱的高度不低于<math display="0">
			<mfrac>
			<mn>3</mn>
			<mn>4</mn>
			</mfrac>
			</math>m时，求这时池中心<i>O</i>到水柱的水平距离<i>x</i>的取值区间.
			</p>
			<p class="center">
			<img class="img-c" alt="" src="../../assets/images/0077-3.jpg" />
			</p>
			<p class="img">第5题图</p>
			</div>
			</div>
			</div>
			<div class="page-box hidePage" page="73">
			</div>
			<!-- 解题思路弹窗 -->
			<el-dialog :visible.sync="thinkingDialog" width="40%" :append-to-body="true" :show-close="false"
			@close="closeDialog" class="thinkDialog">
			<div slot="title" class="think-header"
			style="padding: 0; text-align: center; color: #333;display:flex;justify-content: center;">
			<span style=""> 分析 </span>
			<svg style="position: absolute; right:10px;cursor: pointer;" @click="thinkingDialog = false" t="1718596022986"
			class="icon" viewBox="0 0 1024 1024" version="1.1" xmlns="http://www.w3.org/2000/svg" p-id="4252" width="20"
			height="20" xmlns:xlink="http://www.w3.org/1999/xlink">
			<path
			d="M176.661601 817.172881C168.472798 825.644055 168.701706 839.149636 177.172881 847.338438 185.644056 855.527241 199.149636 855.298332 207.338438 846.827157L826.005105 206.827157C834.193907 198.355983 833.964998 184.850403 825.493824 176.661601 817.02265 168.472798 803.517069 168.701706 795.328267 177.172881L176.661601 817.172881Z"
			fill="#979797" p-id="4253"></path>
			<path
			d="M795.328267 846.827157C803.517069 855.298332 817.02265 855.527241 825.493824 847.338438 833.964998 839.149636 834.193907 825.644055 826.005105 817.172881L207.338438 177.172881C199.149636 168.701706 185.644056 168.472798 177.172881 176.661601 168.701706 184.850403 168.472798 198.355983 176.661601 206.827157L795.328267 846.827157Z"
			fill="#979797" p-id="4254"></path>
			</svg>
			</div>
			<ul>
			<li v-for="(item, index) in thinkData" :key="index">
			<div v-if="index <= showIndex" style="display: flex">
			<span style="position: relative">
			<span style="position: absolute; top: 16px; left: 13px; color: #fff">{{ index + 1 }}</span>
			<img src="../../assets/images/icon/blue-group.png" alt="" style="margin-right: 10px"
			v-if="index < thinkOne.length - 1" />
			<img src="../../assets/images/icon/blue.png" alt="" v-if="index == thinkOne.length - 1"
			style="margin-right: 10px" />
			</span>
			<p class="txt-p" v-html="item"></p>
			</div>
			</li>
			</ul>
			<div @click="changeNext" style="
			display: flex;
			flex-direction: column;
			align-items: center;
			justify-content: center;
			">
			<img src="../../assets/images/icon/mouse.png" alt="" v-if="showIndex < thinkData.length - 1" />
			<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" t="1710234570135"
			class="icon" viewBox="0 0 1024 1024" version="1.1" p-id="5067" width="15" height="15">
			<path
			d="M2.257993 493.371555 415.470783 906.584344 512 1003.113561 608.529217 906.584344 1021.742007 493.371555 925.212789 396.842337 512 810.055127 98.787211 396.842337Z"
			fill="#1296db" p-id="5068" />
			<path
			d="M2.257993 117.980154 415.470783 531.192944 512 627.722161 608.529217 531.192944 1021.742007 117.980154 925.212789 21.450937 512 434.663727 98.787211 21.450937Z"
			fill="#1296db" p-id="5069" />
			</svg>
			</div>
			</el-dialog>
			</div>
			</template>

			<script>
			const handleShow = (num) => {
			const obj = {}
			for (let index = 0; index < num; index++) {
			obj['isShowAnswer' + index] = false
			}
			return obj
			}
			const showObj = handleShow(30)
			import graffiti from '@/components/graffiti/index.vue'
			import paint from '@/components/paint/index.vue'
			import examinations from '@/components/examinations/index.vue'
			export default {
			name: "",
			props: {
			@@ -3778,16 +3672,51 @@
			type: Array,
			default: [],
			},
			questionData: {
			type: Object,
			},
			},
			components: {},
			components: { examinations, paint,graffiti },
			data() {
			return {};
			return {
			collectImg: require('../../assets/images/icon/heart.png'),
			collectCheck: require('../../assets/images/icon/heart-check.png'),
			thinkingDialog: false,
			showIndex: 0,
			thinkData: [],
			thinkOne: [
			'①根据<i>x</i><sup>2</sup>的系数判断函数图像（抛物线）的开口方向；',
			'②用判别式判定出一元二次方程<i>x</i><sup>2</sup>-2<i>x</i>-3=0的解的情况，从而确定二次函数<i>y</i>=<i>x</i><sup>2</sup>-2<i>x</i>-3的图像与<i>x</i>轴的交点个数和交点坐标；',
			'③计算二次函数图像的顶点坐标、与<i>y</i>轴的交点坐标；',
			'④求出二次函数图像的对称轴方程，并利用函数图像的对称性再找出一些点；⑤最后根据上述信息画出函数图像.',
			'画出图像后，<i>y</i>=0，<i>y</i>＞0，<i>y</i>＜0分别对应函数图像与<i>x</i>轴相交、函数图像在<i>x</i>轴上方、函数图像在<i>x</i>轴下方三种情形，根据图像完成（2）（3）两个问题.'
			],
			thinkTwo:[
			'由（<i>x</i>+1）<sup>2</sup>≥4得<i>x</i><sup>2</sup>+2<i>x</i>+1≥4，即<i>x</i><sup>2</sup>+2<i>x</i>-3≥0，从而可以利用二次函数<i>y</i>=<i>x</i><sup>2</sup>+2<i>x</i>-3的图像进行求解；注意到4=2<sup>2</sup>，也可以考虑将（<i>x</i>+1）<sup>2</sup>≥4整理为（<i>x</i>+1）<sup>2</sup>-4≥0，并使用平方差公式，即（<i>x</i>+1）<sup>2</sup>-2<sup>2</sup>≥0，得到（<i>x</i>+3）（<i>x</i>-1）≥0，此时可以借助上面的结论直接求解.下面我们将使用后一种方法进行求解.'
			],
			thinkThree:[
			'利润=（销售单价-成本单价）×销售量.降价过程中，单价降低能够使销售量变大，但也使销售单价与成本单价的差减小，所以降价的范围应保证利润不低于促销前.'
			],
			isShowAnswer: false,
			isShowAnswerOne: false,
			...showObj
			};
			},
			computed: {},
			watch: {},
			created() { },
			mounted() { },
			methods: {},
			mounted() {
			console.log(2, this);
			},
			methods: {
			openDialog(queryData) {
			this.thinkData = queryData
			this.thinkingDialog = !this.thinkingDialog
			},
			closeDialog() {
			this.showIndex = 0
			},
			changeNext() {
			if (this.showIndex < this.thinkData.length - 1) this.showIndex = this.showIndex + 1
			}
			},
			};
			</script>

			@@ -3802,4 +3731,21 @@
			top: 0;
			width: 140px;
			}

			.question-textarea {
			margin-left: 20px;
			width: 94%;
			border-color: #DCDFE6;
			}

			.table-answer-box {
			math {
			width: max-content;
			height: 36px;
			}
			}

			li {
			list-style: none;
			}
			</style>